PowerPoint - Science Geek
... reason backward. This is a very useful accomplishment, and a very easy one, but people do not practice it much.” Sherlock Holmes, in Sir Arthur Conan Doyle’s A Study in Scarlet ...
... reason backward. This is a very useful accomplishment, and a very easy one, but people do not practice it much.” Sherlock Holmes, in Sir Arthur Conan Doyle’s A Study in Scarlet ...
Chapter 17 Thermodynamics: Directionality of Chemical Reactions
... ΔS°=[(197.67) +3(130.68)] − [186.26 + 188.83]J K-1mol-1 = 214.62 J K-1 mol-1 ΔH° = [(-110.53) + 3(0)] − [(-74.81) + (-241.82)] kJ mol-1 = 206.10 kJ mol-1 ...
... ΔS°=[(197.67) +3(130.68)] − [186.26 + 188.83]J K-1mol-1 = 214.62 J K-1 mol-1 ΔH° = [(-110.53) + 3(0)] − [(-74.81) + (-241.82)] kJ mol-1 = 206.10 kJ mol-1 ...
Section 3_Energetics
... Direct determination of lattice energy is very difficult because it is very difficult to get isolated sodium and chloride ions. Therefore the values are usually calculated from other experimentally determined data by applying the Hess Law. The Born-Haber Cycle is a technique of applying Hess‘s Law t ...
... Direct determination of lattice energy is very difficult because it is very difficult to get isolated sodium and chloride ions. Therefore the values are usually calculated from other experimentally determined data by applying the Hess Law. The Born-Haber Cycle is a technique of applying Hess‘s Law t ...
Solubility MC
... Ksp Ag2CrO4 = 1.9 x 10-12 and Molar Mass of Ag2CrO4 = 332 g/mol. (A) 1.9 x 10-12 g (B) 1.9 x 10-8 g (C) 1.4 x 10-6 g (D) 6.3 x 10-6 g (E) 4.7 x 10-4 g ...
... Ksp Ag2CrO4 = 1.9 x 10-12 and Molar Mass of Ag2CrO4 = 332 g/mol. (A) 1.9 x 10-12 g (B) 1.9 x 10-8 g (C) 1.4 x 10-6 g (D) 6.3 x 10-6 g (E) 4.7 x 10-4 g ...
Slide 1 - Western Engineering
... of the isotope. This is usually expressed in terms of the relative molecular mass (either g / mol or kg / kmol : where a mol is NA= 6.022 x 1023 units) For an ideal gas, 1 mol at STP occupies a volume of 23.6 ...
... of the isotope. This is usually expressed in terms of the relative molecular mass (either g / mol or kg / kmol : where a mol is NA= 6.022 x 1023 units) For an ideal gas, 1 mol at STP occupies a volume of 23.6 ...
English Medium - sakshieducation.com
... 1. Write the formulae for the following salts. (a) Sodium sulphate (b) Ammonium chloride. Identify the acids and bases for which the above salts are obtained also write chemical equations for the reactions between such acids and bases which type of chemical reactions they are? 2. Compounds such as a ...
... 1. Write the formulae for the following salts. (a) Sodium sulphate (b) Ammonium chloride. Identify the acids and bases for which the above salts are obtained also write chemical equations for the reactions between such acids and bases which type of chemical reactions they are? 2. Compounds such as a ...
Document
... Like P, V, T, and n, ∆E is a state function since the change in ∆E depends only on the initial and final energies of the system and not on the details of the process the system ...
... Like P, V, T, and n, ∆E is a state function since the change in ∆E depends only on the initial and final energies of the system and not on the details of the process the system ...
Chapter 3
... Sulfur dioxide reacts with chlorine to produce thionyl chloride (used as a drying agent for inorganic halides) and dichlorine monoxide (used as a bleach for wood, pulp and textiles). SO2(g) + 2Cl2(g) → SOCl2(g) + Cl2O(g) If 0.400 mol of Cl2 reacts with excess SO2, how many moles of Cl2O are formed? ...
... Sulfur dioxide reacts with chlorine to produce thionyl chloride (used as a drying agent for inorganic halides) and dichlorine monoxide (used as a bleach for wood, pulp and textiles). SO2(g) + 2Cl2(g) → SOCl2(g) + Cl2O(g) If 0.400 mol of Cl2 reacts with excess SO2, how many moles of Cl2O are formed? ...
