
Exam 1 Review
... (hint – use the balanced chemical equation to solve) Find heat needed to change water at 20 °C to steam at 100 °C. Does entropy increase or decrease for a given reaction? When is a reaction spontaneous? Is positive or negative entropy more favorable? What do exothermic and endothermic mean? What doe ...
... (hint – use the balanced chemical equation to solve) Find heat needed to change water at 20 °C to steam at 100 °C. Does entropy increase or decrease for a given reaction? When is a reaction spontaneous? Is positive or negative entropy more favorable? What do exothermic and endothermic mean? What doe ...
Notes matter energy
... Atoms are mostly empty space. Protons and neutrons are located in a dense nucleus. Electrons occupy the space around the nucleus. The number electrons is equal to number of protons for neutral elements. Protons have a +1 electrical charge. Neutrons have no electrical charge. Electrons have a -1 elec ...
... Atoms are mostly empty space. Protons and neutrons are located in a dense nucleus. Electrons occupy the space around the nucleus. The number electrons is equal to number of protons for neutral elements. Protons have a +1 electrical charge. Neutrons have no electrical charge. Electrons have a -1 elec ...
Photocatalytic reduction of aromatic azides to amines using CdS
... accept a second electron to give a doubly charged species. However, a rapid loss of a N2 to generate a nitrene radical anion (C) is more likely.29 Nitrene radical anion C may subsequently be protonated to give an aminyl radical (D) or abstract a hydrogen to form the amide anion E. Given that quantum ...
... accept a second electron to give a doubly charged species. However, a rapid loss of a N2 to generate a nitrene radical anion (C) is more likely.29 Nitrene radical anion C may subsequently be protonated to give an aminyl radical (D) or abstract a hydrogen to form the amide anion E. Given that quantum ...
File
... Properties and Changes of Matter: 1. Physical Property: characteristics of matter, used to identify substances eg. state at room temperature, boiling and melting points, color, solubility, mass, electrical conductivity 2. Physical Change: a change in the size or form of a substance that does not cha ...
... Properties and Changes of Matter: 1. Physical Property: characteristics of matter, used to identify substances eg. state at room temperature, boiling and melting points, color, solubility, mass, electrical conductivity 2. Physical Change: a change in the size or form of a substance that does not cha ...
Stoichiometry of Chemical Reactions
... The preceding chapter introduced the use of element symbols to represent individual atoms. When atoms gain or lose electrons to yield ions, or combine with other atoms to form molecules, their symbols are modified or combined to generate chemical formulas that appropriately represent these species. ...
... The preceding chapter introduced the use of element symbols to represent individual atoms. When atoms gain or lose electrons to yield ions, or combine with other atoms to form molecules, their symbols are modified or combined to generate chemical formulas that appropriately represent these species. ...
Stoichiometry of Chemical Reactions
... The preceding chapter introduced the use of element symbols to represent individual atoms. When atoms gain or lose electrons to yield ions, or combine with other atoms to form molecules, their symbols are modified or combined to generate chemical formulas that appropriately represent these species. ...
... The preceding chapter introduced the use of element symbols to represent individual atoms. When atoms gain or lose electrons to yield ions, or combine with other atoms to form molecules, their symbols are modified or combined to generate chemical formulas that appropriately represent these species. ...
problems - chem.msu.su
... 3. What factors affect the solubility of K3[Co(NO2)6] in the mother solution after precipitate formation? Choose the right answers: a) stability constant of complex ion [Co(NO2)6]3–; b) solubility product of the precipitate; c) concentration of K+; d) concentration of Co(II); e) concentration of NO2 ...
... 3. What factors affect the solubility of K3[Co(NO2)6] in the mother solution after precipitate formation? Choose the right answers: a) stability constant of complex ion [Co(NO2)6]3–; b) solubility product of the precipitate; c) concentration of K+; d) concentration of Co(II); e) concentration of NO2 ...
