Chapter 3 Review
... 16. Sally throws a ball horizontally from the top of a tall building at the same time that Pete drops a ball from the top of the same building. Which ball will hit the ground first? Explain your answer. ...
... 16. Sally throws a ball horizontally from the top of a tall building at the same time that Pete drops a ball from the top of the same building. Which ball will hit the ground first? Explain your answer. ...
Chapter 13 Notes
... a. Average speed is how far an object moves in a given amount of time. Average Speed = Distance Time b. Motion is always measured in relation to some location called point of reference. c. Velocity describes the speed and direction of an object. Lesson 2: What are forces? Pushes and Pulls a. A for ...
... a. Average speed is how far an object moves in a given amount of time. Average Speed = Distance Time b. Motion is always measured in relation to some location called point of reference. c. Velocity describes the speed and direction of an object. Lesson 2: What are forces? Pushes and Pulls a. A for ...
Chapter 2: Two Dimensional Motion
... Note that factor label of the units gives N/kg, but that is equivalent to m/s/s since F=ma and the units are F (in N) = m (in kg) a (in m/s/s). Now, using the formula for critical velocity: (Consider that g is the centripetal acceleration, and the formula becomes apparent. While normally we don't co ...
... Note that factor label of the units gives N/kg, but that is equivalent to m/s/s since F=ma and the units are F (in N) = m (in kg) a (in m/s/s). Now, using the formula for critical velocity: (Consider that g is the centripetal acceleration, and the formula becomes apparent. While normally we don't co ...
Test 1 Sample
... 4. Joe exerts a constant horizontal force on a large box. As a result, the box moves across a horizontal floor at a constant speed. The constant horizontal force applied to the box by Joe a. has the same magnitude as the weight of the box. b. is greater than the weight of the box. c. has the same m ...
... 4. Joe exerts a constant horizontal force on a large box. As a result, the box moves across a horizontal floor at a constant speed. The constant horizontal force applied to the box by Joe a. has the same magnitude as the weight of the box. b. is greater than the weight of the box. c. has the same m ...
5.4 Projectile Motion
... Projectile motion can be separated into components. a. Roll a ball along a horizontal surface, and its velocity is constant because no component of gravitational force acts horizontally. b. Drop it, and it accelerates downward and covers a greater vertical distance each second. ...
... Projectile motion can be separated into components. a. Roll a ball along a horizontal surface, and its velocity is constant because no component of gravitational force acts horizontally. b. Drop it, and it accelerates downward and covers a greater vertical distance each second. ...
Worksheet 4
... The body has amass that can be adjusted from 1 to 5 kg with the slider control on the left. It is acted on by a force that is adjustable between –10 N (downward) and +10 N (upward) using the slider on the right. You can also turn the force on or off and display a one-dimensional coordinate axis usin ...
... The body has amass that can be adjusted from 1 to 5 kg with the slider control on the left. It is acted on by a force that is adjustable between –10 N (downward) and +10 N (upward) using the slider on the right. You can also turn the force on or off and display a one-dimensional coordinate axis usin ...
Newton`s First Law
... is getting rid of the effects of friction. When we said no force earlier on it should really have been no unbalanced force. In the example of the stone the weight of the stone is just balanced by the upward force of the ice - the two forces on the stone are equal and so it continues moving at a cons ...
... is getting rid of the effects of friction. When we said no force earlier on it should really have been no unbalanced force. In the example of the stone the weight of the stone is just balanced by the upward force of the ice - the two forces on the stone are equal and so it continues moving at a cons ...
4. acceleration and terminal velocity
... • You should know the equation that shows the relationship between resultant force, mass and acceleration, and be able to use it. The equation Resultant force (newton, N) = mass (kg) × acceleration (m/s2). • You can see from this equation that 1 N is the force needed to give 1 kg an acceleration of ...
... • You should know the equation that shows the relationship between resultant force, mass and acceleration, and be able to use it. The equation Resultant force (newton, N) = mass (kg) × acceleration (m/s2). • You can see from this equation that 1 N is the force needed to give 1 kg an acceleration of ...
Motion and Forces ppt.
... according to the inverse-square law. The force of gravity weakens as the distance squared. Ex: If you were three times farther from the center of the Earth as you are now, your weight would be 1/9 of what it is now. ...
... according to the inverse-square law. The force of gravity weakens as the distance squared. Ex: If you were three times farther from the center of the Earth as you are now, your weight would be 1/9 of what it is now. ...
Speed and Velocity
... causes the speed of an object to decrease (Example: the use of a parachute) • An object moving in a circle is constantly changing direction, so its velocity is constantly changing. That means it’s accelerating. A force is needed to accelerate an object. ...
... causes the speed of an object to decrease (Example: the use of a parachute) • An object moving in a circle is constantly changing direction, so its velocity is constantly changing. That means it’s accelerating. A force is needed to accelerate an object. ...
NCEA Level 2 Physics (91171) 2012 Assessment Schedule
... Assessment Schedule – 2012 Physics: Demonstrate understanding of mechanics (91171) Question ONE (a) (b) (c) ...
... Assessment Schedule – 2012 Physics: Demonstrate understanding of mechanics (91171) Question ONE (a) (b) (c) ...
MP 2 Quarterly Review Sheet Answers
... 8. An elevator of mass M is pulled upwards by a cable; the elevator is moving up but accelerating in the opposite directon. What is the tension in the cable (neglecting the mass of the cable)? A. less than zero B. between zero and Mg (although it is moving up it is accelerating DOWN) C. equal to Mg ...
... 8. An elevator of mass M is pulled upwards by a cable; the elevator is moving up but accelerating in the opposite directon. What is the tension in the cable (neglecting the mass of the cable)? A. less than zero B. between zero and Mg (although it is moving up it is accelerating DOWN) C. equal to Mg ...
Review Guide
... 12. Two forces are applied to a car in an effort to accelerate it. The first force is 24 N at a -560 angle from the vertical. The next force is 37 N at a +650 angle from the vertical. What is the resultant of these two forces? If the car has a mass of 2500 kg, what acceleration does it have? (Disreg ...
... 12. Two forces are applied to a car in an effort to accelerate it. The first force is 24 N at a -560 angle from the vertical. The next force is 37 N at a +650 angle from the vertical. What is the resultant of these two forces? If the car has a mass of 2500 kg, what acceleration does it have? (Disreg ...
Newton`s Third Law Action-Reaction
... Adding and Subtracting Vectors Adding vectors graphically: Place the tail of the second at the head of the first. The sum points from the tail of the first to the head of the last. ...
... Adding and Subtracting Vectors Adding vectors graphically: Place the tail of the second at the head of the first. The sum points from the tail of the first to the head of the last. ...
7.5 Test Review- Circular Motion and Gravitation
... radius of the path remains unchanged, the magnitude of the centripetal force acting on the airplane will be a. Half as much b. Twice as much c. One-fourth as much d. Four times as much 21. When a satellite is at a distance d from the center of the Earth, the force due to gravity on the satellite is ...
... radius of the path remains unchanged, the magnitude of the centripetal force acting on the airplane will be a. Half as much b. Twice as much c. One-fourth as much d. Four times as much 21. When a satellite is at a distance d from the center of the Earth, the force due to gravity on the satellite is ...
