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Introduction to Mechanics Non-uniform Circular Motion Introducing Energy Lana Sheridan De Anza College Mar 10, 2016 Last time • applying the idea of centripetal force Overview • non-uniform circular motion and tangential acceleration • energy and work mass? Explain. (c) What is the direction and magnitude of your acceleration when you are at the bottom of the wheel? Assume that its rotational speed has remained constant. Banked Turn Related Problems 71. •• A Conical Pendulum A 0.075-kg toy airplane is tied to the ceiling with a string. When the airplane’s motor is started, it This situation iswith called a “conical But notice, moves a constant speed of pendulum”. 1.21 m/s in a horizontal circle of radius 0.44 m, as illustrated in Figurein 6–40. Find (a) the angle the at an angle of actually a banked-turn-style problem disguise! string makes with the vertical and (b) the tension in the string. ox is attached as shown in tween the box unt the spring it is ! ▲ FIGURE 6–40 Problem 71 •• Awas tugboat tows by a barge constantforce speedin with The role72.that played the atnormal thea 3500-kg banked turn cable, as shown in Figure 6–41. If the angle the cable makes problem is with nowthe played by the tension in the string. horizontal where it attaches to the barge and the tugboat is 22°, find the force the cable exerts on the barge in the forward direction. 1 See prob 85, Ch 6. m of the test tube a linm the axis of rotation, Non-uniform Circular Motion A particle can speed up or slow down while following a circular arc. It it does this it must have a component of its acceleration along the direction of its velocity. 560 g that are many thoudevices referred to as ion g. Even in the relvolved in a centrifuge est tube have a mass bottom of the tube is y at atotal acp x O or decrease its speed. ntial to its path that ! icular to its path, a cp, ▲ FIGURE 6–15 A particle moving in a rated in Figure 6–15. circular path with tangential acceleration ! 1 Figure from Walker, d a cp. We will explore In this“Physics”. case, the particle’s speed is Non-uniform Circular Motion = 9560 g y at ions that are many thouact, devices referred to as million g. Even in the rels involved in a centrifuge the test tube have a mass the bottom of the tube is ease or decrease its speed. ngential to its path that ! pendicular to its path, a cp, llustrated in Figure 6–15. ! centripetal . We will explore t and a cpThe and changes atotal acp O x ▲ FIGURE 6–15 A particle moving in a circular path with tangential acceleration acceleration acp is toward the center In this case, the particle’s speed is increasing at ratevelocity. given by at. the direction ofthe the of the circle The tangential acceleration at is tangent to the circle and causes a change of speed. Problems Radial and Tangential Accelerations 105 10 cm minate cenbe at te the 41. A train slows down as it rounds a sharp horizontal M turn, going from 90.0 km/h to 50.0 km/h in the 15.0 s it takes to round the bend. The radius of the curve is 150 m. Compute the acceleration at the moment the train speed reaches 50.0 km/h. Assume the train continues to slow down at this time at the same rate. ate of small edge). 42. A ball swings counterclockwise in a vertical circle at the end of a rope 1.50 m long. When the ball is 36.9° past the lowest point on its way up, its total acceleration is 1 222.5 i^ 1 20.2 j^ 2 m/s2. For that instant, (a) sketch a vector diagram showing the components of its acceleration, (b) determine the magnitude of its radial acceleration, and (c) determine the speed and velocity of the ball. earch ontal, n Figin a away. cond, elera- 43. (a) Can a particle moving with instantaneous speed 3.00 m/s on a path with radius of curvature 2.00 m have an acceleration of magnitude 6.00 m/s2? (b) Can 1 Pageit93, Serway Jewett. have an&acceleration of magnitude 4.00 m/s2? In Problems Radial and Tangential Accelerations 10 cm minate cenbe at te the 105 41. A train slows down as it rounds a sharp horizontal M turn, going from 90.0 km/h to 50.0 km/h in the 15.0 s it takes to round the bend. The radius of the curve is 150 m. Compute the acceleration at the moment the train speed reaches 50.0 km/h. Chapter 4 Assume 159 the train continues to slow down at this