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Chapter 9.4 More Problem Solving 1 Words to Symbols Addition Subtraction Multiplication Division Equals Sum Difference of Product Quotient Gives Plus Minus Times Divide Is/Was/Should be Added To Subtracted From Multiply Into Yields More Than Less Than Twice Ratio Amounts to Increased by Decreased By Of Divided By Represents Total Less Is the Same As Solving Word Problems • Read the problem – Reread – Find the question to be answered – Draw, if possible – Identify quantities – Assign variables to unknown quantities • Translate the problem to an equation • Solve the equation • Look at the results – do they make sense? Practice • Twice a number added to seven is the same as three subtracted from the number Solution • 2x + 7 = x – 3 • x = -10 Hint • When checking your answer, go back to the original problem, if possible, not just your equation Example • Twice the sum of a number and 4 is the same as four times the number decreased by 12 Solution • 2 (x + 4) = 4x – 12 x = 10 Example • Three times the difference of a number and 5 is the same as twice the number decreased by 3. Solution • 3 (x-5) = 2x – 3 3x – 15 = 2x – 3 x = 12 Example • A ten foot board is to be cut into two pieces so that the length of the longer piece is 4 times the length of the shortest. Find the length of each piece Solution • x is shorter piece • 4x is longer piece • x + 4x = 10 x=2 Example • A computer science major works part time fixing computers. He charges $20 to come to your home and then $25 per hour. During one month he visited 10 homes and his income was $575. How many hours did he spend fixing computers? Solution • A computer science major works part time fixing computers. He charges $20 to come to your home and then $25 per hour. During one month he visited 10 homes and his income was $575. How many hours did he spend fixing computers? • For each house he gets $20, without hours. • He went to 10 homes, so $200 • He earned $575; $200 of that was for visiting, so 375 was for hourly work. Since he earns $25 per hour, 375 = 25H, where H is the number of hours = 375/15 = 35 hours Example • The two walls of the Vietnam Memorial in DC form an isosceles triangle (two sides and two angles the same). The measure of the third angle is 97.5 degrees more than either of the two equal angles. Find the third angle. Solution • The two walls of the Vietnam Memorial in DC form an isosceles triangle (two sides and two angles the same). The measure of the third angle is 97.5 degrees more than either of the two equal angles. Find the third angle. 180 degrees in a triangle The third angle is 97.5 deg more than either of the other two, so the third angle is 97.5 + a, where a is the other two We have 180 = 97.5 + a + 2a = 97.5 + 3a 3a = 180 – 97.5 = 82.5 a = 27.5 Consecutive Integers • Two states have area codes that are consecutive odd integers. If the sum of these integers is 1208, what are the integers? Solution • Two states have area codes that are consecutive odd integers. If the sum of these integers is 1208, what are the integers? Consecutive integers are n and n + 2 n + n + 2 = 1208 2n = 1206 n = 603, n + 2 = 605 Example Two consecutive odd numbered classrooms have the sum of their numbers equal 804. Find the two class numbers Solution Two consecutive odd numbered classrooms have the sum of their numbers equal 804. Find the two class numbers An odd number is written as 2n + 1. The next consecutive odd is 2(n+1) + 1 = 2n + 3 2n + 1 + 2n + 3 = 4n + 4 = 804 n = 800/4 = 200 Number = 2(200)+1 = 401 and 403 Example • The code to unlock your gym locker is three consecutive even numbers whose sum is 240. Find the three numbers. Solution • The code to unlock your gym locker is three consecutive even numbers whose sum is 240. Find the three numbers. The first number is 2n, the second 2n + 2, and the third is 2n + 4 2n + 2n + 2 + 2n + 4 = 6n + 6 = 240 6n = 234, n = 36, numbers are 72, 74, 76 