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NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 17 M1 PRECALCULUS AND ADVANCED TOPICS Lesson 17: The Geometric Effect of Multiplying by a Reciprocal Classwork Opening Exercise Given π€ = 1 + π, what is argβ‘(π€) and |π€|? Explain how you got your answer. Exploratory Challenge 1/Exercises 1β9 1. Describe the geometric effect of the transformation πΏ(π§) = (1 + π)π§. 2. Describe a way to undo the effect of the transformation πΏ(π§) = (1 + π)π§. 3. Given that 0 β€ argβ‘(π§) < 2π for any complex number, how could you describe any clockwise rotation of π as an argument of a complex number? 4. Write a complex number in polar form that describes a rotation and dilation that will undo multiplication by (1 + π), and then convert it to rectangular form. Lesson 17: The Geometric Effect of Multiplying by a Reciprocal This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.81 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. M1 Lesson 17 NYS COMMON CORE MATHEMATICS CURRICULUM PRECALCULUS AND ADVANCED TOPICS 5. In a previous lesson, you learned that to undo multiplication by 1 + π, you would multiply by the reciprocal Write the complex number 1 1+π How do your answers to Exercises 4 and 5 compare? What does that tell you about the geometric effect of multiplication by the reciprocal of a complex number? 7. Jimmy states the following: 1 π+ππ 1+π . in rectangular form π§ = π + ππ where π and π are real numbers. 6. Multiplication by 1 has the reverse geometric effect of multiplication ππ¦β‘ + ππ. Do you agree or disagree? Use your work on the previous exercises to support your reasoning. 8. Show that the following statement is true when π§ = 2 β 2β3π: 1 1 π§ π The reciprocal of a complex number π§ with modulus π and argument π is with modulus and argument 2π β π. 9. Explain using transformations why π§ β Lesson 17: 1 = 1. π§ The Geometric Effect of Multiplying by a Reciprocal This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.82 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 17 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS Exploratory Challenge 2/Exercise 10 10. Complete the graphic organizer below to summarize your work with complex numbers so far. Operation Geometric Transformation Example. Illustrate algebraically and geometrically. Let π = π β ππ and π = βππ. Addition π§+π€ Subtraction π§βπ€ Conjugate of π§ Multiplication π€βπ§ Reciprocal of π§ Division π€ π§ Lesson 17: The Geometric Effect of Multiplying by a Reciprocal This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.83 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 17 M1 PRECALCULUS AND ADVANCED TOPICS Exercises 11β13 Let π§ = β1 + π, and let π€ = 2π. Describe each complex number as a transformation of π§, and then write the number in rectangular form. 11. π€π§Μ 12. 1 π§Μ 13. Μ Μ Μ Μ Μ Μ Μ Μ π€+π§ Lesson 17: The Geometric Effect of Multiplying by a Reciprocal This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 S.84 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 17 NYS COMMON CORE MATHEMATICS CURRICULUM M1 PRECALCULUS AND ADVANCED TOPICS Problem Set 1. 2. Describe the geometric effect of multiplying π§ by the reciprocal of each complex number listed below. a. π€1 = 3π b. π€2 = β2 c. π€3 = β3 + π d. π€4 = 1 β β3π Let π§ = β2 β 2β3π. Show that the geometric transformations you described in Problem 1 really produce the correct complex number by performing the indicated operation and determining the argument and modulus of each number. a. c. 3. β2β2β3π b. π€1 β2β2β3π d. π€3 β2β2β3π π€2 β2β2β3π π€4 In Exercise 12 of this lesson, you described the complex number 1 π§Μ as a transformation of π§ for a specific complex number π§. Show that this transformation always produces a dilation of π§ = π + ππ. 4. Does πΏ(π§) = 1 satisfy the conditions that πΏ(π§ + π€) = πΏ(π§) + πΏ(π€) and πΏ(ππ§) = ππΏ(π§), which makes it a linear π§ transformation? Justify your answer. 5. Μ Μ Μ Μ 1 Show that πΏ(π§) = π€ ( π§) describes a reflection of π§ about the line containing the origin and π€ for π§ = 3π and π€ π€ = 1 + π. 6. Describe the geometric effect of each transformation function on π§ where π§, π€, and π are complex numbers. Μ Μ Μ Μ Μ Μ Μ Μ π§βπ€ π§βπ€ b. πΏ2 (π§) = ( ) a. πΏ1 (π§) = π π c. 7. Μ Μ Μ Μ Μ Μ Μ Μ π§βπ€ πΏ3 (π§) = π ( ) π d. Μ Μ Μ Μ Μ Μ Μ Μ π§βπ€ πΏ3 (π§) = π ( )+π€ π Verify your answers to Problem 6 if π§ = 1 β π, π€ = 2π, and π = β1 β π. π§βπ€ Μ Μ Μ Μ Μ Μ Μ Μ π§βπ€ a. πΏ1 (π§) = b. πΏ2 (π§) = ( ) π π c. Μ Μ Μ Μ Μ Μ Μ Μ π§βπ€ πΏ3 (π§) = π ( ) π Lesson 17: d. Μ Μ Μ Μ Μ Μ Μ Μ π§βπ€ πΏ3 (π§) = π ( ) + π€ The Geometric Effect of Multiplying by a Reciprocal This work is derived from Eureka Math β’ and licensed by Great Minds. ©2015 Great Minds. eureka-math.org This file derived from PreCal-M1-TE-1.3.0-07.2015 π S.85 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.