Circular Motion Web Quest:
... 17. Does the motion of an athlete have to be a full circle to be considered circular motion? Explain. 18. For the speed skater depicted in the picture to the right, draw Free Body Diagrams showing the two components of the contact force. 19. Explain the interactions that occur between a skater and t ...
... 17. Does the motion of an athlete have to be a full circle to be considered circular motion? Explain. 18. For the speed skater depicted in the picture to the right, draw Free Body Diagrams showing the two components of the contact force. 19. Explain the interactions that occur between a skater and t ...
ForcesandMotion new
... Examples of Forces Gravitational Force (Fg) Attraction of two bodies towards each other Ground of earth is inertial reference frame Fg = mg (For relatively small distances of an object ...
... Examples of Forces Gravitational Force (Fg) Attraction of two bodies towards each other Ground of earth is inertial reference frame Fg = mg (For relatively small distances of an object ...
Rotational Motion Notes
... Inertia is measured in terms of mass. Rotational inertia is measured in terms of mass and how far that mass is located from the axis. The greater the mass or the greater the distance of that mass from the axis, the greater the rotational inertia, and therefore the greater the resistance to rotationa ...
... Inertia is measured in terms of mass. Rotational inertia is measured in terms of mass and how far that mass is located from the axis. The greater the mass or the greater the distance of that mass from the axis, the greater the rotational inertia, and therefore the greater the resistance to rotationa ...
Name
... 42. A uniform bridge span weighs 50 x 103 N and is 40.0 m long. An automobile weighing 15 x 103 N is parked with its center of gravity located 12.0 m from the right pier. What upward support force is provided by the left pier? 43. A child wants to use a 10 kg board that is 3.5 m long as a seesaw. S ...
... 42. A uniform bridge span weighs 50 x 103 N and is 40.0 m long. An automobile weighing 15 x 103 N is parked with its center of gravity located 12.0 m from the right pier. What upward support force is provided by the left pier? 43. A child wants to use a 10 kg board that is 3.5 m long as a seesaw. S ...
f F = mg X
... ❑ Equilibrium – an object which has zero acceleration, can be at rest or moving with constant velocity ...
... ❑ Equilibrium – an object which has zero acceleration, can be at rest or moving with constant velocity ...
48.5 KB - KFUPM Resources v3
... The object moves upward with constant acceleration The object has an acceleration of 10 m/s2 downward The tension in the rope is greater than the weight of the object The weight of the object is greater than the tension in the rope ...
... The object moves upward with constant acceleration The object has an acceleration of 10 m/s2 downward The tension in the rope is greater than the weight of the object The weight of the object is greater than the tension in the rope ...
Horse and Wagon
... Rancher John: Do you remember back in high school, when we took physics? Farmer Jo: Yes, I do. We were lab partners in that class. Rancher John: Ah, yes! You do remember Newton’s Three Laws, of course? Farmer Jo: Yes, I do! I remember : 1. Every object persists in its state of rest or uniform motion ...
... Rancher John: Do you remember back in high school, when we took physics? Farmer Jo: Yes, I do. We were lab partners in that class. Rancher John: Ah, yes! You do remember Newton’s Three Laws, of course? Farmer Jo: Yes, I do! I remember : 1. Every object persists in its state of rest or uniform motion ...
Chapter08b
... The Coriolis Force and the Earth The Coriolis effect is important when moving over LARGE distances (air plane travel), with large velocities, away from the equator. ...
... The Coriolis Force and the Earth The Coriolis effect is important when moving over LARGE distances (air plane travel), with large velocities, away from the equator. ...
Newton`s Laws of Motion
... In our case, the moving object is any small mass of air as it moves through the atmosphere. And because the Earth is rotating, this air will appear to be deflected by a Coriolis force, much like the example ...
... In our case, the moving object is any small mass of air as it moves through the atmosphere. And because the Earth is rotating, this air will appear to be deflected by a Coriolis force, much like the example ...
Force and Motion {PowerPoint}
... Ben Tooclose is being chased through the woods by a bull moose which he was attempting to photograph. The enormous mass of the bull moose is extremely intimidating. Yet, if Ben makes a zigzag pattern through the woods, he will be able to use the large mass of the moose to his own advantage. Explain ...
... Ben Tooclose is being chased through the woods by a bull moose which he was attempting to photograph. The enormous mass of the bull moose is extremely intimidating. Yet, if Ben makes a zigzag pattern through the woods, he will be able to use the large mass of the moose to his own advantage. Explain ...
1103 Period 6 Instructor Solutions: Gravity
... a) Write the equation for the gravitational force acting on a rock falling toward the Earth. (Hint: this is a form of Newton’s second law.) ...
... a) Write the equation for the gravitational force acting on a rock falling toward the Earth. (Hint: this is a form of Newton’s second law.) ...
Objective: Conservation of Energy I
... For a closed path, the total work done by a non-conservative force is NOT ZERO - as it is for a conservative force. For instance, a frictional force would oppose the motion and “slow” the car down. Unlike gravity, friction would do negative work on the car through out the entire trip, on both the up ...
... For a closed path, the total work done by a non-conservative force is NOT ZERO - as it is for a conservative force. For instance, a frictional force would oppose the motion and “slow” the car down. Unlike gravity, friction would do negative work on the car through out the entire trip, on both the up ...
Circular Motion
... various given speeds and radii. Calculate the A(c) and F(c) for each situation. Compare. • 1. speed = 10 m/s; radius 10 m • 2. speed = 20 m/s; radius 10 m • 3. speed = 30 m/s; radius 10 m • 4. speed = 10 m/s; radius 20 m • 5. speed = 10 m/s; radius 30 m ...
... various given speeds and radii. Calculate the A(c) and F(c) for each situation. Compare. • 1. speed = 10 m/s; radius 10 m • 2. speed = 20 m/s; radius 10 m • 3. speed = 30 m/s; radius 10 m • 4. speed = 10 m/s; radius 20 m • 5. speed = 10 m/s; radius 30 m ...
inelastic collision
... Ex. 2 - During a storm, rain comes straight down with a velocity of v0 = -15 m/s and hits the roof of a car perpendicularly. the mass of the rain per second that strikes the roof of the car is 0.060 kg/s. Assuming that the rain comes to rest upon striking the car roof, find the average force exerte ...
... Ex. 2 - During a storm, rain comes straight down with a velocity of v0 = -15 m/s and hits the roof of a car perpendicularly. the mass of the rain per second that strikes the roof of the car is 0.060 kg/s. Assuming that the rain comes to rest upon striking the car roof, find the average force exerte ...
Physics Words
... b) So, add 50 grams to the hanger, making the total hanging mass 100grams. The force of gravity pulling on the system will be 1 newton. ...
... b) So, add 50 grams to the hanger, making the total hanging mass 100grams. The force of gravity pulling on the system will be 1 newton. ...
Numerical Integration of Newton`s Second Law of Motion
... the time periods are short enough to give you an approximate answer close enough to the right answer. Note that all the equations given so far are vector equations. That means that they are really three equations in one (one for each dimension – x, y, and z). For the problems we will consider, the p ...
... the time periods are short enough to give you an approximate answer close enough to the right answer. Note that all the equations given so far are vector equations. That means that they are really three equations in one (one for each dimension – x, y, and z). For the problems we will consider, the p ...
Final Review
... spring scale at the bottom of the swing (more, less or same as when the object is at rest). ...
... spring scale at the bottom of the swing (more, less or same as when the object is at rest). ...