time at the same rate. ate of Sketch: 42. A ball swings counterclockwise in a vertical circle at gsmall both its speed and the end of a rope 1.50 m long. When the ball is 36.9° n vector will be the edge). past the lowest point on its way up, its total acceleration is 1 222.5 i^ 1 20.2 j^ 2 m/s2. For that instant, (a) sketch a tial and radial earch vector diagram showing the components of its acceler.ontal, The tangential ation, (b) determine the magnitude of its radial accelFig- the changing dnfrom eration, and (c) determine the speed and velocity of in a the radial while the ball. away. d from the radius of 43. (a) Can a particle moving with instantaneous speed cond, speed. 3.00 m/s on a path with radius of curvature 2.00 m elera- havekm/h an acceleration of magnitude 6.00 m/s2? (b) Can eed units1 from 2 ANS. FIG. P4.41 Pageit93, Serway Jewett. have an&acceleration of magnitude 4.00 m/s ? In Radial and Tangential Accelerations Problems 105 10 cm minate cenbe at te the 41. A train slows down as it rounds a sharp horizontal M turn, going from 90.0 km/h to 50.0 km/h in the 15.0 s it takes to round the bend. The radius of the curve is 150 m. Compute the acceleration at the moment the train speed reaches 50.0 km/h. Assume the train continues to slow down at this time at the same rate. ate of small edge). 42. A ball swings counterclockwise in a vertical circle at the end of a rope 1.50 m long. When the ball is 36.9° past the lowest point on its way up, its total acceleration is 1 222.5 i^ 1 20.2 j^ 2 m/s2. For that instant, (a) sketch a vector diagram showing the components of its acceleration, (b) determine the magnitude of its radial acceleration, and (c) determine the speed and velocity of the ball. earch ontal, n Figin a away. cond, elera- 43. (a) Can a particle moving with instantaneous speed 3.00 m/s on a path with radius of curvature 2.00 m 1 an acceleration of magnitude 6.00 m/s2? (b) Can Pagehave 93, Serway & Jewett. Radial and Tangential Accelerations Problems 105 10 cm minate cenbe at te the 41. A train slows down as it rounds a sharp horizontal M turn, going from 90.0 km/h to 50.0 km/h in the 15.0 s it takes to round the bend. The radius of the curve is 150 m. Compute the acceleration at the moment the train speed reaches 50.0 km/h. Assume the train continues to slow down at this time at the same rate. ate of small edge). in a vertical circle at 42. A ball swings counterclockwise 90.0 the end a rope long.m/s When the m/s ball is 36.9° vi = of 90.0 km/h1.50 m = = 25.0 3.6way up, its total acceleration past the lowest point on its 2. For that instant, (a) sketch a is 1 222.5 i^ 1 20.2 j^ 2 m/s 50.0 vector diagram showing the components its accelerm/s = 13.9ofm/s vf = 50.0 km/h = ation, (b) determine the3.6 magnitude of its radial acceleration, and (c) determine the speed and velocity of the ball. earch ontal, n Figin a away. cond, elera- 43. (a) Can a particle moving with instantaneous speed 3.00 m/s on a path with radius of curvature 2.00 m 1 an acceleration of magnitude 6.00 m/s2? (b) Can Pagehave 93, Serway & Jewett. Radial and Tangential Accelerations Problems 10 cm minate cenbe at te the 105 41. A train slows down as it rounds a sharp horizontal M turn, going from 90.0 km/h to 50.0 km/h in the 15.0 s it takes to round the bend. The radius of the curve is 150 m. Compute the acceleration at the moment the train speed reaches 50.0 km/h. Assume the train continues to slow down at this time at the same rate. in a vertical circle at 42. A ball swings counterclockwise 90.0 the end a rope long.m/s When the m/s ball is 36.9° vi = of 90.0 km/h1.50 m = = 25.0 3.6way up, its total acceleration past the lowest point on its 2. For that instant, (a) sketch a is 1 222.5 i^ 1 20.2 j^ 2 m/s earch 50.0 vector diagram showing the components its accelerm/s = 13.9ofm/s vf = 50.0 km/h = ontal, 3.6 ation, (b) determine the magnitude of its radial acceln Figeration, and (c) determine the speed and velocity of in a Tangential accel. corresponds to changing speed: at,avg = ∆v ∆t the ball. away. ate of small edge). v2 43. (a) Can particle moving with instantaneous cond, Centripetal accel.a corresponds to changing direction: acp =speed 3.00 m/s on a path with radius of curvature 2.00r m elera1 an acceleration of magnitude 6.00 m/s2? (b) Can Pagehave 