Example In a triangle, angle A = angle B and Angle C is 42 degrees less than angle A. Find the angles Solution In a triangle, angle A = angle B and Angle C is 42 degrees less than angle A. Find the angles Angle A = Angle B = x. Angle c = x – 42 x + x + x – 42 = 180, 3x = 222, x = 74 deg Example • A taxi costs $3.00 plus $0.80 cents a mile. How far can you travel for $7.80? Solution • A taxi costs $3.00 plus $0.80 cents a mile. How far can you travel for $7.80? • Let miles = m, cost = 3 + 0.8m = 7.8 • 0.8m = 4.8, m = 6 miles Example • An 18 foot wire is to be cut so that the length of the longer piece is 5 times the length of the shorter piece. Find the length of each piece. Solution • Let x be the shorter piece, y the longer • 18 = x + y • y = 5x • 18 = x + 5x = 6x x = 3 ft, the shorter piece. The longer is 5x = 15 ft Example • Through the year 2010 California will have 21 more electoral votes for president than Texas. If the total votes of the two states is 80, find the votes for each state Solution • T + C = 89 • C = T + 21 T + C = T + T + 21 = 2T + 21 = 89 So 2T = 89 – 21 = 68, T = 34, C = 55 Example • A car rental company charges $28 a day and $0.15 per mile. If you rent a car for a day and your bill is $52, how far did you drive? Solution • A car rental company charges $28 a day and $0.15 per mile. If you rent a car for a day and your bill is $52, how far did you drive? • Your bill is $52. Of that $28 is for the day. This leaves 52 – 28 = 24 for mileage. Let M be the number of miles 0.15 x M = 24 M = 24/0.15 = 2400/15 = 160 miles Section 9.5 Formulas and Problem Solving Formulas Formulas give relationships between quantities – Distance = rate times time – Perimeter of a rectangle = twice the length plus twice the width – The area of a rectangle is length times width – Area of a circle = π r2 Example • If we can travel 5 miles per hour and we have traveled for four hours, how far did we go? Solution • If we can travel 5 miles per hour and we have traveled for four hours, how far did we go? • Distance = speed x time • D = 5 mph x 4 hrs = 20 mi Example • A family is planning a vacation drive that is 1180 miles long. • If they drive 50 mph, how long will it take them to reach their goal? solution • A family is planning a vacation drive that is 1180 miles long. • If they drive 50 mph, how long will it take them to reach their goal? • Distance = speed times time. = D • Let H be the number of hours • 1180 =H (speed) = 50 H • H = 1180/50 = 96 miles Example • Tom has enough fence for a rectangular garden with perimeter 140 feet. If his garden is 30 ft wide, how long can it be? Solution • Tom has enough fence for a rectangular garden with perimeter 140 feet. If his garden is 30 ft wide, how long can it be? • Perimeter = 2L + 2W, where L and W are length and width • 140 = 2L + 2(30) • 140 = 2L + 60 • 80 = 2L • L = 40 feet long Section 9.5 Formulas Solving for a Variable Distance = rate times time: D=rt Solve for t: Need to isolate t. Divide both sides by r: t = D/r Volume: the volume of a box is lwh, V = lwh, where l is length, w is width, and h is height. Solve for h Need to isolate h. Divide both sides by lw h = V/lw Example The perimeter of a rectangle, P = 2l + 2w, where l is the length and w is the width. Solve for w Solution P = 2l + 2w subtract 2l from each side P – 2l = 2w divide both sides by 2 w = (P – 2l) / 2 Example Temperature conversion F = 9/5 C + 32 Solve for C Solution Temperature conversion F = 9/5 C + 32 Solve for C Subtract 32 from both sides: F – 32 = 9/5 C Multiply both sides by 5/9 (5/9)(F – 32) = C Solving for a Variable • Solve T = mnr for n 47 Solution • Solve T = mnr for n • n = T / (mr) 48 Example • Solve for A = PRT for T 49 Solution • Solve for A = PRT for T • Divide by PR, A/PR = T 50 Section 9.6 Percent and Mixture Problems Example • The number 63 is what percent of 72? Solution • 63 = n% x 72 • 63/72 = n% • n = 0.875 • 87.5 % Example • A realtor earns 4% commission. If