Chapter15
... Each C is bonded to the maximum number of other atoms – saturated hydrocarbons Naming: Each chain, branch or ring has a name based on the number of carbons Prefix + root + suffix Root: # of carbon atoms in the longest continuous chain in the molecule (Table 15.1) Suffix: type of organic compound (id ...
... Each C is bonded to the maximum number of other atoms – saturated hydrocarbons Naming: Each chain, branch or ring has a name based on the number of carbons Prefix + root + suffix Root: # of carbon atoms in the longest continuous chain in the molecule (Table 15.1) Suffix: type of organic compound (id ...
Fall 2008 Blank Exam 1 - Department of Chemistry | Oregon State
... This exam consists of 25 multiple-choice questions. Each question has four points associated with it. Select the best multiple-choice answer by filling in the corresponding circle on the rear page of the answer sheet. If you have any questions before the exam, please ask. If you have any questions d ...
... This exam consists of 25 multiple-choice questions. Each question has four points associated with it. Select the best multiple-choice answer by filling in the corresponding circle on the rear page of the answer sheet. If you have any questions before the exam, please ask. If you have any questions d ...
Section 1 Compounds and Molecules
... > How do ionic bonds form? > Ionic bonds form from the attractions between such oppositely charged ions. • ionic bonds: the attractive force between oppositely charged ions, which form when electrons are transferred from one atom to another • Ionic bonds are formed are formed by the transfer of elec ...
... > How do ionic bonds form? > Ionic bonds form from the attractions between such oppositely charged ions. • ionic bonds: the attractive force between oppositely charged ions, which form when electrons are transferred from one atom to another • Ionic bonds are formed are formed by the transfer of elec ...
Carbonyl Alpha-Substitution Reactions
... • Sodium hydride (NaH) or lithium diisopropylamide [LiN(i-C3H7)2] are strong enough to form the enolate ...
... • Sodium hydride (NaH) or lithium diisopropylamide [LiN(i-C3H7)2] are strong enough to form the enolate ...
TV RajanBabu Chemistry, 730 Autumn 1997
... Acidites of phosphonium and sulfonium compounds and ylides (for chemistry see later) Enols, enamines and metalloenamines in synthesis Mechanism of acid and base catalyzed enolization, kinetic vs thermodynamic control Detailed mechanism of -substitution of a carbonyl compound (e. g., bromination) Ca ...
... Acidites of phosphonium and sulfonium compounds and ylides (for chemistry see later) Enols, enamines and metalloenamines in synthesis Mechanism of acid and base catalyzed enolization, kinetic vs thermodynamic control Detailed mechanism of -substitution of a carbonyl compound (e. g., bromination) Ca ...
BSc-Chemistry-II
... Mechanisms of nucleophilic substitution in nitroarenes and their reductions in acidic, neutral and alkaline media. Picric acid. Alkyl and Aryl amines : Reactivity, structure and nomenclature of amines, physical properties. Stereochemistry of amines. Separation of a mixture of primary, secondary and ...
... Mechanisms of nucleophilic substitution in nitroarenes and their reductions in acidic, neutral and alkaline media. Picric acid. Alkyl and Aryl amines : Reactivity, structure and nomenclature of amines, physical properties. Stereochemistry of amines. Separation of a mixture of primary, secondary and ...
Chapter 2 - people.vcu.edu
... o These are formed by the overlap of unhybridized p orbitals o There is one sigma bond and one pi bond in a double bond. o There is one sigma bond and two pi bonds in a triple bond. ...
... o These are formed by the overlap of unhybridized p orbitals o There is one sigma bond and one pi bond in a double bond. o There is one sigma bond and two pi bonds in a triple bond. ...
Chapter 22/23-Organic Chemistry
... c. 1,3-dibromo-2-chloro-5-methylcylcohexane d. 3,3-difluoro-1,4-pentadiene e. 4–ethyl–2,6–dimethyl–2–heptene. f. 1,1-dichlorobenzene 3. Based on what you know about the ability of a carbon-carbon double bond to rotate, do these two structures represent isomers, or are they just the same molecule? ...
... c. 1,3-dibromo-2-chloro-5-methylcylcohexane d. 3,3-difluoro-1,4-pentadiene e. 4–ethyl–2,6–dimethyl–2–heptene. f. 1,1-dichlorobenzene 3. Based on what you know about the ability of a carbon-carbon double bond to rotate, do these two structures represent isomers, or are they just the same molecule? ...
I B.Sc. HORTICULTURE-MODEL QUESTION PAPER
... Answer any FIVE of the following questions Each carries FIVE marks 5x5 = 25 Marks 1. Define the electron deficient molecules and draw the structure of Borazole and Diborane. 2. Classify the Oxides based on the oxygen content with one example to each. 3. How the following are synthesized from Organo ...
... Answer any FIVE of the following questions Each carries FIVE marks 5x5 = 25 Marks 1. Define the electron deficient molecules and draw the structure of Borazole and Diborane. 2. Classify the Oxides based on the oxygen content with one example to each. 3. How the following are synthesized from Organo ...
Skill Sheet 19-C Naming Chemical Compounds
... and/or polyatomic ions. Use the periodic table and the polyatomic ion chart in section 19.2 of your student text to help you name the ions. ...
... and/or polyatomic ions. Use the periodic table and the polyatomic ion chart in section 19.2 of your student text to help you name the ions. ...
