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Download Exercise 2 – Voltages and currents measurements
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Exercise 2 – Voltages and currents measurements 1. Aim of the exercise The aim of the exercise is to familiarize students with the methods of measuring voltages and currents in the actual electric circuits. Another aim is to getting the ability of measurement uncertainty evaluation and measurement equipment familiarization. Main topics Direct voltage and current measurements Indirect current measurements Measurements of EMF of actual voltage sources, acquisition errors estimation, internal source resistance estimation Compensation method for EMF measurement 2. Gained skills the ability to measure voltages and currents the ability to determine the current value with the indirect method, the ability to measure the EMF of the actual source and determine its internal resistance the ability to measure the EMF with the compensation method, 3. Instrumentation Figure 1. Measurement box U01 4. Measurements and tasks Task 1 – Direct and indirect voltage and current measurements With the use of the module U01 (Fig. 1) connect the measurement circuit from Figure 2. The power supply should be connected to “WE” connectors. The output voltage, current limit and the resistance to adjust on the decade resistor will be provided by the supervisor. For the voltage measurement use the 34450A multimeter and for the current measurement U1252B handheld one. I + + A – + V E – U Rx – Figure 2 Schematic diagram for simple voltage and current measurement After measuring the current with the meter, calculate its value by applying the Ohm’s law (Hence, you measure it now also indirectly). Compare the values and the errors of both measurements. Task 2. Voltage measurement on a real voltage source. Estimating internal resistance of the source. Use LM-3 voltmeter (class 0.5) and 34450A multimeter (10 MΩ internal resistance) to measure the voltage on Źr. 1, Źr. 2 and Źr 3 sources. What is the reason of the discrepancy in the meters’ readings for “Źr. 1”, “Źr. 2” and “Źr. 3”? Can you quickly estimate the internal resistance of “Źr. 2”? Have you got idea how you can calculate it quite precisely? NOTE: Taking measurements with LM-3 meter, select the lowest possible range for “Źr. 1”, and DO NOT change it during subsequent measurements. Task 3. Compensation method Connect the circuit according to Figure 3. Use the compensation method to measure the voltage at “Źr. 3”. Estimate the relative error of the method. ! What can you say about the method’s advantage? Rx „0” V Ex Uref Eref Figure 3. Schematic diagram for voltage measurement with usage of compensation method. 𝛿𝑔 𝑈 = 𝛿𝑔 𝑈𝑟𝑒𝑓 + ∆𝑈 ∙ 100% 𝑈𝑟𝑒𝑓 where: ΔU – is the lowest voltage possible to read on the zero indicator. 5. Control questions 1. What is the acquisition error? 2. Define the class index of the meter. 3. Is the relative error of a voltmeter of 0.5 class index always equal to 0.5 %? Justify the answer. 4. What is the connection configuration of the ammeter and what of the voltmeter to the electric circuit? 5. Draw the scheme for the voltage measurement with the compensation method. What are the requirements for the voltmeters to obtain the error as small as possible? 6. What is the internal resistance influence on the measurement results for: - An ideal voltage source - A real voltage source 7. What will be the voltmeter’s indication if it has the internal resistance of 10 kΩ when measuring voltage on the real source with EMF of 10V and internal resistance of 10 kΩ? 8. What value should be internal resistances of ideal voltmeter and of ideal ammeter? 9. The voltage was measured on the real voltage source of the EMF = 5V. The result was 2.5 V. What is the internal source resistance if the voltmeter internal resistance is 100 kΩ. 10. The current was measured with the use of the ammeter. The result was I = 10 mA at the range of 50 mA. Calculate the relative error if the formula for the ammeter limiting error is given by formula: 𝛿𝑔 𝐼 = 0.05% + 0.02% ∙ 𝐼𝐹𝑆 𝐼 11. The current was measured indirectly by the measurement of the voltage drop on the R = 10 kΩ resistor. The result of the voltage measurement was U = 10V. Calculate the current value and the relative error of its measurement if the error of the voltage measurement is given by formula: 𝑈𝐹𝑆 𝛿𝑔 𝑈 = 0.05% + 0.01% ∙ 𝑈 12. The EFM was measured with the use of the compensation method. The result was U = 10 V at the range of 30 V. Calculate the relative error if the voltage measurement was performed with the meter for which the relative error is given by a formula: 𝛿𝑔 𝑈 = 0.05% + 0.01% ∙ 𝑈𝐹𝑆 𝑈 The zero indicator has the resolution of 0.01 mV. 13. The EFM was measured with the use of the compensation method. The result was U =5 V at the range of 10 V. What should be the resolution of the balance indicator for the insensitivity error to be 10 times smaller than the relative error of the voltage measurement by the meter given by the formula: 𝛿𝑔 𝑈 = 0.05% + 0.01% ∙ 𝑈𝐹𝑆 𝑈