PHYSICAL SETTING CHEMISTRY
... The possession or use of any communications device is strictly prohibited when taking this examination. If you have or use any communications device, no matter how briefly, your examination will be invalidated and no score will be calculated for you. This is a test of your knowledge of chemistry. Us ...
... The possession or use of any communications device is strictly prohibited when taking this examination. If you have or use any communications device, no matter how briefly, your examination will be invalidated and no score will be calculated for you. This is a test of your knowledge of chemistry. Us ...
3. Chemical changes and Structure Unit Questions
... 24. (a) Atoms of different elements have different attractions for bonded electrons. What term is used as a measure of the attraction an atom involved in a bond has for the electrons of the bond? (1) (b) Atoms of different elements are different sizes. What is the trend in atomic size across the per ...
... 24. (a) Atoms of different elements have different attractions for bonded electrons. What term is used as a measure of the attraction an atom involved in a bond has for the electrons of the bond? (1) (b) Atoms of different elements are different sizes. What is the trend in atomic size across the per ...
unit_k_reading_notes
... already seen—it’s composition stoichiometry, which is the study of mass relationships of elements in compounds. Examples of this include calculating percentage composition, and determination of empirical and molecular formulas. The second one is reaction stoichiometry, which deals with the mass, mol ...
... already seen—it’s composition stoichiometry, which is the study of mass relationships of elements in compounds. Examples of this include calculating percentage composition, and determination of empirical and molecular formulas. The second one is reaction stoichiometry, which deals with the mass, mol ...
Chapter 3
... produced if there is enough oxygen gas to react with all of the CO. A) 7.20 mol B) 44.0 mol C) 3.60 mol D) 1.80 mol Nitrous oxide (N2O) is also called “laughing gas.” It can be prepared by the thermal decomposition of ammonium nitrate (NH4NO3). The other product is H2O. The balanced equation for thi ...
... produced if there is enough oxygen gas to react with all of the CO. A) 7.20 mol B) 44.0 mol C) 3.60 mol D) 1.80 mol Nitrous oxide (N2O) is also called “laughing gas.” It can be prepared by the thermal decomposition of ammonium nitrate (NH4NO3). The other product is H2O. The balanced equation for thi ...
Intro to Titrimetry
... Ex: Volhard Methods and Fajans Method RedOx Titrations – involves species which undergo redox reactions. The reaction is monitored by RedOx indicators or thru Electrochemical methods. Ex: 2 MnO4- + 5 C2O42- + 16 H+ 2 Mn2+ + 10 CO2 + 8 H2O Complexometric Titrations – reactions involving chelating/c ...
... Ex: Volhard Methods and Fajans Method RedOx Titrations – involves species which undergo redox reactions. The reaction is monitored by RedOx indicators or thru Electrochemical methods. Ex: 2 MnO4- + 5 C2O42- + 16 H+ 2 Mn2+ + 10 CO2 + 8 H2O Complexometric Titrations – reactions involving chelating/c ...
Equilibrium Review worksheet
... 10. A 0.10 mol/L solution of the essential amino acid tryptophan has a measured pH of 5.19 at 25 °C. Predict the percent ionization of this tryptophan solution, and the Ka value for aqueous tryptophan. The molecular formula for tryptophan may be written as C 10H11N2COOH. ...
... 10. A 0.10 mol/L solution of the essential amino acid tryptophan has a measured pH of 5.19 at 25 °C. Predict the percent ionization of this tryptophan solution, and the Ka value for aqueous tryptophan. The molecular formula for tryptophan may be written as C 10H11N2COOH. ...
Unit 1 Review, pages 138–145
... 33. The contribution to the periodic table made by Dobereiner was his early attempt to classify small groups of elements according to their properties. 34. If an atom has high ionization energy, its electron affinity is also high. 35. (a) An electrolyte is a compound that conducts an electric curren ...
