Liquid-phase hydrodechlorination of chlorobenzene by molecular
... HDCl of chlorobenzene in two-phase aqueous–organic solvent system was carried out in a glass temperature-controlled reactor equipped with a magnetic stirrer and a condenser. Reduced catalyst (95.7 mg) was placed in the reactor, mixed with aqueous 50 % KOH (4 ml), and activated at 50 °C for 1 h with ...
... HDCl of chlorobenzene in two-phase aqueous–organic solvent system was carried out in a glass temperature-controlled reactor equipped with a magnetic stirrer and a condenser. Reduced catalyst (95.7 mg) was placed in the reactor, mixed with aqueous 50 % KOH (4 ml), and activated at 50 °C for 1 h with ...
Ionic Equations and State Symbols
... Compounds written as Whole molecules and not individual ions oare: 1. Solids or non-soluble precipitates which result from mixing previously aqueous ions are written with their molecular formula and not as seperate ions e.g Ag+(aq) + NO3 2- (aq) + Cl- (aq) ...
... Compounds written as Whole molecules and not individual ions oare: 1. Solids or non-soluble precipitates which result from mixing previously aqueous ions are written with their molecular formula and not as seperate ions e.g Ag+(aq) + NO3 2- (aq) + Cl- (aq) ...
Exam 2
... Which one of the following would be predicted to spontaneously oxidise aqueous iodide ions but not aqueous chloride ions? A. Au+(aq) B. Sn2+(aq) C. Fe2+(aq) D. Br2(aq) ...
... Which one of the following would be predicted to spontaneously oxidise aqueous iodide ions but not aqueous chloride ions? A. Au+(aq) B. Sn2+(aq) C. Fe2+(aq) D. Br2(aq) ...
Chapter 5: thermochemstry
... Measuring ΔH Using a Coffee-Cup Calorimeter A student mixes 50 mL of 1.0 M HCl and 50 mL of 1.0 M NaOH in a coffee-cup calorimeter . The temperature of the solution increases from 21.0 C to 27.5 C. Calculate the ΔH for the reaction in kJ/mol HCl, assuming: the calorimeter loses only a negligible qua ...
... Measuring ΔH Using a Coffee-Cup Calorimeter A student mixes 50 mL of 1.0 M HCl and 50 mL of 1.0 M NaOH in a coffee-cup calorimeter . The temperature of the solution increases from 21.0 C to 27.5 C. Calculate the ΔH for the reaction in kJ/mol HCl, assuming: the calorimeter loses only a negligible qua ...
Balancing Redox Reactions 1 - VCC Library
... In a redox reaction, the substance that gets oxidized (that loses electrons) is called the reducing agent because it reduces the other substance by giving its electrons. The substance that gets reduced (that gains electrons) is called the oxidizing agent because it oxidizes the other substance by re ...
... In a redox reaction, the substance that gets oxidized (that loses electrons) is called the reducing agent because it reduces the other substance by giving its electrons. The substance that gets reduced (that gains electrons) is called the oxidizing agent because it oxidizes the other substance by re ...
CHEM 115 EXAM #1 - chem.wilkes.edu
... A compound is a chemical combination of two or more elements in a fixed ratio (ex. include NaCl, H2O, CuSO4 and many, many more) . A homogenous mixture is a physical combination of two or more substances (which can be either elements or compounds) that can be made in varying ratios (ex. include clea ...
... A compound is a chemical combination of two or more elements in a fixed ratio (ex. include NaCl, H2O, CuSO4 and many, many more) . A homogenous mixture is a physical combination of two or more substances (which can be either elements or compounds) that can be made in varying ratios (ex. include clea ...
energy changes in physical and chemical processes
... ∆HØ (neutr) = -51.4kJ mol-1 Similarly if ethanoic acid (weak acid) is neutralized by sodium hydroxide (strong base) only 55.2kJ of heat is produced for every mole of water formed. CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l), ∆H (neutr) = - 55.2kJmol-1 The weak acids, such as ethanoic acid or weak ...
... ∆HØ (neutr) = -51.4kJ mol-1 Similarly if ethanoic acid (weak acid) is neutralized by sodium hydroxide (strong base) only 55.2kJ of heat is produced for every mole of water formed. CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l), ∆H (neutr) = - 55.2kJmol-1 The weak acids, such as ethanoic acid or weak ...
Chapter 8 Section 1 Describing Chemical Reactions
... Sample Problem E Solution 1. Identify the reactants. Magnesium will attempt to displace lead from lead(II) nitrate. 2. Check the activity series. Magnesium is more active than lead and displaces it. 3. Write the balanced equation. Mg + Pb(NO3)2 Pb + Mg(NO3)2 Double-Displacement Reactions • In a do ...
... Sample Problem E Solution 1. Identify the reactants. Magnesium will attempt to displace lead from lead(II) nitrate. 2. Check the activity series. Magnesium is more active than lead and displaces it. 3. Write the balanced equation. Mg + Pb(NO3)2 Pb + Mg(NO3)2 Double-Displacement Reactions • In a do ...
one
... • Step 2 – change one or more coefficients until the equation is balanced. – Start by balancing an element that appears in only one reactant and product. – Once one element is balanced, proceed to balance another, and another, until all elements are balanced. – Balance chemical formulas by placing c ...
... • Step 2 – change one or more coefficients until the equation is balanced. – Start by balancing an element that appears in only one reactant and product. – Once one element is balanced, proceed to balance another, and another, until all elements are balanced. – Balance chemical formulas by placing c ...
Word Equations • a summary
... Use molecular building kits to look at the reaction of: Methane + CH4 ...
... Use molecular building kits to look at the reaction of: Methane + CH4 ...
