Download Class 6 Decimals

ID : in-6-Decimals [1]
Class 6
Decimals
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Answer t he quest ions
(1)
At a construction site, there are 19.5 loads of bricks, and the total weight of all the loads
together is 466.44 kgs. What is the weight of one load?
(2)
T he corner store sells 129.91 liters of milk on T hursday and 11.32 liters more than this amount
on Friday. T he f ollowing day, 18.94 liters less milk than on Friday were sold. How many liters of
milk did they sell on the Saturday?
(3)
What are you lef t with when you take away One T enths six times f rom 1?
(4) What number do you get by adding 8 T enths and 72 T en thousandths together to 33 T ens?
(5)
What is the smallest number should be subtracted f rom 15.51 to give a prime number?
(6) What is the sum of the numbers two T en thousandths and six Hundredths?
Choose correct answer(s) f rom given choice
(7) What do you get when you subtract 692.92 f rom 719.23?
a. 24.91
b. 28.41
c. 26.31
d. 2.631
Fill in t he blanks
(8)
Solve the f ollowing:
A)
C)
(9)
B)
÷ 10 = 68.805
D)
154.58 + 33.87 =
(29 Ones + 1 Hundredths +
7.4 x
1.96 x
= 56.24
= 52.92
Hundredths) x 1 T enths = 2.907
(10) Each bag of oranges weighs 1.46 kgs. If the total weight of a sack containing oranges bags is
61.32 kgs, then
(11)
(12)
bags are in the sack.
93 T ens + 4 T housandths =
260.79 + 65.19 + 0.92 =
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ID : in-6-Decimals [2]
(13) A snail crawls 34 cm in 22 minutes. It crawls another 98 cm in 65 minutes. T he total distance it
crawls is
metres.
(14) Bala's f ather gave him Rs.188 to spend. He spent Rs.69.24 to buy some toys and Rs.13.18 to
buy some books. He now has Rs.
(15)
T he number nine T enths can be written as
lef t.
in decimals
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ID : in-6-Decimals [3]
Answers
(1)
23.92 kg
Step 1
T he number of loads of bricks = 19.5
Step 2
T otal weight of all the loads together = 466.44 kgs
Step 3
In order to f ind the weight of one load, we need to divide the total weight by the number of
loads.
Step 4
T heref ore, the weight of one load is 466.44 ÷ 19.5 = 23.92 kg.
(2)
122.29 liters
Step 1
Amount of milk sold on T hursday = 129.91 liters
Step 2
Amount of milk sold on next day (i.e. Friday) = 129.91 + 11.32 = 141.23 liters
Step 3
Amount of milk sold on next day (i.e. Saturday) = 141.23 - 18.94 = 122.29 liters
(3)
0.4
Step 1
Look at the question caref ully and notice that One T enths of 1 =
1
,
10
and six times of
1
=
10
6
10
= 0.6
Step 2
Now take One T enths six times f rom 1 or subtracting 0.6 f rom 1 = 1 - 0.6
= 0.4
Step 3
T heref ore the lef t value with you, when you take away One T enths six times f rom 1 is 0.4.
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ID : in-6-Decimals [4]
(4) 330.8072
Step 1
Let us f irst convert the number names into numerals:
8 T enths = 8 ÷ 10 = 0.8
72 T en thousandths = 72 ÷ 10000 = 0.0072
33 T ens = 33 × 10 = 330
Step 2
Let’s f irst add the decimal numbers as below:
| T housands|
Lakhs|
| T L| L|
Ones| T enths| Hundredths| T housandths| T en thousandths|
T T H| T H| H| T | O| . (1/10)|
T otal
(1/100)|
(1/1000)|
(1/10000)|
0 .
8
0
0
0
0 .
0
0
7
2
0 .
8
0
7
2
Legend:
T L - T en Lakhs, L - Lakhs, T T H - T en T housands, T H - T housands, H - Hundreds, T T ens, O - Ones.
Step 3
Let us now add the decimal numbers with the whole number:
| T housands|
Ones| T enths| Hundredths| T housandths| T en thousandths|
Lakhs|
| T L| L|
T T H| T H| H| T | O| . (1/10)|
T otal
(1/100)|
(1/1000)|
(1/10000)|
0 .
8
0
7
2
3 3 0 .
0
0
0
0
3 3 0 .
8
0
7
2
Step 4
T heref ore, by adding 8 T enths and 72 T en thousandths together to 33 T ens, we get
330.8072.
(5)
2.51
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ID : in-6-Decimals [5]
(6) 0.0602
Step 1
2
T wo T en thousandths =
10000
and six Hundredths =
6
100
Step 2
T heref ore the sum of the numbers two T en thousandths and six Hundredths =
2
+
10000
6
100
=
2 × 1 + 6 × 100
10000
=
2 + 600
10000
=
602
10000
= 0.0602
(7) c. 26.31
Step 1
Decimals with the same number of decimal places are called Like Decimals. T he numbers
given here are theref ore Like Decimals.
