Higher Chemistry Specimen Question Paper
... 6. Which of the following is not a correct statement about the effect of a catalyst? The catalyst A ...
... 6. Which of the following is not a correct statement about the effect of a catalyst? The catalyst A ...
Answers to Selected Problems
... 63. a. Both electrons in Ca are removed from the same energy level. The second electron removed from a K atom is in a lower energy level. b. Because Cs has a larger atomic radius than Li, the nuclear charge in a Cs atom has a smaller effect on the electrons in the highest occupied energy level. c. I ...
... 63. a. Both electrons in Ca are removed from the same energy level. The second electron removed from a K atom is in a lower energy level. b. Because Cs has a larger atomic radius than Li, the nuclear charge in a Cs atom has a smaller effect on the electrons in the highest occupied energy level. c. I ...
Topic 4
... We’ve stated the terms strong acid, strong base, soluble salt, insoluble salt, but we haven’t describe how to determine which species fall under these terms. To be able to write chemical reactions correctly, we will need to understand solubility and how strong and weak species dissociate in water. ...
... We’ve stated the terms strong acid, strong base, soluble salt, insoluble salt, but we haven’t describe how to determine which species fall under these terms. To be able to write chemical reactions correctly, we will need to understand solubility and how strong and weak species dissociate in water. ...
Stoichometry Notes (Unit 2)
... nature of chemical reactions. Chemical equations represent the qualitative and quantitative nature of chemical reactions. The equation: ...
... nature of chemical reactions. Chemical equations represent the qualitative and quantitative nature of chemical reactions. The equation: ...
Acid-Base Reactions Worksheet #2 - Mro
... informing me that they are aware you've cut class and have received a zero for any test or lab report expected for that class day. 3. Going beyond the allotted time on a test will result in loss of all credit for that question/problem. 4. Work missed due to an illness must be made up within a reason ...
... informing me that they are aware you've cut class and have received a zero for any test or lab report expected for that class day. 3. Going beyond the allotted time on a test will result in loss of all credit for that question/problem. 4. Work missed due to an illness must be made up within a reason ...
Course Book - Department of Chemistry
... Science is basic foundation of any technological and engineering creation. In view of the changing scenario at national and international level in field of Science and Technology, there is great demand for basic sciences with considerable knowledge of its applications. VNIT is committed to high acad ...
... Science is basic foundation of any technological and engineering creation. In view of the changing scenario at national and international level in field of Science and Technology, there is great demand for basic sciences with considerable knowledge of its applications. VNIT is committed to high acad ...
Chemical Equations - Salem Community Schools
... • After it reacts, it no longer has the same chemical identity. ...
... • After it reacts, it no longer has the same chemical identity. ...
- sartep.com
... Which of the following statements regarding the reaction represented by the equation above is correct? (A) Iodide ion is oxidized by hydroxide ion. (B) MnO4¯ is oxidized by iodide ion. (C) The oxidation number of manganese changes from +7 to +2. (D) The oxidation number of manganese remains the same ...
... Which of the following statements regarding the reaction represented by the equation above is correct? (A) Iodide ion is oxidized by hydroxide ion. (B) MnO4¯ is oxidized by iodide ion. (C) The oxidation number of manganese changes from +7 to +2. (D) The oxidation number of manganese remains the same ...
1.24 calculations and chemical reactions
... A solution of this acid was prepared by dissolving 2.02 g of H2A in water and making the volume up to 250 cm3 in a volumetric flask. A 25.0 cm3 sample of this solution required 22.80 cm3 of 0.150 mol dm–3 aqueous NaOH for complete reaction. Calculate the relative molecular mass, Mr, of H2A 4.2) Sodi ...
... A solution of this acid was prepared by dissolving 2.02 g of H2A in water and making the volume up to 250 cm3 in a volumetric flask. A 25.0 cm3 sample of this solution required 22.80 cm3 of 0.150 mol dm–3 aqueous NaOH for complete reaction. Calculate the relative molecular mass, Mr, of H2A 4.2) Sodi ...
Gas phase chemistry of neutral metal clusters
... are, in general, determined by chemical (electronic) properties of surface atoms/molecules [11,12]. On the basis of the concept that a catalytic reaction occurs at specific locally active sites [6,13,14], gas phase metal, metal oxide/sulfide/carbide clusters, which are composed of limited numbers of a ...
... are, in general, determined by chemical (electronic) properties of surface atoms/molecules [11,12]. On the basis of the concept that a catalytic reaction occurs at specific locally active sites [6,13,14], gas phase metal, metal oxide/sulfide/carbide clusters, which are composed of limited numbers of a ...
13AP General Equilibrium FR worksheet (missing 1988)
... experiment, the following equilibrium concentrations were measured. [H2] = 0.20 mol/L [CO2] = 0.30 mol/L [H2O] = [CO] = 0.55 mol/L (a) What is the mole fraction of CO(g) in the equilibrium mixture? (b) Using the equilibrium concentrations given above, calculate the value of Kc, the equilibrium const ...
... experiment, the following equilibrium concentrations were measured. [H2] = 0.20 mol/L [CO2] = 0.30 mol/L [H2O] = [CO] = 0.55 mol/L (a) What is the mole fraction of CO(g) in the equilibrium mixture? (b) Using the equilibrium concentrations given above, calculate the value of Kc, the equilibrium const ...
CHEMICAL REACTIONS
... e. Lewis acid (e- pr acceptor) and Lewis base (e- pr. donor) • e.g. boron trifluoride (e- deficient) and ammonia (lone pair on N) : BF3 + NH3 Æ BF3NH3 B. Decomposition/ Analysis Reactions 1. decomposition (not necessarily heated): a. hydrogen peroxide decomposes into water and oxygen. b. ammonium hy ...
