Mass on a plane with friction
... Elevator accelerating upwards Since the net force is 100 N, the upward force (of the scale) and downward force (of the weight) must equal a 100 N upward force. Fnet = F scale – W 100 N = F scale - (50 kg)(9.8 m/s2) F scale = 600 N Therefore, the scale will read 600 N Note that this is a heavier rea ...
... Elevator accelerating upwards Since the net force is 100 N, the upward force (of the scale) and downward force (of the weight) must equal a 100 N upward force. Fnet = F scale – W 100 N = F scale - (50 kg)(9.8 m/s2) F scale = 600 N Therefore, the scale will read 600 N Note that this is a heavier rea ...
Physics 20 Concept 20 Uniform Circular Motion I. Acceleration
... If the centripetal force is removed (i.e. the string is cut), the ball will continue to move at a constant velocity in a direction tangent to the point where the force was removed. ...
... If the centripetal force is removed (i.e. the string is cut), the ball will continue to move at a constant velocity in a direction tangent to the point where the force was removed. ...
There are 2 types of acceleration
... If you are only changing the direction you are going and maintain a constant speed: You are in Uniform Circular Motion (UCM for short). Things to remember about UCM: UCM is circular motion at a constant speed. The only acceleration there is will be centripetal acceleration. The centripetal acc ...
... If you are only changing the direction you are going and maintain a constant speed: You are in Uniform Circular Motion (UCM for short). Things to remember about UCM: UCM is circular motion at a constant speed. The only acceleration there is will be centripetal acceleration. The centripetal acc ...
1 Chapter 5: Work and Energy (pages 159 182) Dat
... Potential energy is associated with an object that has the potential to move because of its position relative to some other location. ...
... Potential energy is associated with an object that has the potential to move because of its position relative to some other location. ...
1 Review Part 1 units n
... Ex. 2 - Conservation of Energy Problem • A tall volcano fills its neck with magma to an elevation of h1 = 1000 m above a weak area. The pressure forms a rupture in the weak area. Define the height there as h2 = 0 meters. • How fast is the lateral blast? • The rupture has area A2 = 10000 m2 , small ...
... Ex. 2 - Conservation of Energy Problem • A tall volcano fills its neck with magma to an elevation of h1 = 1000 m above a weak area. The pressure forms a rupture in the weak area. Define the height there as h2 = 0 meters. • How fast is the lateral blast? • The rupture has area A2 = 10000 m2 , small ...
No Slide Title
... So far, we used: PEgravity=mgh Only valid for h near earth’s surface. More general: PEgravity=-GMEarthm/r PE=0 at infinity distance from the center of the earth See example 7.12 for consistency between these two. Example: escape speed: what should the minimum initial velocity of a rocket be if we wa ...
... So far, we used: PEgravity=mgh Only valid for h near earth’s surface. More general: PEgravity=-GMEarthm/r PE=0 at infinity distance from the center of the earth See example 7.12 for consistency between these two. Example: escape speed: what should the minimum initial velocity of a rocket be if we wa ...
UNIT 10 Lab - TTU Physics
... velocity for each cart. Compare the quantity mv f - mv i for each cart, where m is the mass, vf is the final velocity, and vi is the initial velocity of the cart. c. Two objects are each accelerated by the same constant force for the same time t. Using Newton’s Second Law and kinematics, solve for ...
... velocity for each cart. Compare the quantity mv f - mv i for each cart, where m is the mass, vf is the final velocity, and vi is the initial velocity of the cart. c. Two objects are each accelerated by the same constant force for the same time t. Using Newton’s Second Law and kinematics, solve for ...
Science and the Road
... A car skidded 12.6 m before hitting a parked van on its side. The two vehicles became locked together and skidded a distance of 3.6 m before coming to a stop. The coefficient of tyre/road friction was found to be 0.71. Total mass of the car and its passengers was 1,260 kg and total mass of the van a ...
... A car skidded 12.6 m before hitting a parked van on its side. The two vehicles became locked together and skidded a distance of 3.6 m before coming to a stop. The coefficient of tyre/road friction was found to be 0.71. Total mass of the car and its passengers was 1,260 kg and total mass of the van a ...
Unit C2: Scheme of Work
... (c) Tension: Tie a string to the book: pull it and the book moves. Explain the change in motion via tension in the string. Strings can never push, and must be taut to pull. N3L: “if A exerts a force on B, B exerts an equal force in the opposite direction on A”. For the book on the table, consider th ...
... (c) Tension: Tie a string to the book: pull it and the book moves. Explain the change in motion via tension in the string. Strings can never push, and must be taut to pull. N3L: “if A exerts a force on B, B exerts an equal force in the opposite direction on A”. For the book on the table, consider th ...
