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Independent Assortment and Meiosis A B B a b B A 25% AB b A Linkage and Meiosis 25% Ab A B A Meiosis B 50% AB 50% ab b a b a Meiosis 25% aB 0% aB a B A 25% ab 0% Ab b a b a Partial Linkage and Meiosis Crossingover and Recombinantion B A B A b a ?% AB ?% ab b a Meiosis ?% aB B a ?% Ab Which are the Parental types and which the recombinant types? b A Genetic Distance • The likelihood of recombination is roughly proportional to the distance two genes are apart. • If two genes are close together on a chromosome there will be few recombinants. Genetic Distance Genetic Distance = Frequency of Recombination = (Rf) of Recombinants = #total # of progeny In a Testcross An underestimate of true Rf!!! • If two genes are farther apart on a chromosome there will be more recombinants. •Units for genetic distance – centimorgans = map units 1 map unit = 1%Rf 1 Outcome of Double Crossing-Over Effect of Double Crossing-over b a B A b a B Double Crossing Over Mask Recombination Therefore analysis of recombinant genotype will underestimate the frequency of crossing over Practice Problem In Drosophila, the droopy gene is 5 map units away from the curved gene. A heterozygous female was generated by mating a wildtype female with a double recessive male. If this heterozygote was testcrossed and 1000 progeny were examined, how many would you expect to be wildtype for both traits? Example Generate a dihybrid and testcross Observed frequency (%) of Recombinant between loci A Actual frequency (%) of Recombinant between two loci Detecting and Estimating Linkage • Why determine linkage? Help determine the chromosomal position of a locus. Remember chromosomal position defines a gene. • To detect linkage generate a dihybrid and testcross the dihybrid. • First test for independent assortment (Chi square) in testcross progeny – If you fail to reject ind assort, then conclude the genes are on different chromosome or are on the same chromosome but far apart >45 mu. – If you reject independent assortment conclude the genes are on the same chromosome and closer than 50 map units. Genetic Mapping 1. Wildtype female X black curled male 2. F1 Female X black curled male Testcross progeny 784 wildtype 762 black curled 234 curled 210 black Are these genes independently assorting? Only test for linkage if reject independently assortment How far apart are the genes on the chromosome? Rf = # rec/total Progeny Why is this an underestimate of genetic distance? What results would you predict if you testcross a male F1 (remember in drosophila there is no crossing over in males) • Analyze the relative position on a chromosome. • Example – Black and Curly are 22.3mu – Black and Pink are 30.6mu – Curly and Pink are 46.6 • Rough map • Effects of double crossovers 2 Three Point Mapping • Analyze results of a testcross of a trihybrid. • Better than two point mapping for determining gene position on a chromosome • Better for determining position on a chromosome • Trick: Analyze two genes at a time Example • In nematode the dumpy body, uncoordinated movement, and knobby body are all recessive to wildtype. A trihybrid female was generated by mating a homozygous dumpy and a homozygous uncoordinated knobby. The trihybrid was testcrossed and the following progeny were obtained. Dpy Unc Knb Unc Knb Knb Unc 3 392 34 61 Dpy Unc Dpy Knb Dpy Wildtype 40 65 410 3 How would you test for Ind Assort of knb and dpy? What is the linkage relationship between the three genes? Draw a genetic map indicating the relative position of the genes on a chromosome. 3