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Transcript
2.8 Integrators and Differentiators
2.8.1 The Inverting Configuration with General Impedances
Vo ( s )
Z ( s)
 2
Vi ( s )
Z1 ( s )
(2.48)
Example 2.6, p106
Sol)
Vo ( s )
1

Vi ( s )
Z1 ( s )Y2 ( s )
Vo ( s )  R2 / R1

Vi ( s ) 1  sC2 R2
Vo ( s )
 ? * Is this STC circuit?
Vi ( s )
* dc gain=?, 3 dB frequency=?
* Design a circuit of dc gain=40 dB,
3 dB frequency=1 kHz, input
resistance = 1 kΩ
* Frequency of gain=1
and phase at this frequency
Microelectronic Circuits - Fifth Edition
Sedra/Smith
Vo ( s )
1

R1
Vi ( s )
 sC2 R1
R1
K 
R2
R1
0 
1
C 2 R2
R2
 100, R1  1 k, R2  100 k
R1
1
0  2  1  103 
C2  1.59 nF
C2  100  103
-20dB roll off  f t  100 f 0  100 kHz
40 dB = 100 V/V
from Bode plots phase shift = -270o or +90o
Copyright  2004 by Oxford University Press, Inc.
29