Download Grade 5 Decimal Numbers

ID : pk-5-Decimal-Numbers [1]
Grade 5
Decimal Numbers
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Answer t he quest ions
(1)
A snail can move a distance of 0.322 meters in 2.3 hours. What distance can it travel in ten
hours?
(2)
At a construction site, there are 13.5 loads of bricks, and the total weight of all the loads
together is 448.2 kgs. What is the weight of one load?
(3)
What number do you get by adding 7 T enths and 91 T enths together to 61 T housands?
(4) Which number is 0.5 larger than the smallest 2-digit number?
Choose correct answer(s) f rom given choice
(5)
A caterpillar can move a distance of 31.28 meters in 3.4 hours. What distance can it travel in 4
days?
a. 879.3 m
b. 8832 m
c. 883.2 m
d. 885.8 m
(6) T he value of 0.0666 ÷ 0.03 is
a. 2.022
b. 2.22
c. 22.2
d. none of these
(7) Waf a bought the f ollowing things when she got her f irst salary:
A gaming system f or Rs. 1120.35
Some clothes f or Rs. 5895.75
A television f or Rs. 24107.80
If her salary was Rs. 60000, what does she have lef t af ter all the shopping?
(8)
a. Rs.2887.61
b. Rs.28875.00
c. Rs.28877.80
d. Rs.28876.10
Each bag of oranges weighs 3.73 kgs. If the total weight of a sack containing oranges bags is
156.66 kgs, then how many bags are in the sack?
a. 42
b. 40
c. 43
d. 45
(9) A thread of length 18 metres was cut into pieces that were 1.5 metres long. How many pieces
was it cut into?
a. 14
b. 16
c. 12
d. 10
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ID : pk-5-Decimal-Numbers [2]
(10) Which of the f ollowing represents the number nine Hundredths in decimal f orm
a. 0.90000
b. 0.000900
c. 0.18000
d. 0.09000
Fill in t he blanks
(11)
(12)
T ake away One T enths eight times f rom 1 and you are lef t with
.
T he smallest number should be added to 19.89 to give an even number is
(13) If the f ollowing f igure represents 0.09
then the result of
―
is
(14) Shahid drove 84.9882 kms to visit his grandmother. When he reached his grandmother's house
he noticed the car had used up 4.74 litres of petrol. He traveled
kilometers per litre
of petrol?
(15)
6.57 x 5.0 =
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ID : pk-5-Decimal-Numbers [3]
Answers
(1)
1.4
Step 1
T he distance the snail can move in 2.3 hours = 0.322 metres
Step 2
T he distance it can move in 1 hour = 0.322 ÷ 2.3 = 0.14 metres
Step 3
T he distance it can move in 10 hours = 0.14 × 10 = 1.4 metres
Step 4
T heref ore, the snail can move 1.4 metres in ten hours.
(2)
33.2 kg
Step 1
T he number of loads of bricks = 13.5
Step 2
T otal weight of all the loads together = 448.2 kgs
Step 3
In order to f ind the weight of one load, we need to divide the total weight by the number of
loads.
Step 4
T heref ore, the weight of one load is 448.2 ÷ 13.5 = 33.2 kg.
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ID : pk-5-Decimal-Numbers [4]
(3)
61009.8
Step 1
Let us f irst convert the number names into numerals:
7 T enths = 7 ÷ 10 = 0.7
91 T enths = 91 ÷ 10 = 9.1
61 T housands = 61 × 1000 = 61009
Step 2
Let’s f irst add the decimal numbers as below:
| T housands|
Lakhs|
| T L| L|
Ones| T enths| Hundredths| T housandths| T en thousandths|
T T H| T H| H| T | O| . (1/10)|
T otal
(1/100)|
(1/1000)|
(1/10000)|
0 .
7
0
0
0
9 .
1
0
0
0
9 .
8
0
0
0
Legend:
T L - T en Lakhs, L - Lakhs, T T H - T en T housands, T H - T housands, H - Hundreds, T T ens, O - Ones.
Step 3
Let us now add the decimal numbers with the whole number:
| T housands|
Ones| T enths| Hundredths| T housandths| T en thousandths|
Lakhs|
| T L| L|
T otal
T T H| T H| H| T | O| . (1/10)|
(1/100)|
(1/1000)|
(1/10000)|
9 .
8
0
0
0
6
1
0 0 0 .
0
0
0
0
6
1
0 0 9 .
8
0
0
0
Step 4
T heref ore, by adding 7 T enths and 91 T enths together to 61 T housands, we get 61009.8.
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ID : pk-5-Decimal-Numbers [5]
(4) 10.5
Step 1
T he smallest 2-digit number is 10 (a whole number).
Step 2
T he number 0.5 larger than 10 can be f ound by adding the numbers 0.5 and 10.
Step 3
Let us f irst convert the whole number 10 into decimal f orm. In decimal f orm, 10 can be
written as 10.00. Decimals with the same number of decimal places are called like decimals.