... 33. The contribution to the periodic table made by Dobereiner was his early attempt to classify small groups of elements according to their properties. 34. If an atom has high ionization energy, its electron affinity is also high. 35. (a) An electrolyte is a compound that conducts an electric curren ...
chemistry — released form
... Alternatively, realize that the substance in the diagram is a solid to begin with. This fact is not stated in the problem, but it should have been. Anyway, Once 100 kJ of heat is added, the substance is still a solid but is at its melting point (10°C). Once a total of 150 kJ has been added, th ...
... Alternatively, realize that the substance in the diagram is a solid to begin with. This fact is not stated in the problem, but it should have been. Anyway, Once 100 kJ of heat is added, the substance is still a solid but is at its melting point (10°C). Once a total of 150 kJ has been added, th ...
H2O - WCCUSD.net
... year, or less if it’s opened. The yeast in our demonstration acts as a catalyst to speed up this reaction. And higher concentrations of H2O2 produce more oxygen. ...
... year, or less if it’s opened. The yeast in our demonstration acts as a catalyst to speed up this reaction. And higher concentrations of H2O2 produce more oxygen. ...
Covalent Bonding - whitburnscience
... In ionic bonding one atom, the one with the greater electronegativity removes the electron from another atom with a smaller electronegativity. Both end up with noble gas electron arrangement in the outer shell. A chlorine atom with an electron configuration 2)8)7 will try to pick up an electron to g ...
... In ionic bonding one atom, the one with the greater electronegativity removes the electron from another atom with a smaller electronegativity. Both end up with noble gas electron arrangement in the outer shell. A chlorine atom with an electron configuration 2)8)7 will try to pick up an electron to g ...
Are You suprised ?
... The correct arrangement of heat of vaporization of the following compounds is: A) C10H22 > C2H6 > CH4 > C3H8. B) CH4 > C2H6 > C3H8 > C10H22. C) C10H22 > C3H8 > C2H6 > CH4. D) C10H22 > CH4 > C3H8 > C2H6. ...
... The correct arrangement of heat of vaporization of the following compounds is: A) C10H22 > C2H6 > CH4 > C3H8. B) CH4 > C2H6 > C3H8 > C10H22. C) C10H22 > C3H8 > C2H6 > CH4. D) C10H22 > CH4 > C3H8 > C2H6. ...
2014-15 FINAL REVIEW Nomenclature: Chemical Name Chemical
... 1. Using the following equation: 2 NaOH + H2SO4 2 H2O + Na2SO4 How many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid (H2SO4)? 2. Using the following equation: Pb(SO4)2 + 4 LiNO3 Pb(NO3)4 + 2 Li2SO4 How many grams o ...
... 1. Using the following equation: 2 NaOH + H2SO4 2 H2O + Na2SO4 How many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid (H2SO4)? 2. Using the following equation: Pb(SO4)2 + 4 LiNO3 Pb(NO3)4 + 2 Li2SO4 How many grams o ...
Types of Chemical Reactions
... Note two oxygen atoms on the reactant side and only one on the product side, therefore place a two in front of water The two now doubles everything in water, thus 4 hydrogen and 2 oxygen. Now place a 2 in front of hydrogen. ...
... Note two oxygen atoms on the reactant side and only one on the product side, therefore place a two in front of water The two now doubles everything in water, thus 4 hydrogen and 2 oxygen. Now place a 2 in front of hydrogen. ...
Chapter 12 Packet
... much sodium azide is needed to create this volume of nitrogen gas. Remember, this reaction does not occur under STP conditions so you must use the density of N2 which is 0.916 g/L. ...
... much sodium azide is needed to create this volume of nitrogen gas. Remember, this reaction does not occur under STP conditions so you must use the density of N2 which is 0.916 g/L. ...
Chemistry Final Exam Review 2006-2007
... a. Calculate the heat absorbed when 15.0 g of ice melts to liquid. See reference sheet for Hfus b. Calculate the heat released when 75.4 g of vapor condenses into liquid. See reference sheet for Hvap 10. Know how to calculate the heat released or absorbed in a chemical reaction? a) What is the spe ...
