Download lesson 17.notebook

lesson 17.notebook
October 06, 2015
Topic C Lesson 17:
Solving equations in factored form
A‐REI.3 Student Outcomes:
*Students learn that equations of the form (x-a)(x-b) = 0
have the same solution set as two equations joined by "or"
: x - a = 0 or x - b = 0
*Students solve factored or easily factorable equations
Warm up: Be ready to discuss!!
If you were told that the product of two numbers is zero,
could you assume anything about those numbers?
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Topic C Lesson 17:
Solving equations in factored form
So if....
ab = 0, then either a = 0 or b = 0
This is called the ZERO PRODUCT PROPERTY
You could say the same for the product of
three number equivalent to zero.
abc = 0, then either a = 0, b = 0, or c = 0
lesson 17.notebook
October 06, 2015
Exercise 1
Solve the equations
x - 10 = 0
x + 20 = 0
2
Can you give us two solutions for the following
Exercise 1 con't
Consider this equation:
(x - 4)(x + 3) = 0
Rewrite as a compound statement and
find the two solutions
x - 4 = 0 OR
x+3=0
lesson 17.notebook
October 06, 2015
Exercise 2
Solve: 2x2 - 10x = 0 , for x
Exercise 3
21h2 = 7h
Factor (distribute)
to get a product of
expressions equal
to 0.
Solve the equation for h :
lesson 17.notebook
Exercise 3 con't
October 06, 2015
Solve the equation for x :
x(x - 3) + 5(x - 3) = 0
Exercise 3 con't
x2 + 7x + 12 = 0,
Solve the equation for x :
lesson 17.notebook
October 06, 2015
Steps to solve a polynomial equation:
1-Set the equation = 0
2-Factor using distributive property
3-Use the zero product property
4-Solve for each variable
Solve by using the zero product property
Exercise 4
Consider the equation
(x - 2)(2x - 3) = (x - 2)(x + 5)
lesson 17.notebook
October 06, 2015
Work on the following individually
first, then check in groups.
Solve the following for the solution set
x2 + 10x + 21 = 0
x2 + 4x + 4 = 0