Step 4
Now, our task is to add the Like Decimals 0.5 and 10.00. Let us add them starting f rom the
hundredths and carry over if needed. T he decimal point in the answer will be placed as being
placed in the addends:
Hundred
T en
T housands
T housands
T housands Hundreds T ens Ones . T enth Hundredth
1
+
1
0
.
0
0
0
.
5
0
0
.
5
0
Step 5
Hence, the number 0.5 larger than the smallest 2-digit number is 10.5.
(5)
c. 883.2 m
(6) b. 2.22
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ID : pk-5-Decimal-Numbers [6]
(7) d. Rs.28876.10
Step 1
Amount received by Waf a as salary = Rs.60000
Step 2
Let us add the amounts spent by Waf a f or purchasing various things:
T en
T housands Hundreds T ens Ones . T enth Hundredth
T housands
A gaming
system
1
1
2
0
.
3
5
Some clothes
5
8
9
5
.
7
5
A television
2
4
1
0
7
.
8
0
T otal
3
1
1
2
3
.
9
0
Expense
Hence, Waf a's total expense is Rs.31123.90.
Step 3
In order to f ind the amount lef t with Waf a, let us subtract her f irst salary with her total
expense:
Amount lef t with Waf a = Waf a's salary - Waf a's total expense
= 60000 - 31123.90
= 60000.00 - 31123.90 ...(Writing 60000 in decimal f orm 60000.00 so that the two numbers
are Like Decimals)
Step 4
Now, let us subtract 31123.90 f rom 60000.00 by placing the digits of two decimal numbers
according to their place values:
T en T housands T housands Hundreds T ens Ones . T enth Hundredth
-
6
0
0
0
0
.
0
0
3
1
1
2
3
.
9
0
2
8
8
7
6
.
1
0
Step 5
Hence, af ter shopping Waf a is lef t with Rs.28876.10.
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ID : pk-5-Decimal-Numbers [7]
(8)
a. 42
Step 1
T he weight of each bag of oranges = 3.73 kgs
Step 2
T otal weight of oranges bags in a sack = 156.66 kgs
Step 3
Number of oranges bags in the sack = 156.66 ÷ 3.73 = 42 bags
Step 4
Hence, there are 42 bags in the sack.
(9) c. 12
Step 1
T otal length of the thread = 18 metres
Length of one piece of thread = 1.5 metres
Step 2
Number of pieces the thread was cut into =
T otal length of the thread
Length of one piece of thread
=
18
1.5
= 12
Step 3
T heref ore, it was cut into 12 pieces.
(10) d. 0.09000
Step 1
Let’s f irst convert the number name into number/f raction. So, nine Hundredths can be
written as:
9
100
Step 2
By converting the f raction into decimals, we get:
9
= 0.09
100
Step 3
T heref ore, the number nine Hundredths in decimal f orm is 0.09.
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ID : pk-5-Decimal-Numbers [8]
(11)
0.2
Step 1
Look at the question caref ully and notice that One T enths of 1 =
1
,
10
and eight times of
1
10
=
8
10
= 0.8
Step 2
Now take One T enths eight times f rom 1 or subtracting 0.8 f rom 1 = 1 - 0.8
= 0.2
Step 3
T heref ore the lef t value with you, when you take away One T enths eight times f rom 1 is
0.2.
(12)
0.11
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ID : pk-5-Decimal-Numbers [9]
(13)
0.49
Step 1
If we look at the f igure, we notice that, there are total 100 boxes. 9 of 100 represents 0.09.
T heref ore, 1 of 100 represents =
1
= 0.01
100
Step 2
―
T he dif f erence of the boxes in the given f igures = 66 - 17 = 49
and hence 49 of 100 represents =
49
= 0.49
100
Step 3
T hus, the result of
―
is 0.49.
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ID : pk-5-Decimal-Numbers [10]
(14)
17.93
Step 1
Distance that Shahid drove to reach his grandmother's house = 84.9882 kms
Step 2
Number of litres used while driving = 4.74 litres
Step 3
In order to know the number of kilometres per litre of petrol, we will need to divide the
number of kilometers traveled Shahid by the number of litres of petrol used.
Step 4
T hus, the number of kilometers Shahid travelled per litre of petrol = 84.9882 ÷ 4.74 = 17.93
km/litre
Step 5
T heref ore, the kilometres per litre of petrol (mileage of the car) is 17.93 km/liter.
(15)
32.850
Step 1
In order to multiply the two decimal numbers, let us f irst f ind out the position of the decimal
point in the f inal product.
Step 2
Let us f irst count the number of decimal places in both the multiplicands. T he total number
of decimal places in the product will be the sum of the number of decimal places in both the
multiplicands.
Step 3
In the number 5.0, there is 1 decimal place and in 6.57 there are 2 decimal places.
Hence, there will be a total of 3 decimal places in the f inal product.
Step 4
Now, let us multiply the two numbers just like whole numbers, and in the f inal product place
the decimal point such that there are 3 decimal places (i.e. af ter 3 places f rom the right):
6 5 7
x 5 0
0 0 0
3 2 8 5 0
3 2 8 5 0
Step 5
Now put the decimal point af ter three places f rom right. T heref ore,
6.57 × 5.0 = 32.850
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