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Transcript
Chapter 39 Particles Behaving as Waves
March 20 De Broglie waves
39.1 Electron waves
Louis de Broglie (1892 –1987):
• French physicist.
• Nobel Prize in Physics (1929) for his
prediction of the wave nature of electrons.
• Originally studied history.
Broglie hypothesis:
• All forms of matter have both wave and particle characteristics.
• The de Broglie wavelength of a particle is  
• The frequency of a particle is
f 
E
.
h
h
h
h
.
, 
in relativity.
p mv
mv
Note: Some photon equations, especially f =c/, may not apply to particles with mass.
1
Electron diffraction
Davisson-Germer experiment (1926):
• Scattering of low-energy electrons
from a nickel target exhibited maxima
and minima at specific angles.
• They measured the wavelength of the
electrons and confirmed de Broglie
relationship: p = h /.
Electron diffraction:
Like a diffraction grating, strong reflection occur at
d sin   m
m  0,1,2, 
De Broglie wavelength of a nonrelativistic electron:
p2 
eVba 
h
2m    

h
2meVba



p
2
The electron microscope
• The electron microscope
depends on the wave
characteristics of electrons.
• The electron microscope has
a high resolving power
because the electrons have a
very short wavelength:
electron ~ (1/ 100) photon.
Example 39.1,2,3
Test 39.1
3
Read: Ch39: 1
Homework: Ch39: 3,6,11,14
Due: March 31
4
March 22 The nuclear atom
39.2 The nuclear atom and atomic spectra
Atomic line spectra:
• A discrete line emission spectrum is observed when a low-pressure gas sample is
subjected to an electric discharge.
• An absorption spectrum is obtained by passing a white light from a continuous source
through a cool gas sample.
• Observation and analysis of these spectral lines is called spectroscopy.
• No two elements have the same line spectrum.  Spectroscopy provides a practical
and sensitive technique for identifying the elements existing in unknown samples.
5
Emission spectra:
Absorption spectra:
6
Joseph John Thomson (1856-1940):
• British scientist.
• Nobel Prize in physics (1906).
• The discoverer of the electron.
Thomson’s model of the atom:
Electrons embedded throughout a volume of positive charge.
7
Rutherford’s thin foil experiment (1911):
• A beam of positively charged alpha particles hit a thin gold
foil target and are scattered.
• Most of the particles passed through the foil. Many
particles were scattered at large angles. Some particles were
deflected backward.
• The large deflections could not be explained by Thomson’s
model.
8
Rutherford’s model of the atom:
• Positive charge is concentrated in the center of the
atom, called the nucleus.
• Electrons orbit the nucleus like planets orbit the sun.
Difficulties with the Rutherford model: Failure of
classical physics
1) Rutherford model is unable to explain that atoms
are stable and emit certain discrete characteristic
frequencies of electromagnetic radiation.
2) Rutherford’s electrons are undergoing a centripetal
acceleration. It should radiate electromagnetic
waves of the same frequency. The radius should
steadily decrease and the electron should
eventually spiral into the nucleus.
Example 39.4
Test 39.2
9
Read: Ch39: 2
Homework: Ch39: 17
Due: March 31
10
March 24,27 Bohr’s model of the atom
39.3 Energy levels and the Bohr model of the atom
Bohr’s hypothesis about energy levels:
Each atom has a set of energy levels. The line spectrum of an element results from the
emission or absorption of photons when the atom makes a transition between different
energy levels.
hf 
hc

 Ei  E f
Example 39.5
Frank-Hertz experiment (1914):
When the electrons moving in mercury vapor have kinetic energy of 4.9 eV or more,
the vapor emits ultraviolet light with wavelength at 250 nm.
11
Electron waves and Bohr model of hydrogen
Niels Bohr (1885-1962)
• Danish physicist.
• Fundamental contributions to atomic structure and quantum
mechanics.
• Nobel Prize in Physics in 1922.
• Taking part in the Manhattan Project.
Bohr’s theory of hydrogen (1913):
• An obsolete theory which has been replaced by
quantum mechanics.
• The model can still be used to develop ideas of
energy and angular momentum quantization in
atomic-sized systems.
Assumption 1: The electron moves in circular orbits
around the proton under the electric force.
Assumption 2: Only certain electron orbits are stable.
The atom does not emit energy in these stationary
states.
12
Assumption 3: Radiation is emitted by the atom when the electron makes a transition from
an initial state to a lower-energy orbit. The frequency of the emitted radiation is given by
Ei – Ef = hƒ, which is independent of frequency of the electron’s orbital motion.
Assumption 4: The allowed orbits are those for which the electron’s orbital angular
momentum about the nucleus is quantized and equal to an integral multiple of =h/2p:
Ln=mvnrn = n ħ, n = 1, 2, 3,…
The de Broglie wave and the Bohr model:
Fitting a standing wave around a circle:
The circumference of the circle must include
integer number of wavelengths.
2prn  nn

nh

 n.
h
h   mvn rn 
n 

2p
pn mvn 
13
Bohr orbitals:
2
h  
2 h 0
Angular momentum: mvn rn  n
r n
, n  1,2,3,
2p   n
pme 2
2
2 
1
e
mv
e2
Coulomb force =
n 


v 
2
Centripetal force:
4p 0 rn
rn   n 2nh 0
Bohr radius (rn for n =1):
h 2 0
a0 
 0.0529 nm
2
pme
Radius of an orbit:
rn  n 2 a0  n 2 (0.0529 nm)
14
Bohr energy levels:
1
e2 
2
En  K n  U n  mvn 