... e. Lewis acid (e- pr acceptor) and Lewis base (e- pr. donor) • e.g. boron trifluoride (e- deficient) and ammonia (lone pair on N) : BF3 + NH3 Æ BF3NH3 B. Decomposition/ Analysis Reactions 1. decomposition (not necessarily heated): a. hydrogen peroxide decomposes into water and oxygen. b. ammonium hy ...
g - Highline Community College
... • A reversible process will proceed back and forth between the two end conditions any reversible process is at equilibrium results in no change in free energy ...
... • A reversible process will proceed back and forth between the two end conditions any reversible process is at equilibrium results in no change in free energy ...
EXAM IIR - Academics
... 20. In another, parallel universe, the charge/mass ratio of a fundamental particle was measured and found to be + 5.685 x 10-12 coulombs/kg. From this one can conclude that: (A) The mass of the particle must be very large and/or the charge must be very small. (B) The particle has a net negative char ...
... 20. In another, parallel universe, the charge/mass ratio of a fundamental particle was measured and found to be + 5.685 x 10-12 coulombs/kg. From this one can conclude that: (A) The mass of the particle must be very large and/or the charge must be very small. (B) The particle has a net negative char ...
1. (a) Write the electronic structure of a manganese atom and a Mn
... potassium manganate(VII) solution. In the reaction iron(II) ions are oxidised to iron(III) ions. If a solution contains both iron(II) and iron(III) ions, the concentration of each ion can be found by: • titrating samples of the original solution with standard potassium manganate(VII) solution • reac ...
... potassium manganate(VII) solution. In the reaction iron(II) ions are oxidised to iron(III) ions. If a solution contains both iron(II) and iron(III) ions, the concentration of each ion can be found by: • titrating samples of the original solution with standard potassium manganate(VII) solution • reac ...
class xii – preparatory examination - 1
... in a test tube,a violet gas ‘B’ is evolved.This gas dissolves in KI solution more than water.The gas is also soluble in CCl4.Its solution in alcohol is used as an antiseptic.Identify ‘A’ and ‘B’ and explain the observations. 12. Which is more acidic-phenol or p-nitrophenol ? Explain. 13. How will yo ...
... in a test tube,a violet gas ‘B’ is evolved.This gas dissolves in KI solution more than water.The gas is also soluble in CCl4.Its solution in alcohol is used as an antiseptic.Identify ‘A’ and ‘B’ and explain the observations. 12. Which is more acidic-phenol or p-nitrophenol ? Explain. 13. How will yo ...
File
... - in phase equilibrium particles in both phases are gaining or losing kinetic energy, such that they are ________ from one phase to another, while an equal number are moving in the reverse direction e.g. H2O(l) → H20(g) 3. Chemical Reaction Equilibrium - Quantitative reactions are those reactions wh ...
... - in phase equilibrium particles in both phases are gaining or losing kinetic energy, such that they are ________ from one phase to another, while an equal number are moving in the reverse direction e.g. H2O(l) → H20(g) 3. Chemical Reaction Equilibrium - Quantitative reactions are those reactions wh ...
answers to part a of the national high school
... can been done using the graph provided in the question. ...
... can been done using the graph provided in the question. ...
Maths for Chemistry Facts and Formulae
... The mole is the amount of substance that contains 6.0221415× 1023 (Avogadro constant/ mol−1 ) atoms or molecules of the pure substance being measured. For example 1 mole (mol) of potassium will contain NA atoms. 1 mole of water contains NA water molecules. A mole of any substance contains as many at ...
... The mole is the amount of substance that contains 6.0221415× 1023 (Avogadro constant/ mol−1 ) atoms or molecules of the pure substance being measured. For example 1 mole (mol) of potassium will contain NA atoms. 1 mole of water contains NA water molecules. A mole of any substance contains as many at ...
Ch 4 Student
... consumed and limits amount of product • Reactant in excess – reactant present in greater quantity than limiting reactant • Theoretical Yield – amount of product made based on consumption of all the limiting reactant • Actual Yield – amount of product actually ...
... consumed and limits amount of product • Reactant in excess – reactant present in greater quantity than limiting reactant • Theoretical Yield – amount of product made based on consumption of all the limiting reactant • Actual Yield – amount of product actually ...
Bioorthogonal chemistry
The term bioorthogonal chemistry refers to any chemical reaction that can occur inside of living systems without interfering with native biochemical processes. The term was coined by Carolyn R. Bertozzi in 2003. Since its introduction, the concept of the bioorthogonal reaction has enabled the study of biomolecules such as glycans, proteins, and lipids in real time in living systems without cellular toxicity. A number of chemical ligation strategies have been developed that fulfill the requirements of bioorthogonality, including the 1,3-dipolar cycloaddition between azides and cyclooctynes (also termed copper-free click chemistry), between nitrones and cyclooctynes, oxime/hydrazone formation from aldehydes and ketones, the tetrazine ligation, the isocyanide-based click reaction, and most recently, the quadricyclane ligation.The use of bioorthogonal chemistry typically proceeds in two steps. First, a cellular substrate is modified with a bioorthogonal functional group (chemical reporter) and introduced to the cell; substrates include metabolites, enzyme inhibitors, etc. The chemical reporter must not alter the structure of the substrate dramatically to avoid affecting its bioactivity. Secondly, a probe containing the complementary functional group is introduced to react and label the substrate.Although effective bioorthogonal reactions such as copper-free click chemistry have been developed, development of new reactions continues to generate orthogonal methods for labeling to allow multiple methods of labeling to be used in the same biosystems.