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lesson 17.notebook October 06, 2015 Topic C Lesson 17: Solving equations in factored form A‐REI.3 Student Outcomes: *Students learn that equations of the form (x-a)(x-b) = 0 have the same solution set as two equations joined by "or" : x - a = 0 or x - b = 0 *Students solve factored or easily factorable equations Warm up: Be ready to discuss!! If you were told that the product of two numbers is zero, could you assume anything about those numbers? COPY NOW! Topic C Lesson 17: Solving equations in factored form So if.... ab = 0, then either a = 0 or b = 0 This is called the ZERO PRODUCT PROPERTY You could say the same for the product of three number equivalent to zero. abc = 0, then either a = 0, b = 0, or c = 0 lesson 17.notebook October 06, 2015 Exercise 1 Solve the equations x - 10 = 0 x + 20 = 0 2 Can you give us two solutions for the following Exercise 1 con't Consider this equation: (x - 4)(x + 3) = 0 Rewrite as a compound statement and find the two solutions x - 4 = 0 OR x+3=0 lesson 17.notebook October 06, 2015 Exercise 2 Solve: 2x2 - 10x = 0 , for x Exercise 3 21h2 = 7h Factor (distribute) to get a product of expressions equal to 0. Solve the equation for h : lesson 17.notebook Exercise 3 con't October 06, 2015 Solve the equation for x : x(x - 3) + 5(x - 3) = 0 Exercise 3 con't x2 + 7x + 12 = 0, Solve the equation for x : lesson 17.notebook October 06, 2015 Steps to solve a polynomial equation: 1-Set the equation = 0 2-Factor using distributive property 3-Use the zero product property 4-Solve for each variable Solve by using the zero product property Exercise 4 Consider the equation (x - 2)(2x - 3) = (x - 2)(x + 5) lesson 17.notebook October 06, 2015 Work on the following individually first, then check in groups. Solve the following for the solution set x2 + 10x + 21 = 0 x2 + 4x + 4 = 0