 
									
								
									Newton
									
... 10. A player catches a ball. Consider the action force to be the impact of the ball against the player’s glove. What is the reaction to this force? a) the player’s grip on the glove d) the muscular effort in the player’s arms b) the force the glove exerts on the ball e) None of these answers are cor ...
                        	... 10. A player catches a ball. Consider the action force to be the impact of the ball against the player’s glove. What is the reaction to this force? a) the player’s grip on the glove d) the muscular effort in the player’s arms b) the force the glove exerts on the ball e) None of these answers are cor ...
									1 - Moodle
									
... rightward acceleration of 2 m/s2. The force of friction between the object and the surface is 5 N. Use the diagram to determine the gravitational force, normal force, applied force, frictional force, and net force. (Neglect air resistance.) ...
                        	... rightward acceleration of 2 m/s2. The force of friction between the object and the surface is 5 N. Use the diagram to determine the gravitational force, normal force, applied force, frictional force, and net force. (Neglect air resistance.) ...
									PPT
									
... A point on an object, located a distance r from a fixed axis of rotation, rotates in such a way that it travels a distance d along the circumference of a circle. The ratio of d to r is defined to be the angle q measured in radians. θ = d / r and will be referred to as the angular displacement ...
                        	... A point on an object, located a distance r from a fixed axis of rotation, rotates in such a way that it travels a distance d along the circumference of a circle. The ratio of d to r is defined to be the angle q measured in radians. θ = d / r and will be referred to as the angular displacement ...
									Newton`s Laws of Motion
									
... would continue in motion with the same speed and direction - forever! (Or at least to the end of the table top.) ...
                        	... would continue in motion with the same speed and direction - forever! (Or at least to the end of the table top.) ...
									9/7/2006 ISP 209 - 2B - MSU Physics and Astronomy Department
									
... proportional to the displacement (extension or compression). F = k x where k is called Hooke’s constant for the spring. ...
                        	... proportional to the displacement (extension or compression). F = k x where k is called Hooke’s constant for the spring. ...
									PHYS101 - Concord University
									
... spheres. The key is to consider the ratios of forces and distances. Gravity is an inverse-square relationship; the force is related to the inverse square of the distance. The force increases by a factor of (0.160 N)/(0.010 N) = 16, so the distance must decrease by a factor of = 4. The ...
                        	... spheres. The key is to consider the ratios of forces and distances. Gravity is an inverse-square relationship; the force is related to the inverse square of the distance. The force increases by a factor of (0.160 N)/(0.010 N) = 16, so the distance must decrease by a factor of = 4. The ...
									Name _____Answer Key____ 1. force ____Any push or pull that
									
... 1. The moving parts of an automobile engine are coated in oil or grease to reduce the __friction__ between the metal parts. 2. Some toys let you draw hair, eyebrows, and other features with a special wand that moves iron filings around by ____magnetism______. 3. A balance scale works by using ______ ...
                        	... 1. The moving parts of an automobile engine are coated in oil or grease to reduce the __friction__ between the metal parts. 2. Some toys let you draw hair, eyebrows, and other features with a special wand that moves iron filings around by ____magnetism______. 3. A balance scale works by using ______ ...
									force-problems-with-acceleration-2-step
									
... 5. A 50 kg skater pushed by a friend accelerates 5 m/sec2. How much force did the friend apply? F = ma f= 50 x 5 f= 250 N How fast was she going after 1.2 seconds? 6 m/s 6. A force of 250 N is applied to an object that accelerates at a rate of 5 m/sec2. What is the mass of the object? F = ma 250N=(m ...
                        	... 5. A 50 kg skater pushed by a friend accelerates 5 m/sec2. How much force did the friend apply? F = ma f= 50 x 5 f= 250 N How fast was she going after 1.2 seconds? 6 m/s 6. A force of 250 N is applied to an object that accelerates at a rate of 5 m/sec2. What is the mass of the object? F = ma 250N=(m ...
									Physics 20 Dynamics – Day 15: Inclined Planes - ND
									
... Be able to draw a free-body diagram of an object on an incline plane and determine the relevant forces. In the free body diagram (FBD), all of the ______________ acting on a body are shown (but none of their __________________ and no forces acting on other bodies). When drawing the vectors represent ...
                        	... Be able to draw a free-body diagram of an object on an incline plane and determine the relevant forces. In the free body diagram (FBD), all of the ______________ acting on a body are shown (but none of their __________________ and no forces acting on other bodies). When drawing the vectors represent ...
 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									