93, Serway & Jewett. Radial and Tangential Accelerations 10 cm minate cenbe at te the Problems 105 41. A train slows down as it rounds a sharp horizontal M turn, going from 90.0 km/h to 50.0 km/h in the 15.0 s it takes to round the bend. The radius of the curve is 150 m. Compute the acceleration at the moment the train speed reaches 50.0 km/h. Assume the train continues to slow down at this time at the same rate. ate of 42. A ball swings counterclockwise in a vertical circle at small the end of2a rope 1.50 m long.2 When the ball is 36.9° ; apoint (calling outward positive) r = −1.29 edge). at = −0.741 past them/s lowest on its m/s way up, its total acceleration 2 ^ ^ is 1 222.5 i 1 20.2 j 2 m/s . For that instant, (a) sketch a earch vector components 2 ontal, a =diagram 1.48 m/sshowing inward the at an angle 29.9◦of its acceleration, (b) determine the magnitude of its radial acceln Figbackward from the direction of travel eration, and (c) determine the speed and velocity of in a the ball. away. cond, elera- 43. (a) Can a particle moving with instantaneous speed Page3.00 93, Serway & Jewett. m/s on a path with radius of curvature 2.00 m 1 Energy Energy is a difficult concept to define, but it is very important for physics. Energy can take many different forms. Knowing the amount of energy a system has can tell us about what states or configurations we can find the system in. Energy Energy is a difficult concept to define, but it is very important for physics. Energy can take many different forms. Knowing the amount of energy a system has can tell us about what states or configurations we can find the system in. One way that energy is often described is that it represents the ability of a system to do work. We need to know what work is! Work Work is an amount of energy. The amount of work done on an object depends on the applied force and the displacement of the object as the force acts. we do work. The greater the force, the greater the work; the grea tance, the greater the work. These simple ideas form the basis for ou Work of work. ! Toamount be specific, suppose we push a box with a! constant force F, a Work is an of energy. Figure 7–1. If we move the box in the direction of F through a displace work W we have done is Fd: The amount of work done on an object depends on the applied Definition of Work, W, of When Constant Is in the Direction of Displac force and the displacement theaobject as Force the force acts. W = Fd If the force is in the same direction as the displacement, SI unit: newton-meter 1N # m2 = joule, J W = Fd orce in through case, nt are in e on the d F F Work W = Fd Units of Work? They have a special name: Joules, symbol J. 1 joule = 1 J = 1 Nm Work is not a vector. Work is a scalar. The work done by gravitational force the agent on the Example rest through a ver book–Earth system is What is the work done in mgy lifting a 3.0-kg book 0.50 m? to our discussion o f " mgy i. Physics S S !r Fapp Physics yf S yi mg Figure 7.15 An external agent lifts a book slowly from a height yi to a height yf . appear as an incre the work and is at the kinetic energy Because the en the work-kinetic e appear as some fo book, we could rel (and therefore, the that was done in l tem had the potenti allowed to fall. Th is released potenti only be associated The amount of po the system. Movin may change the co The work done by gravitational force the agent on the Example rest through a ver book–Earth system is What is the work done in mgy lifting a 3.0-kg book 0.50 m? to our discussion o f " mgy i. appear as an incre the work and is at the kinetic energy S Because the en Fapp S !r the work-kinetic e Physics appear as some fo yf book, we could rel S mg (and therefore, the yi that was done in l tem had the potenti allowed to fall. Th is released potenti Figure 7.15 An external agent To lift a book withlifts constant velocity, mg be associated a book slowly fromrequires a heightFyiapp = only The amount of po to a height yf . W = Fd = (3.0 kg)(9.81 m/s2 )(.50 m) = 14.7 theJ system. Movin may change the co Physics Summary • non-uniform circ. motion and tangential acceleration • energy and work Homework Walker Physics: • Ch 6, onward from page 177. Problems: 29, 105, 109, 110 • Ch 7, onward from page 210. Questions: 1, 3, 5; Problems: 5, 7