Chapter 23 Functional Groups
... alcohols classified into categories according to the number of R groups attached to the carbon with the hydroxyl –1 R group: primary alcohol –2 R groups: secondary alcohol –3 R groups: tertiary alcohol ...
... alcohols classified into categories according to the number of R groups attached to the carbon with the hydroxyl –1 R group: primary alcohol –2 R groups: secondary alcohol –3 R groups: tertiary alcohol ...
Chapters 9 and 10
... Indicate the total number of sigma (σ) bonds and the total number of pi (π) bonds in the molecule ...
... Indicate the total number of sigma (σ) bonds and the total number of pi (π) bonds in the molecule ...
Benzene and Aromatics
... the molecular formula C6H6. It is sometimes abbreviated Ph–H. Benzene is a colorless and highly flammable liquid with a sweet smell and a relatively high melting point. Because it is a known carcinogen, its use as an additive in gasoline is now limited, but it is an important industrial solvent and ...
... the molecular formula C6H6. It is sometimes abbreviated Ph–H. Benzene is a colorless and highly flammable liquid with a sweet smell and a relatively high melting point. Because it is a known carcinogen, its use as an additive in gasoline is now limited, but it is an important industrial solvent and ...
Unit 6 Naming Binary Compounds
... their respective charges. (For polyatomic ions you are expected to know their charges and names.) 2. Add whatever subscripts are needed to balance the charges, or criss-cross. ...
... their respective charges. (For polyatomic ions you are expected to know their charges and names.) 2. Add whatever subscripts are needed to balance the charges, or criss-cross. ...
Chemistry: The Central Science, 12e (Brown et al
... 39) Alkenes have the general formula __________. A) CnH2n. B) CnH2n-2. C) CnH2n+2 D) CnHn. E) C2nHn. 40) In general, __________ are the most reactive hydrocarbons. A) alkenes B) alkynes C) alkanes D) cycloalkanes E) olefins 41) The addition of HBr to 2-butene produces __________. A) 1-bromobutane B) ...
... 39) Alkenes have the general formula __________. A) CnH2n. B) CnH2n-2. C) CnH2n+2 D) CnHn. E) C2nHn. 40) In general, __________ are the most reactive hydrocarbons. A) alkenes B) alkynes C) alkanes D) cycloalkanes E) olefins 41) The addition of HBr to 2-butene produces __________. A) 1-bromobutane B) ...
solution is a solution that contains the maximum amount of solute
... Part A: Fill-in-the-blanks. Choose the word that best completes each statement. [36 points/2 points each] ...
... Part A: Fill-in-the-blanks. Choose the word that best completes each statement. [36 points/2 points each] ...
Lecture notes Chapters 14-15
... Physical properties of alcohols: 1. Because of the large difference in electronegativity between oxygen and carbon (3.5 - 2.5 = 1.0) and between oxygen and hydrogen (3.5 - 2.1 = 1.4), alcohols are polar molecules. 2. There is hydrogen bonding between the alcohol molecules (because of –OH). 3. Alcoho ...
... Physical properties of alcohols: 1. Because of the large difference in electronegativity between oxygen and carbon (3.5 - 2.5 = 1.0) and between oxygen and hydrogen (3.5 - 2.1 = 1.4), alcohols are polar molecules. 2. There is hydrogen bonding between the alcohol molecules (because of –OH). 3. Alcoho ...
File - Garbally Chemistry
... Aromatic - hydrocarbons with a Benzene ring of 6 carbon atoms, where the bonds are intermediate between single and double bonds. Aliphatic hydrocarbons. A homologous series is a group of compounds with similar chemical properties due to having the same functional group. They have a gradual variation ...
... Aromatic - hydrocarbons with a Benzene ring of 6 carbon atoms, where the bonds are intermediate between single and double bonds. Aliphatic hydrocarbons. A homologous series is a group of compounds with similar chemical properties due to having the same functional group. They have a gradual variation ...
1 Carbonyl Condensation Reactions (Conjugate Addition) If we look
... note that an y carbonyl compound with alpha hydrogens can undergo the aldol reaction (i.e. esters, acids, etc.). How can we tell whether a molecule is going to undergo an aldol-like reaction, or an enolate-like reaction? There are a couple of clues: 1) STRONG base. If bases like LDA are being used, ...
... note that an y carbonyl compound with alpha hydrogens can undergo the aldol reaction (i.e. esters, acids, etc.). How can we tell whether a molecule is going to undergo an aldol-like reaction, or an enolate-like reaction? There are a couple of clues: 1) STRONG base. If bases like LDA are being used, ...
Organosulfur compounds
Organosulfur compounds are organic compounds that contain sulfur. They are often associated with foul odors, but many of the sweetest compounds known are organosulfur derivatives, e.g., saccharin. Nature abounds with organosulfur compounds—sulfur is essential for life. Of the 20 common amino acids, two (cysteine and methionine) are organosulfur compounds, and the antibiotics penicillin (pictured below) and sulfa drugs both contain sulfur. While sulfur-containing antibiotics save many lives, sulfur mustard is a deadly chemical warfare agent. Fossil fuels, coal, petroleum, and natural gas, which are derived from ancient organisms, necessarily contain organosulfur compounds, the removal of which is a major focus of oil refineries.Sulfur shares the chalcogen group with oxygen, selenium and tellurium, and it is expected that organosulfur compounds have similarities with carbon–oxygen, carbon–selenium and carbon–tellurium compounds, which is true to some extent.A classical chemical test for the detection of sulfur compounds is the Carius halogen method.