she earned $6000 on the last house she sold, what was the sales price of the house? Solution • A realtor earns 4% commission. If she earned $6000 on the last house she sold, what was the sales price of the house? • 6000 = 4% x Price • 6000/0.04 = 600,000/ 4 = 150,000 = price Example • Mark is taking Peggy out to dinner. He has $66 to spend. If he wants to tip the server 20%, how much can he afford to spend on the meal? 56 Solution • Mark is taking Peggy out to dinner. He has $66 to spend. If he wants to tip the server 20%, how much can he afford to spend on the meal? • Cost = base + tip x base • Let B = Base • 66 = B + 0.2 B = 1.2B • B = 66/1.2 = 55, • He can spend $55 57 Example • The cost of a certain car increased from $16,000 last year to $17,280 this year. What was the percent of increase? 58 Solution • The cost of a certain car increased from $16,000 last year to $17,280 this year. What was the percent of increase? • Increase = n% ( cost) • Cost this year = 17280 • Cost last year = 16000 • Increase = 17280 – 16000 = 1280 • 1280 = n% (16000) • n% = 1280/16000 = 128/1600 = 0.08 or 8% 59 Example • Patrick weighed 285 pounds two years ago. After dieting, he reduced his weight to 171 pounds. What was the percent of decrease in his weight? 60 Solution • Patrick weighed 285 pounds two years ago. After dieting, he reduced his weight to 171 pounds. What was the percent of decrease in his weight? • Decrease = 285 – 171 = 114 • Decrease = n% ( 285) • 114 = n% (285) • n% = 114/285 = 0.4 or 40% 61 Section 9.7 Solving Inequalities Inequalities Represents the set {xx ≤ 7} 7 Represents the set {xx > – 4} -4 63 Example Graph: −2 < x ≤ 5 64 Additive Property • If a < b then a + c < b + c 65 Example 2x – 4 < x + 6 +4 +4 add 4 2x < x + 10 -x -x subtract x x < 10 66 Multiplicative Property • If a < b then ca < bc if c > 0 ca > bc if c < 0 • When we multiply or divide by a negative number, we change the sign 67 Example 2x – 4 < x + 6 +4 +4 add 4 2x < x + 10 -x -x 2x – 4 < x + 6 -6 - 6 subtract 6 2x – 10 < x subtract x x < 10 or -x > -10 -2x - 2x subtract 2x -10 < -x or 10 > x We used only addition, but proved the multiplication rule. If we multiply or divide by -1, we change the signs and change the inequality 68 Inequalities vs. Equalities • An equality has a equal sign: Ax + B = C • An inequality has one of the following: – Greater than or equal to: ≥ – Less than or equal to: ≤ – Greater than: > – Less than: < • We use the same techniques to solve them, but the answers are quite different 69 Examples of Types of Expressions a) 4x – 5 Neither an equation nor an inequality b) 4x – 5 = 1 An equation or equality c) 4x – 5 < 11 A linear inequality in one variable d) 4x2 – 5 < 11 An inequality, but not linear e) 4x – 5y < 3 A linear inequality in two variables More Complex Inequalities Do the following satisfy 6x – 2 < 5x – 4? • x = -3 • x = -1.5 Solution Do the following satisfy 6x – 2 < 5x – 4? Substitute values • x = -3 6( -3) – 2 < 5(-3) – 4 -18 – 2 < -15 – 4, or – 20 < - 19 YES • x = -1.5 6(-1.5) -2 < 5(-1.5) – 4 -9 – 2 < - 7.5 – 4 -11 < - 11.5 NO Examples Find the solution of (values of x for which it is true) and graph: 6v – 2 < 5v - 3 Solution 6v – 2 < 5v – 3 Add -5v to both sides 6v – 5v – 2 = 5v – 5v – 3 v – 2 < -3 Add 2 to both sides v < 2 – 3 = -1 v < -1 Parentheses? Just distribute as always: 3(x – 4) < -2 3x – 12 < -2 3x < 10 x < 10/3 Example Is x = 2 a solution to the following: • x>3 • x ≥ -1 • 3x – 5 ≥ 2(x – 1) • 5x – 3 ≤ 2x - 3 Solution Is x = 2 a solution to the following: • x > 3; NO • x ≥ -1; YES • 3x – 5 ≥ 2(x – 1) or 3x – 5 ≥ 2x – 2: subtract 2x from both sides: 5x – 5 ≥ -2 add 5 to both sides: 5x ≥ 3; YES • 5x – 3 ≤ 2x – 3 subtract 2x from both sides, 3x – 3 ≤ – 3 add 3 to both sides: 3x ≤ 0; NO Words to Math • x is at least 4: • x is at most 4: • x exceeds 2: • x never exceeds 2: • x is a minimum of 2: Solution • x is at least 4: x ≥ 4 • x is at most 4: x ≤ 4 • x exceeds 2: x > 2 • x never