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Transcript
CHM 101 LECTURE NOTE
COURSE TITLE: INTRODUCTORY PHYSICAL CHEMISTRY
CREDIT UNIT:
03
PART TITLE:
CHEMICAL EQUILIBRIUM
COURSE LECTURER:
DR. S.A. AHMED
COURSE SYNOPSIS
- The concept of equilibrium
- Equilibrium Law ( Law of Mass action )
- Relationship between Kp and Kc
- Relationship between G and K
- Effect of temperature on the equilibrium
constant.
- Homogenous chemical equilibria
- Heterogeneous equilibria system
- Factors affecting equilibrium constants
- Chemical equilibrium in solution
 water dissociation constant
 hydrolysis and hydrolysis constant
- Solubility equilibria
- Common-ion effects
RECOMMENDED TEXTBOOKS/ REFERENCES
1. Principle of physical chemistry by J.M. Gross
2. Physical chemistry by Atkins
3. Essentials of physical chemistry by Bahl and Bahl
4. Chemistry: The central science by Brown, Lemay,
Bursten and Murphy.
5. Physical chemistry by K.K. Sharma and L.K. Sharma
Concept of Equilibrium
Consider this direct reaction,
aA + bB
→
cC + dD
The reaction stops when the reactants are used up.
However, for a reversible reaction like this
aA + bB
cC + dD
the equilibrium is attained when the rate of forward reaction
is equal to the rate of backward reaction.
Chemical equilibrium is the state of a reversible reaction when
the two opposing reactions occur simultaneously.
At equilibrium, the concentrations of reactants and products
do not change with time.
The Equilibrium Law (Law of Mass action)
The law states that “at constant temperature, the rate at which
a substance reacts is directly proportional to the active masses
of the reactant”
Active mass is a thermodynamic quantity and it is expressed
a=fc, where a -active mass, f- activity co-efficient (fugacity),
c- molar concentration.
For ideal gaseous and solution reaction, f = 1.
Therefore, the active mass is equal to molar concentration.
a
b
According to the law, R f   A B 
R
Also,
Rb 
 R =K
b
f
a
b
= K f  A B 
C c D d
b
C c D d
a
b
c
d
At equilibrium, K f  A B  = K b C  D 
Kf
Kb
c
d

C  D 

Aa B b
 Kc
K c is the equilibrium constant in term of concentration,
In term of activities,
KA
 aC c a D d 

a
b ,




a
a
B
 A

The concept of activity addresses the deviation from ideal
behaviour. Therefore, it can be defined as an idealized
concentration. K A is exact and does not depend on pressure.
In term of pressure,
Kp
PCc PDd
 a b
PA PB
c
a
b
d
,
P
P
,
P
where A B
C and PD are the
partial pressure of various gaseous species at equilibrium.
Relationship between
Kp
and
Kc
In a gaseous reaction, the concentration of the gases at any
given temp is expressed in term of their partial pressures.
Consider this gaseous reaction
aA(g) + bB(g)
cC(g) + dD(g),
the equilibrium constant in term of pressure is expressed as
Kp
PCc PDd
 a b
PA PB
c
a
b
d
where PA , PB , PC and PD are the
partial pressure of various gaseous species at equilibrium.
However, K p and K c are not numerically equal, the
relationship can be derived as follow
For an ideal gases,
PV  nRT
n
 P  V RT
n
But V

=
C
P  CRT
CCc RT  CDd RT 
Kp  a
a
b
C A RT  CBb RT 
c
d
CCc CDd RT 
 a b
(a b)
CACB RT 
(c  d )
Recall that
Kc 

c
CC DD
d
a
b
AA BB
K p  K c RT 
n

 

Where n  c  d  a b i.e change in the amount of
gaseous reagents
When n is positive,
 the number of molecules of
products are larger than those of the reactants i.e K p  K c
When n is zero,  the number of molecules of products =
the number of molecules of the reactants i.e K p  K c
When n is negative,  the number of molecules of
products are smaller than those of the reactants i.e K p  K c
If the equilibrium constant is expressed in term of mole
fractions, X it is related to K p by
( X C P) c  X C P 
Kp 
b
( X A P) a  X B P 
d
 ( X ) X D  
  P cd ab 
K p   C
 ( X A ) X B  

K p  K x P n
where ∆n = c  d   a b 
Relationship between ∆G and the equilibrium constant
The change in free energy of a reaction and the equilibrium
constant K are related to each other by the expressions
G   RT ln K
Temperature dependence on the equilibrium constant
The value of equilibrium constant varies with temperature
change. The relationship between the equilibrium constants at
two different temperatures and the enthalpy change is given
by
log
K p2
K p1
H o  T2  T1 



2.303R  T 1 T2 
Where K p 2 and K p1 are the equilibrium constants at
temperature T2 and T1 respectively.
In terms of change in internal energy ( E o ), the equation
becomes
log
K p2
K p1
E o  T2  T1 



2.303R  T 1 T2 