Slides
... 4 s to give velocity v = aT. In the second case, the force is half, therefore the acceleration is also half, so to achieve the same final speed, the time must be doubled. ...
... 4 s to give velocity v = aT. In the second case, the force is half, therefore the acceleration is also half, so to achieve the same final speed, the time must be doubled. ...
solution
... A small coin of mass M is just inside the edge of a rotating horizontal circular stage of radius R as illustrated below. The coefficient of static friction between the coin and the stage floor is µs. ...
... A small coin of mass M is just inside the edge of a rotating horizontal circular stage of radius R as illustrated below. The coefficient of static friction between the coin and the stage floor is µs. ...
Achievement - Waimea Physics
... If you need more space for any answer, use the pages provided at the back of this booklet and clearly number the question. For all numerical answers, full working should be shown and the answer should be rounded to the correct number of significant figures and given with an SI unit. For all ‘describ ...
... If you need more space for any answer, use the pages provided at the back of this booklet and clearly number the question. For all numerical answers, full working should be shown and the answer should be rounded to the correct number of significant figures and given with an SI unit. For all ‘describ ...
momentum is conserved
... A 2.0 kg ball, A, is moving at a velocity of 5.0 m/s. It collides with a stationary ball, B, also of mass 2.0 kg. After the collision, ball A moves off in a direction 300 to the left of its original direction. Ball B moves off in a direction 900 to the right of ball A’s final direction. a. Draw a v ...
... A 2.0 kg ball, A, is moving at a velocity of 5.0 m/s. It collides with a stationary ball, B, also of mass 2.0 kg. After the collision, ball A moves off in a direction 300 to the left of its original direction. Ball B moves off in a direction 900 to the right of ball A’s final direction. a. Draw a v ...
m - Cloudfront.net
... A box sliding on a horizontal frictionless surface runs into a fixed spring, compressing it a distance x1 from its relaxed position while momentarily coming to rest. If the initial speed of the box were doubled and its mass were halved, how far x2 would the spring compress ? ...
... A box sliding on a horizontal frictionless surface runs into a fixed spring, compressing it a distance x1 from its relaxed position while momentarily coming to rest. If the initial speed of the box were doubled and its mass were halved, how far x2 would the spring compress ? ...
MOMENTUM ! - Urbana School District #116
... Why does a spinning ice skater speed up when she pulls her arms in? Suppose Mr. Stickman is sitting on a stool that swivels holding a pair of dumbbells. His axis of rotation is vertical. With the weights far from that axis, his moment of inertia is large. When he pulls his arms in as he’s spinning, ...
... Why does a spinning ice skater speed up when she pulls her arms in? Suppose Mr. Stickman is sitting on a stool that swivels holding a pair of dumbbells. His axis of rotation is vertical. With the weights far from that axis, his moment of inertia is large. When he pulls his arms in as he’s spinning, ...
Slide 1
... This is a demonstration of Inertia where a washer can be removed from a stack if the blow is fast. Why does it ...
... This is a demonstration of Inertia where a washer can be removed from a stack if the blow is fast. Why does it ...
MOMENTUM!
... Why does a spinning ice skater speed up when she pulls her arms in? Suppose Mr. Stickman is sitting on a stool that swivels holding a pair of dumbbells. His axis of rotation is vertical. With the weights far from that axis, his moment of inertia is large. When he pulls his arms in as he’s spinning, ...
... Why does a spinning ice skater speed up when she pulls her arms in? Suppose Mr. Stickman is sitting on a stool that swivels holding a pair of dumbbells. His axis of rotation is vertical. With the weights far from that axis, his moment of inertia is large. When he pulls his arms in as he’s spinning, ...
28 Aug 2006 (First Class)
... Gravitation near the Earth’s surface. Assume a mass m. Then F=GMEm/r2 where r is really just the Earth’s radius RE. Therefore g=GME/RE2. Mention Cavendish experiment. Variation with altitude? Sure. Remind them that (1+x)n=1+nx when x is very small. We will use this in a little while (today) after we ...
... Gravitation near the Earth’s surface. Assume a mass m. Then F=GMEm/r2 where r is really just the Earth’s radius RE. Therefore g=GME/RE2. Mention Cavendish experiment. Variation with altitude? Sure. Remind them that (1+x)n=1+nx when x is very small. We will use this in a little while (today) after we ...
Conceptual Rotational Inertia and Angular Momentum notes
... Newton’s first law, the law of inertia, applies to rotating objects. • An object rotating about an internal axis tends to keep rotating about that axis. • Rotating objects tend to keep rotating, while nonrotating objects tend to remain non-rotating. • The resistance of an object to changes in its ro ...
... Newton’s first law, the law of inertia, applies to rotating objects. • An object rotating about an internal axis tends to keep rotating about that axis. • Rotating objects tend to keep rotating, while nonrotating objects tend to remain non-rotating. • The resistance of an object to changes in its ro ...
N - Purdue Physics
... This is a demonstration of Inertia where a washer can be removed from a stack if the blow is fast. Why does it ...
... This is a demonstration of Inertia where a washer can be removed from a stack if the blow is fast. Why does it ...
Exam Review Answer Key 1) Force of Friction = 50N
... a. False - An object which is moving to the right could have unbalanced forces, but only if it is accelerating. The presence of unbalanced forces must always be associated with acceleration, not mere motion. In this case, an object moving to the right could have a balance of forces if it is moving w ...
... a. False - An object which is moving to the right could have unbalanced forces, but only if it is accelerating. The presence of unbalanced forces must always be associated with acceleration, not mere motion. In this case, an object moving to the right could have a balance of forces if it is moving w ...
Dr. Naumoff - AP Physics 1– chapter 6 Setup practice problems 1
... The car’s velocity is v and µs is the coefficient of static friction between the track and the tires. a. Draw a free body diagram for the car. b. Derive the expression for the maximum velocity that the car can attain before it begins to skid. c. What is supplying the centripetal force? 7. A car is g ...
... The car’s velocity is v and µs is the coefficient of static friction between the track and the tires. a. Draw a free body diagram for the car. b. Derive the expression for the maximum velocity that the car can attain before it begins to skid. c. What is supplying the centripetal force? 7. A car is g ...