exceeds 2: x ≤ 2 • x is a minimum of 2: x ≥ 2 Example Four times the quantity, x plus three, exceeds eleven more than 3 times x Solution Four times the quantity x plus three exceeds eleven more than 3 times x 4 (x + 3) > 11 + 3x 4x + 12 > 3x + 11 4x – 3x + 12 > 3x – 3x + 11 x + 12 > 11 x + 12 – 12 > 11 – 12 x > -1 Examples Six, plus four times x, is greater than or equal to three times x, plus five Solution Six plus four times x is greater than or equal to three times x, plus five 6 + 4x ≥ 3x + 5 x ≥ -1 Example • Five, minus two times x, is less than or equal to three times x, plus 5 Solution Five minus two times x is less than or equal to three, times x plus 5 5 – 2x ≤ 3 (x+5) 5 – 2x ≤ 3 x + 15 -10 ≤ x Example • Five times w never exceeds three more than four times w Solution • Five times w never exceeds three more than four times w 5w ≤ 4w + 3 w≤3 Solve • 5 (w-2) + 14 > 4 (w+3) Solution • 5 (w-2) + 14 > 4 (w+3) 5w – 10 + 14 > 4w + 12 5w + 4 > 4w + 12 w>8 Solve • 5(2m + 8) + 3m > 3 (4m + 5) - 4 Solution • 5(2m + 8) + 3m > 3 (4m + 5) - 4 10m + 40 + 3m > 12m + 15 – 4 13m + 40 > 12m + 11 m > - 29 Example • You are having a catered event. You can spend at most $1200. The set up fee is $250 plus $15 per person, find the greatest number of people that can be invited and still stay within the budget. 92 Solution • You are having a catered event. You can spend at most $1200. The set up fee is $250 plus $15 per person, find the greatest number of people that can be invited and still stay within the budget. • 1200≥ 250 + 15 n, where n is the number of people • Subtract 20 from each side • 1950 ≥ 15 n • 63.3 ≥ n 93 Example The daily cost of producing x units of computer mice includes a fixed cost of $450 per day and a variable cost of $4 per unit. The income produced by selling x units is $5 per unit. Determine the values of x for which the company earns a daily profit. Solution The daily cost of producing x units of computer mice includes a fixed cost of $450 per day and a variable cost of $4 per unit. The income produced by selling x units is $5 per unit. Determine the values of x for which the company earns a daily profit. Cost = fixed cost + variable cost times the number of units Profit = income – cost Cost = 450 + 4x, where x is the number of units Income = 5x, where x is the number of units Profit = 5x – 450 – 4x = x – 450 x – 450 > 0, or x > 450 units Example To earn an A in algebra, a student must have at least 630 points. He has 535 points going into the last, 100 point test. How many points must he score on the last test? Solution To earn an A in algebra, a student must have at least 630 points. He has 535 points going into the last, 100 point test. How many points must he score on the last test? 535 + x > 630 x > 95 Example • A farmer has 84 ft of fence that he wants to use to fence three sides of a rectangular pen with sides 12ft, x ft, and 12 ft. What is the largest area he can fence in? Solution • A farmer has 84 ft of fence that he wants to use to fence three sides of a rectangular pen with sides 12ft, x ft, and 12 ft. What is the largest area he can fence in? Fencing needed is 12 + x + 12. This must be less than or equal to 84 ft 12 + x + 12 ≤ 84 x + 24 ≤ 84 x ≤ 60 Area is length times width, = 12 x. The area ≤ 60 (12) = 720 ft Example 1. The sum of any two sides of a triangle is greater than the length of the third sides. If the lengths of the sides are a, b, and c, find three different inequalities illustrating the statement 2. Write an expression for: a. 3 more than x b. 3 is more than x c. 2 less than x d. 2 is less than x Solution 1. The sum of any two sides of a triangle is greater than the length of the third sides. If the lengths of the sides are a, b, and c, find three different inequalities illustrating the statement a + b > c, a + c > b, c + b > a 2. Write an expression for: a. 3 more than x: x + 3 b. 3 is more than x: 3 > x c. 2 less than x: x - 2 d. 2 is less than x: 2 < x