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Transcript
Standardized Test Practice - Cumulative, Chapters 1-11
or
1. What is the value of x in the figure below?
Since length cannot be negative, x = 7. The correct
choice is B.
ANSWER: B
A5
B7
C8
D 10
SOLUTION: The altitude drawn to the hypotenuse of a right
triangle separates the hypotenuse into two segments.
The length of this altitude is the geometric mean
between the lengths of these two segments. 2. Which of the following is not a property of
parallelograms?
F The opposite angles of a parallelogram are
congruent.
G The opposite sides of a parallelogram are
congruent.
H The consecutive angles of a parallelogram are
supplementary.
J The consecutive angles of a parallelogram are
complementary.
SOLUTION: The consecutive angles of a parallelogram are
supplementary, not complementary. So, the statement
in option J is incorrect. Therefore, the correct choice
is J.
ANSWER: J
3. What is the area of the triangle below? Round your
answer to the nearest tenth if necessary.
To factor this polynomial we are looking for factors
of
whose sum is –14.
Factors
Sum of factors
24, –49
–25
28, –42
–14
2
A 152.8 in
B 159.2 in2
2
C 164.5 in
D 171.9 in2
SOLUTION: We need to determine the length of the base of the
triangle.
Use the tangent ratio to find the left part of the base
b 1 and use the Pythagorean Theorem to find the right
part of the base b 2. or
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Since length cannot be negative, x = 7. The correct
choice is B.
Page 1
Use the tangent ratio to find the left part of the base
b 1 and use the Pythagorean Theorem to find the right
Standardized Test Practice - Cumulative, Chapters 1-11
part of the base b 2. The area of the triangle is about 171.9 square inches.
Therefore, the correct choice is D.
ANSWER: D
6. GRIDDED RESPONSE Suppose two similar
rectangles have a scale factor of 3:5. The perimeter
of the smaller rectangle is 21 millimeters. What is the
perimeter of the larger rectangle? Express your
answer in millimeters.
SOLUTION: The ratio of the perimeters of two rectangles is same
as the ratio of their sides. Let x be the perimeter of
the larger rectangle. The perimeter of the larger rectangle is 35 mm.
The area of the triangle is about 171.9 square inches.
Therefore, the correct choice is D.
ANSWER: 35
7. Copy the circles below on a sheet of paper and draw
the common tangents, if any exist.
ANSWER: D
6. GRIDDED RESPONSE Suppose two similar
rectangles have a scale factor of 3:5. The perimeter
of the smaller rectangle is 21 millimeters. What is the
perimeter of the larger rectangle? Express your
answer in millimeters.
SOLUTION: SOLUTION: The ratio of the perimeters of two rectangles is same
as the ratio of their sides. Let x be the perimeter of
the larger rectangle. Draw the two circles and use a straight edge to look
for lines that are tangent to both circles. The easiest
to find are the lines tangent to the outside of both. The perimeter of the larger rectangle is 35 mm.
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ANSWER: 35
Page 2
Draw the two
and -use
a straight edge
to look1-11
Standardized
Testcircles
Practice
Cumulative,
Chapters
for lines that are tangent to both circles. The easiest
to find are the lines tangent to the outside of both. 9. Copy the figure and point D. Then use a ruler to
draw the image of the figure under a dilation with
center D and a scale factor of 2.
SOLUTION: The more difficult lines to find are the tangents that
cross between the circles. There should be 4 common tangents.
ANSWER: There should be 4 common tangents.
9. Copy the figure and point D. Then use a ruler to
draw the image of the figure under a dilation with
center D and a scale factor of 2.
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Use a ruler to draw guidelines from D to each of the
corners of the rectangle. Now measure the distance from each corner to D,
and plot the new corners twice this distance along
the corresponding lines. Connect the corners to
draw the scaled figure. ANSWER: 11. GRIDDED RESPONSE What is the area of the
parallelogram below? Express your answer in square
feet. Round to the nearest whole number if
necessary.
Page 3
b. What is the total area of the figure?
c. Explain how the areas of the squares model the
Pythagorean Theorem.
Standardized Test Practice - Cumulative, Chapters 1-11
SOLUTION: a. The area of the triangle is
11. GRIDDED RESPONSE What is the area of the
parallelogram below? Express your answer in square
feet. Round to the nearest whole number if
necessary.
The area of the squares are:
SOLUTION: Each pair of opposite sides and opposite angles of a
parallelogram are congruent. We have a right triangle
with an acute angles of 65° and a hypotenuse of 9 ft.
b. The total area of the figure is the sum of the areas
of the squares and the triangle: 30 + 25 + 144 + 169
2
The area of a parallelogram is the product of the
base b and height h.
= 368 m .
c. The area of each square represents the square of
2
2
a side of a right triangle. They show that a + b =
The area of the parallelogram is about 106 square
feet.
c since 25 + 144 = 169.
ANSWER: 106
12. Use the figure below to answer each question.
2
ANSWER: a. 144 m2, 169 m2, 25 m2, 30 m2
2
b. 368 m
c. Sample answer: The area of each square
represents the square of a side of a right triangle.
2
2
2
They show that a + b = c since 25 + 144 = 169.
a. Find the area of each square and the area of the
triangle.
b. What is the total area of the figure?
c. Explain how the areas of the squares model the
Pythagorean Theorem.
SOLUTION: a. The area of the triangle is
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Page 4