Lab 1
... Note: these are exact relationships between two totally different units i.e. ft in or cm in A conversion factor is important in math because they are equal to 1 and are therefore useful in chemistry to help us do calculations. ...
... Note: these are exact relationships between two totally different units i.e. ft in or cm in A conversion factor is important in math because they are equal to 1 and are therefore useful in chemistry to help us do calculations. ...
- Catalyst
... Step 1) Assign oxidation numbers to all elements in the equation. Step 2) From the changes in oxidation numbers, identify the oxidized and reduced species. Step 3) Compute the number of electrons lost in the oxidation and gained in the reduction from the oxidation number changes. Draw tie-lines betw ...
... Step 1) Assign oxidation numbers to all elements in the equation. Step 2) From the changes in oxidation numbers, identify the oxidized and reduced species. Step 3) Compute the number of electrons lost in the oxidation and gained in the reduction from the oxidation number changes. Draw tie-lines betw ...
MC94 - Southchemistry.com
... (A) I only (B) III only (C) I and II only (D) II and III only (E) I, II, and III 58. N2(g) + 3 H2(g) ---> 2 NH3(g) The reaction indicated above is thermodynamically spontaneous at 298 K, but becomes nonspontaneous at higher temperatures. Which of the following is true at 298 K? (A) G, H, and S ar ...
... (A) I only (B) III only (C) I and II only (D) II and III only (E) I, II, and III 58. N2(g) + 3 H2(g) ---> 2 NH3(g) The reaction indicated above is thermodynamically spontaneous at 298 K, but becomes nonspontaneous at higher temperatures. Which of the following is true at 298 K? (A) G, H, and S ar ...
Unit #8 - consumerchem
... producing energy (heat & light). a) Combustion of an element: i) General formula: ...
... producing energy (heat & light). a) Combustion of an element: i) General formula: ...
chemistry advanced may 2010 marking scheme
... (b) Complete the diagram to show the conical flask intended to collect the two-layer mixture. Show clearly whether this flask connects tightly, or otherwise, with the rest of the apparatus. If the flask is shown connected firmly to the adaptor, award no mark. (c) (i) Explain why the distillate consi ...
... (b) Complete the diagram to show the conical flask intended to collect the two-layer mixture. Show clearly whether this flask connects tightly, or otherwise, with the rest of the apparatus. If the flask is shown connected firmly to the adaptor, award no mark. (c) (i) Explain why the distillate consi ...
Example 1: An experiment shows that 64g of
... 3. 6.4 g of sulphur were burned completely in air. What mass of sulphur dioxide was formed? 4. How much carbon dioxide is produced when 20 tonnes of carbon are burned in excess of oxygen? 5. How much oxygen is needed to react with 12 tonnes of iron to form iron (III) oxide? 6. A chemist is investiga ...
... 3. 6.4 g of sulphur were burned completely in air. What mass of sulphur dioxide was formed? 4. How much carbon dioxide is produced when 20 tonnes of carbon are burned in excess of oxygen? 5. How much oxygen is needed to react with 12 tonnes of iron to form iron (III) oxide? 6. A chemist is investiga ...
IB Chemistry Online EQ_Ans
... in the presence of excess oxygen under standard conditions.[2] c Hess’s law states that the total enthalpy change for a reaction is independent of the route taken. It depends only on the initial and final states. ...
... in the presence of excess oxygen under standard conditions.[2] c Hess’s law states that the total enthalpy change for a reaction is independent of the route taken. It depends only on the initial and final states. ...
Chemistry 400
... D) 2 E) 4 10) Determine the electron geometry and polarity of SF6 . A) eg=trigonal bipyramidal, nonpolar B) eg=tetrahedral, polar C) eg=trigonal bipyramidal, polar D) eg=octahedral, nonpolar E) eg=octahedral, polar 11) Determine the electron geometry and polarity of HBrO2 . A) eg=trigonal bipyramida ...
... D) 2 E) 4 10) Determine the electron geometry and polarity of SF6 . A) eg=trigonal bipyramidal, nonpolar B) eg=tetrahedral, polar C) eg=trigonal bipyramidal, polar D) eg=octahedral, nonpolar E) eg=octahedral, polar 11) Determine the electron geometry and polarity of HBrO2 . A) eg=trigonal bipyramida ...
get Assignment File
... Kelvins. But how much heat is this? If we consult Table 6.1, we see that the heat capacity of water (Cwater) is 4.18 J/K∙g. Thus: q = Cwater ∙ m water ∙ ΔT = (418 J/K ∙ g) (100.0 g) (6.9K) = 2.9 x 103 Here q is the heat actually produced inside the calorimeter by the reaction of the HCl (aq) with th ...