Class_X–Science__term_I
... iii) Reaction with Non -metallic oxides – These oxides are generally acidic in nature. They react with bases to form salt and water. 2NaOH + CO2 Na2CO3 + H2O 7) pH Scale: The concentration of hydrogen ion in solution is expressed in terms of pH. The pH of a solution is defined as the negative logar ...
... iii) Reaction with Non -metallic oxides – These oxides are generally acidic in nature. They react with bases to form salt and water. 2NaOH + CO2 Na2CO3 + H2O 7) pH Scale: The concentration of hydrogen ion in solution is expressed in terms of pH. The pH of a solution is defined as the negative logar ...
Gas Laws
... 12. Calculate the pH, pOH, and [H+1] of a solution in which the [OH-1] = 2.34 x 10-5. Calculate each significantly! pH = 9.369, pOH = 4.631, [H+1] = 4.27 x 10-10 M 13. Calculate the pH of a 0.10 M solution of Ca(OH)2. pH = 13.3 14. Using the following Ka values, place the following acids in order of ...
... 12. Calculate the pH, pOH, and [H+1] of a solution in which the [OH-1] = 2.34 x 10-5. Calculate each significantly! pH = 9.369, pOH = 4.631, [H+1] = 4.27 x 10-10 M 13. Calculate the pH of a 0.10 M solution of Ca(OH)2. pH = 13.3 14. Using the following Ka values, place the following acids in order of ...
Moles - University of Leicester
... 3) Find the relative atomic masses for the elements and enter them in the third column 4) Perform the calculation in the fourth column (i.e. divide the value in column 2 by that in column 1). 5) To determine the test ratio, take the smallest number in column 4 and divide each of the column 4 values ...
... 3) Find the relative atomic masses for the elements and enter them in the third column 4) Perform the calculation in the fourth column (i.e. divide the value in column 2 by that in column 1). 5) To determine the test ratio, take the smallest number in column 4 and divide each of the column 4 values ...
Chem 221 Quiz
... Because the ethanol molecules can H-bond to hold themselves together and the methyl ether molecules can only dipole-dipole to hold on to each other, it takes less energy to separate the methyl ether molecules from each other and they have a lower bp ...
... Because the ethanol molecules can H-bond to hold themselves together and the methyl ether molecules can only dipole-dipole to hold on to each other, it takes less energy to separate the methyl ether molecules from each other and they have a lower bp ...
Paper 3 - TheAllPapers
... (ii) Rhodium catalyses the decomposition of the oxides of nitrogen. 2NO → N2 + O2 Two other pollutants are carbon monoxide and unburnt hydrocarbons. How are they made into less harmful substances? ...
... (ii) Rhodium catalyses the decomposition of the oxides of nitrogen. 2NO → N2 + O2 Two other pollutants are carbon monoxide and unburnt hydrocarbons. How are they made into less harmful substances? ...
Which notation represents an atom of sodium
... (1) Sodium has a larger atomic radius and is more metallic. (2) Sodium has a larger atomic radius and is less metallic. (3) Sodium has a smaller atomic radius and is more metallic. (4) Sodium has a smaller atomic radius and is less metallic. Base your answers to questions 15 through 17 on the inform ...
... (1) Sodium has a larger atomic radius and is more metallic. (2) Sodium has a larger atomic radius and is less metallic. (3) Sodium has a smaller atomic radius and is more metallic. (4) Sodium has a smaller atomic radius and is less metallic. Base your answers to questions 15 through 17 on the inform ...
Chemistry Review 1 Answer Key
... condition was mentioned in the first sentence of the passage. Therefore, the condition not mentioned is high temperature. [1 point] 'see explanation below' 29. Base your answer on the information below. Carbon and oxygen are examples of elements that exist in more than one form in the same phase. Gr ...
... condition was mentioned in the first sentence of the passage. Therefore, the condition not mentioned is high temperature. [1 point] 'see explanation below' 29. Base your answer on the information below. Carbon and oxygen are examples of elements that exist in more than one form in the same phase. Gr ...
LESSON ASSIGNMENT LESSON 2 Elements of Chemical Change
... substance is its molecular weight expressed in grams. Thus, a GMW of NaOH would be 40 grams, where the atomic weights are as follows: Na = 23, O = 16, and H = 1. Thus, .5 GMW of NaOH would be 20 grams, and so forth. A mole is one-gram molecular weight of a substance. Thus, a mole of NaOH is 40 grams ...
... substance is its molecular weight expressed in grams. Thus, a GMW of NaOH would be 40 grams, where the atomic weights are as follows: Na = 23, O = 16, and H = 1. Thus, .5 GMW of NaOH would be 20 grams, and so forth. A mole is one-gram molecular weight of a substance. Thus, a mole of NaOH is 40 grams ...
CHAPTER 1 CHEMICAL FOUNDATIONS 1 CHAPTER ONE
... calculation. For addition/subtraction, the result has the same number of decimal places as the least precise number used in the calculation (not necessarily the number with the fewest significant figures). ...
... calculation. For addition/subtraction, the result has the same number of decimal places as the least precise number used in the calculation (not necessarily the number with the fewest significant figures). ...
08 PowerPoint
... must show all reactants and products formulas must be correct Law of Conservation of Mass must be satisfied (equation must be balanced) ...
... must show all reactants and products formulas must be correct Law of Conservation of Mass must be satisfied (equation must be balanced) ...
Electrolysis of water
Electrolysis of water is the decomposition of water (H2O) into oxygen (O2) and hydrogen gas (H2) due to an electric current being passed through the water.This technique can be used to make hydrogen fuel (hydrogen gas) and breathable oxygen; though currently most industrial methods make hydrogen fuel from natural gas instead.