2
4p0 rn 
2

1 me4
13
13.6.6eV
eV
2 h 0
rn  n

E




..



n
2
2
2 2
22
pme
n 8 0 h
nn


e2
vn 

2nh 0

hcR
me 4
Rydberg Constant: En   2 , R  2 3  1.097  107 m -1 is the Rydberg constant.
n
8 0 h c
 hcR   hcR 
 EnU  EnL    2     2 

 nU   nL 
hc
 1
1 
 R  2  2 

 nL nU 
1
This theoretical prediction agrees with experimental observation very well.
15
Spectra of the hydrogen atom:
Balmer series:
Johann Balmer (1885): Empirical equation for
the four visible emission lines of hydrogen:
Hα , λ = 656.3 nm,
Hβ , λ = 486.1 nm, 1  R 1  1 
2
2
Hγ , λ = 434.1 nm, 
2 n 
Hδ , λ = 410.2 nm.
Other series:
Lyman series:
1 

 R 1  2 , n  2,3,4, 

 n 
1
1 1 
 R  2  2 , n  4,5,6,

3 n 
1
 1 1 
Brackett series:  R  2  2 , n  5,6,7, 

4 n 
Paschen series:
1
Energy level diagram:
Ground level, excited levels, ionization energy, transitions.
16
Extension to H-like atoms:
( Ze)e
Ze 2
Coulomb force:

2
4p0 r
4p0 r 2
-e
+Ze
Z is the atomic number of the element.
a0
.
Z
Z 2 me4
En   2
.
2 2
n 8 0 h
rn  n 2
Example 39.6
Test 39.3
17
Read: Ch39: 3
Homework: Ch39: 20,21,29,30
Due: March 31
18
March 29,31 Blackbody radiation
39.5 Continuous spectra
Thermal radiation: The electromagnetic emission from an object.
• Covers all the spectrum.
• At room temperature, the wavelengths of the radiation are mainly in the infrared. As the
surface temperature increases, the wavelength shifts to red and then white.
• Classical physics could not describe the observed distribution of the radiation emitted by
a blackbody.
Blackbody: An ideal system that absorbs all
radiation incident on it.
Blackbody radiation: The electromagnetic
radiation emitted by a blackbody.
19
Two significant experimental results:
1) The total power of the emitted radiation increases with temperature.
Stefan-Boltzmann law (Chapter 17):
I  sT 4
I: intensity of radiation.
s: constant, = 5.67×10-8 W/m2·K4.
T: surface temperature.
2) The peak of the wavelength distribution shifts to shorter wavelengths as the
temperature increases.
Wien’s displacement law: mT = 2.90 × 10-3 m·K
An early classical attempt to explain blackbody radiation:
Rayleigh-Jeans law: I ( ) 
2pckT
4
Ultraviolet catastrophe:
At short wavelengths, there was a major disagreement
between the Rayleigh-Jeans law and the experiment.
20
Max Planck and the quantum hypothesis: Planck (1900) assumed that the cavity
radiation came from atomic oscillations in the cavity walls. He made two assumptions about
the nature of the oscillators:
1) The energy of an oscillator can have only certain discrete values:
En = n h ƒ
Quantum number
Frequency of oscillation
i) The energy is quantized.
ii) Each energy value corresponds
to a quantum state.
Planck’s constant, h = 6.626×10-34 J·s
2) The oscillators emit or absorb energy when making a transition from one quantum state
to another, E = h f.
Allowed transitions
Energy levels
21
Energy-level diagram:
A diagram that shows the quantized energy levels and the allowed transitions.
The energy levels are populated
according to the Boltzmann
distribution law:
Nn
 exp[  En / kT ]  exp[ nhf / kT ]
N0
The average energy of a wave is the
energy difference between levels of
the oscillator, weighted by the
probability of the wave being emitted
[~ Sn exp(-En /kT)].
22
Planck’s radiation law: Planck generated a theoretical expression for the intensity
distribution of blackbody radiation:
2phc 2
I ( )  5 hc / kT
 (e
 1)
Conclusions from Planck’s equation:
1) At long wavelengths, Planck’s equation reduces to the Rayleigh-Jeans law
(using ex1+x):
I ( ) 
2pckT
4
.
2) At short wavelengths, it predicts an exponential decrease in intensity with decreasing
wavelength. This is in agreement with experimental results.
3) Total power radiated :


0
I ( )d  
s 

0
2phc 2
2p 5 k 4 4
4
d


T

s
T
5 (e hc / kT  1)
15c 2 h 3
2p k
8
2
4

5.67

10
W/m
·K
15c 2 h 3
5
4
Stefan-Boltzmann law
23
4) Peak of the distribution (“most probable” wavelength):
dI ( )
hc
 0  mT  4.97   0.00290 m  K
d
k
Wien’s displacement law
Question:
1) m at room temperature.
2) fpeak=c/peak?
Example 39.7,8
Test 39.5
24
Read: Ch39: 5
Homework: Ch39: 38,40,41,43,61
Due: April 7
25