... Kelvins. But how much heat is this? If we consult Table 6.1, we see that the heat capacity of water (Cwater) is 4.18 J/K∙g. Thus: q = Cwater ∙ m water ∙ ΔT = (418 J/K ∙ g) (100.0 g) (6.9K) = 2.9 x 103 Here q is the heat actually produced inside the calorimeter by the reaction of the HCl (aq) with th ...
Lecture Ch#5 Thermochemistry
... A. When the gas expands isothermally, it does work without a decrease in its energy, so heat must flow into the system. B. During the expansion, the gas pressure decreases, thereby releasing heat to the surroundings. C. The fact that the process is isothermal means that heat does not flow. Isotherma ...
... A. When the gas expands isothermally, it does work without a decrease in its energy, so heat must flow into the system. B. During the expansion, the gas pressure decreases, thereby releasing heat to the surroundings. C. The fact that the process is isothermal means that heat does not flow. Isotherma ...
bond enthalpy activity sheet
... a) 13.1g of zinc are added to excess dilute hydrochloric acid. b) Excess zinc is added to 100cm3 of 2 moll-1 hydrochloric acid. ...
... a) 13.1g of zinc are added to excess dilute hydrochloric acid. b) Excess zinc is added to 100cm3 of 2 moll-1 hydrochloric acid. ...
pH and pOH (cont.)
... solution react to produce a salt and water. • A salt is an ionic compound made up of a cation from a base and an anion from an acid. • Neutralization is a double-replacement ...
... solution react to produce a salt and water. • A salt is an ionic compound made up of a cation from a base and an anion from an acid. • Neutralization is a double-replacement ...
syllabus details - hrsbstaff.ednet.ns.ca
... Cross reference with topics 2, 4 and 5. Data for all these properties are listed in the data booklet. Explanations for the first four trends should be given in terms of the balance between the attraction of the nucleus for the electrons and the repulsion between electrons. Explanations based on effe ...
... Cross reference with topics 2, 4 and 5. Data for all these properties are listed in the data booklet. Explanations for the first four trends should be given in terms of the balance between the attraction of the nucleus for the electrons and the repulsion between electrons. Explanations based on effe ...
Toluenediamine
... nitrotoluene using 65 wt.% nitric acid in the presence of solid acids was published. The researchers found that due to strong adsorption of water on the catalytic acid sites only materials having a high density of acid sites are suitable catalysts. This requirement is only met by supported liquid ac ...
... nitrotoluene using 65 wt.% nitric acid in the presence of solid acids was published. The researchers found that due to strong adsorption of water on the catalytic acid sites only materials having a high density of acid sites are suitable catalysts. This requirement is only met by supported liquid ac ...
Lesson 11.1 properties of solutions
... be explained in terms of two factors. One is the natural tendency of substances to mix. However, if the process of dissolving one substance in another involved nothing more than mixing, you would expect all substances to be completely soluble in one another. You know this is not always the case, so ...
... be explained in terms of two factors. One is the natural tendency of substances to mix. However, if the process of dissolving one substance in another involved nothing more than mixing, you would expect all substances to be completely soluble in one another. You know this is not always the case, so ...
Theoretical Competition - Austrian Chemistry Olympiad
... 2.1. What is the element A? 2.2. Give the formula and the name of complex K1. 2.3. Draw the occupation of the d-orbitals for K1 and verify it by comparing the calculated and the measured magnetic moment. 2.4. Calculate the ligand energy splitting ∆ (in kJ/mol) for K1. 2.5. In case of the same centra ...
... 2.1. What is the element A? 2.2. Give the formula and the name of complex K1. 2.3. Draw the occupation of the d-orbitals for K1 and verify it by comparing the calculated and the measured magnetic moment. 2.4. Calculate the ligand energy splitting ∆ (in kJ/mol) for K1. 2.5. In case of the same centra ...
Electrolysis of water
Electrolysis of water is the decomposition of water (H2O) into oxygen (O2) and hydrogen gas (H2) due to an electric current being passed through the water.This technique can be used to make hydrogen fuel (hydrogen gas) and breathable oxygen; though currently most industrial methods make hydrogen fuel from natural gas instead.