... a. Calculate the heat absorbed when 15.0 g of ice melts to liquid. See reference sheet for Hfus b. Calculate the heat released when 75.4 g of vapor condenses into liquid. See reference sheet for Hvap 10. Know how to calculate the heat released or absorbed in a chemical reaction? a) What is the spe ...
Name: Period:______ PHYSICAL SCIENCE 1st Semester Final
... Explain why the covalent bonds of elements are always nonpolar Explain why the covalent bonds of compounds are polar (example: H2O) Determine what type of bond a molecule/compound will form (or not form) based on its properties-Examples: oxygen + oxygen (nonpolar covalent), chlorine + sodium (ionic) ...
... Explain why the covalent bonds of elements are always nonpolar Explain why the covalent bonds of compounds are polar (example: H2O) Determine what type of bond a molecule/compound will form (or not form) based on its properties-Examples: oxygen + oxygen (nonpolar covalent), chlorine + sodium (ionic) ...
topic 3: periodicity
... they reduce water to hydrogen and hydroxide forming an alkali solution which is why they are called alkali metals: (observations: the metals move around and fizz). Also a gas is produced. 2Na (s) + 2H2O (l) 2NaOH (aq) + H2 (g) they readily react with air producing distinctly coloured flames a ...
... they reduce water to hydrogen and hydroxide forming an alkali solution which is why they are called alkali metals: (observations: the metals move around and fizz). Also a gas is produced. 2Na (s) + 2H2O (l) 2NaOH (aq) + H2 (g) they readily react with air producing distinctly coloured flames a ...
1412e3 - studylib.net
... PART II (8 points each) Please show all your work. 21. Balance the following equation in basic solution and determine the oxidizing and reducing agent. Zn + MnO4 Zn(OH)2 + MnO2 22. How many minutes will it take to plate out 5.00 g of Fe from an Fe(NO 3)3 solution by a current of 1.50 A? (atomic wei ...
... PART II (8 points each) Please show all your work. 21. Balance the following equation in basic solution and determine the oxidizing and reducing agent. Zn + MnO4 Zn(OH)2 + MnO2 22. How many minutes will it take to plate out 5.00 g of Fe from an Fe(NO 3)3 solution by a current of 1.50 A? (atomic wei ...
Redox

Redox reactions include all chemical reactions in which atoms have their oxidation state changed; in general, redox reactions involve the transfer of electrons between species. The term ""redox"" comes from two concepts involved with electron transfer: reduction and oxidation. It can be explained in simple terms: Oxidation is the loss of electrons or an increase in oxidation state by a molecule, atom, or ion. Reduction is the gain of electrons or a decrease in oxidation state by a molecule, atom, or ion.Although oxidation reactions are commonly associated with the formation of oxides from oxygen molecules, these are only specific examples of a more general concept of reactions involving electron transfer.Redox reactions, or oxidation-reduction reactions, have a number of similarities to acid–base reactions. Like acid–base reactions, redox reactions are a matched set, that is, there cannot be an oxidation reaction without a reduction reaction happening simultaneously. The oxidation alone and the reduction alone are each called a half-reaction, because two half-reactions always occur together to form a whole reaction. When writing half-reactions, the gained or lost electrons are typically included explicitly in order that the half-reaction be balanced with respect to electric charge.Though sufficient for many purposes, these descriptions are not precisely correct. Oxidation and reduction properly refer to a change in oxidation state — the actual transfer of electrons may never occur. The oxidation state of an atom is the fictitious charge that an atom would have if all bonds between atoms of different elements were 100% ionic. Thus, oxidation is better defined as an increase in oxidation state, and reduction as a decrease in oxidation state. In practice, the transfer of electrons will always cause a change in oxidation state, but there are many reactions that are classed as ""redox"" even though no electron transfer occurs (such as those involving covalent bonds).There are simple redox processes, such as the oxidation of carbon to yield carbon dioxide (CO2) or the reduction of carbon by hydrogen to yield methane (CH4), and more complex processes such as the oxidation of glucose (C6H12O6) in the human body through a series of complex electron transfer processes.