Step 2
We need to subtract 692.92 f rom 719.23. T heref ore, 719.23 must be placed on top and
692.92 below. T he digits of the two numbers must be placed according to their place values.
Step 3
Let us now do the subtraction of the two numbers digit by digit, starting f rom the
hundredths and borrowing if needed:
T housands Hundreds T ens Ones . T enth Hundredth
-
7
1
9
.
2
3
6
9
2
.
9
2
0
2
6
.
3
1
Step 4
Hence, when we subtract 692.92 f rom 719.23, we get 26.31.
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ID : in-6-Decimals [6]
(8)
A)
B)
C)
D)
(9)
(10)
688.05
7.6
188.45
27
6
42
Step 1
T he weight of each bag of oranges = 1.46 kgs
Step 2
T otal weight of oranges bags in a sack = 61.32 kgs
Step 3
Number of oranges bags in the sack = 61.32 ÷ 1.46 = 42 bags
Step 4
Hence, there are 42 bags in the sack.
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ID : in-6-Decimals [7]
(11)
930.004
Step 1
First, let us convert the number names into numerals as below:
93 T ens = 93 × 10 = 930
4 T housandths = 4 ÷ 1000 = 0.004
Step 2
Let’s now add the two numbers:
| T housands|
Ones| T enths| Hundredths| T housandths| T en thousandths|
Lakhs|
| T L| L|
T T H| T H| H| T | O| . (1/10)|
T otal
(1/100)|
(1/1000)|
(1/10000)|
9 3 0 .
0
0
0
0
0 .
0
0
4
0
9 3 0 .
0
0
4
0
Legend:
T L - T en Lakhs, L - Lakhs, T T H - T en T housands, T H - T housands, H - Hundreds, T T ens, O - Ones.
Step 3
T hus, 93 T ens + 4 T housandths = 930.004
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ID : in-6-Decimals [8]
(12)
326.9
Step 1
Decimals with the same number of decimal places are called Like Decimals. T he numbers
given here are theref ore Like Decimals.
Step 2
In order to add the given Like Decimals, let us arrange the digits according to their place
value, that is one below the other to make sure that the decimals are also placed exactly
one below the other. T his way, we will place the ones below the ones, the tenths below the
tenths and so on.
Step 3
T he decimal point in the answer will be placed as being placed in the addends.
Step 4
Let us add the numbers digit by digit starting f rom the hundredths and carry over if needed:
T housands Hundreds T ens Ones . T enth Hundredth
2
6
0
.
7
9
6
5
.
1
9
0
.
9
2
6
.
9
0
+
3
2
Step 5
Hence, when we add the decimals 260.79, 65.19, and 0.92 we get 326.9
(13)
1.32
Step 1
T he total distance (in cm) the snail crawls: 34 cm + 98 cm = 132 cm
Step 2
Let us now convert the distance 132 cm (centimetres) into distance in meters as below. We
know that:
100 cm = 1 m
T heref ore, 132 cm =
132
m = 1.32 m
100
Step 3
Hence, the snail crawls 1.32 m in the total time.
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ID : in-6-Decimals [9]
(14)
105.58
Step 1
T he amount of money that Bala's f ather gave him = Rs.188
Step 2
T he amount that Bala spent in buying toys = Rs.69.24
Step 3
T he amount that Bala spent in buying books = Rs.13.18
Step 4
Let us add the amount he spent in buying toys and books to f ind his total expense:
T oys
= Rs.69.24
Books
= Rs.13.18
T otal expense = Rs.82.42
Step 5
In order to f ind the amount lef t with him, we need to subtract the amount Bala's f ather gave
and the amount Bala spent.
Step 6
Bef ore subtracting the two numbers, let us make sure they are written as Like Decimals.
Decimals with the same number of decimal places are called Like Decimals. T hus, let us
write Rs.188 as Rs.188.00, and subtract Rs.82.42 f rom it
Step 7
Let us subtract the amount Bala spent (Rs.82.42) f rom the amount his f ather gave (Rs.188)
digit by digit. T he numbers must be placed according to their place values. T he greater
number must be placed on top and the lesser one below:
T housands Hundreds T ens Ones . T enth Hundredth
1
1
8
8
.
0
0
8
2
.
4
2
0
5
.
5
8
Step 8
Hence, Bala is lef t with Rs.105.58.
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ID : in-6-Decimals [10]
(15)
0.9
Step 1
Let’s f irst convert the number name into number/f raction. So, nine T enths can be written as:
9
10
Step 2
By converting the f raction into decimals, we get:
9
= 0.9
10
Step 3
T heref ore, the number nine T enths in decimal f orm is 0.9.
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