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Group cohomology - of Alexey Beshenov
Group cohomology - of Alexey Beshenov

... Here f : G × G → L× , and σ(x) denotes the Galois action of σ on x ∈ L. A tedious verification shows that the associativity of the product above imposes the same associativity condition (3) on f as we have seen before. This construction leads to crossed product algebras (L/K, f). Two such algebras ( ...
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The structure of reductive groups - UBC Math

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Profinite Orthomodular Lattices

... there exists a coatom go, say, such that x $ qo and qo A L is open. Now let q be any coatom of C(L) . We claim that q A L is open in L . Indeed, letting x = q' in the above, we have a coatom qo of C(L) such that q' $ qo and q0 A L is open. But qo must be q since C(L) is a Boolean algebra, proving th ...
Isotriviality and the Space of Morphisms on Projective Varieties
Isotriviality and the Space of Morphisms on Projective Varieties

... is reductive. Then φ is isotrivial if and only if φ has potential good reduction at all places v of K. Proof. The only if direction is clear. For the if direction, we imitate the proof in [12] to create a morphism from the complete curve C to the affine variety Md (X, L), which must be constant. Spe ...
Part IX. Factorization
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... that every natural number can be uniquely written as a product of primes. The units in Z are 1 and −1 and the irreducibles in Z are the positive primes and the negative primes. So the only associate of a prime is its negative. Since Z is a UFD, every element can be expressed as a product of irreduci ...
NON-SEMIGROUP GRADINGS OF ASSOCIATIVE ALGEBRAS Let A
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... and (δ 2 − δ )λ 6= (γ 2 − γ )µ . Then the said root space decomposition is a non-semigroup grading of A. Note that the conditions (1) and (2) are somewhat weaker than (Aλ Aη )Aµ 6= 0 and Aλ (Aη Aµ ) 6= 0, respectively. Proof. The conditions (1) and (2) ensure that both expressions (λ ∗ η ) ∗ µ and λ ...
homogeneous polynomials with a multiplication theorem
homogeneous polynomials with a multiplication theorem

... modulus of the algebra. Then, since fi(x) can be expressed as a polynomial in less than n variables, make a linear transformation on the variables x< so that /i(x) is a polynomial in X\, • • • , xni, in which nx is as small as possible. When we make the induced transformation on the basal numbers of ...
Quaternion Algebras and Quadratic Forms - UWSpace
Quaternion Algebras and Quadratic Forms - UWSpace

... say that v is an isotropic if B(v, v) = qB (v) = 0, and anisotropic otherwise. The quadratic space (V, B) is said to be isotropic if it contains an isotropic vector, and it is anisotropic otherwise. And (V, B) is totally isotropic if every non-zero vector in V is isotropic, i.e. B ≡ 0. Theorem 1.3.2 ...
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... a more concrete group or algebra consisting of matrices or operators. In this way we can study an algebraic object as collection of symmetries of a vector space. Hence we can apply the methods of linear algebra and functional analysis to the study of groups and algebras. Representation theory also p ...
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... Fermat’s Theorem: If p is an odd prime, ap−1 = 1 mod p for all a A quick reject test: if ap−1 mod p ̸= 1 mod p: reject! Miller-Rabin test: if ap−1 mod p = 1 mod p: • Let p − 1 = c · 2b where c: odd number, b > 0 ap−1 mod p = [. . . [ac mod p]2 . . .]2 mod p ...
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full text (.pdf)
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... ∗ . In the presence of ∗ , these properties plus the infinitary star-continuity condition are sufficient for representation by a nonstandard relational model—one in which p∗ is the least reflexive transitive relation containing p in the algebra, although not necessarily the set-theoretic reflexive t ...
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... To prove that two groups are isomorphic usually requires finding an explicit isomorphism. Proving that two groups are not isomorphic is often easier, as if we can find an “abstract property” that distinguishes them, then this is enough, since isomorphic groups have the same “abstract properties”. We ...
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... 2.5 Let r ≥ 0 and s ≥ 0 be integers; let X1 , . . . , Xr be smooth quasiprojective varieties defined over k and G1 , . . . , Gr a finite (possibly empty) family of semi-abelian varieties defined over k. We define Mixed K-groups K(k, {CH0 (Xi )}ri=1 ; {Gj }sj=1 ) as follows. If r = 0 and s = 0, we wr ...
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... call Of a skyscraper sheaf. We define Of to have degree equal to deg(f ). (Intuitively, we should think of torsion sheaves as being very small. For c, where M = k[x0 , x1 ]/(f ). Note example, one can easily show that Of = M that this does not always decompose into skyscraper sheaves: for example, i ...
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Packaging Mathematical Structures - HAL

... Many of the op-cited works focused on the definition of the hierarchy rather than its use, making simplyfying assumptions that would have masked the problems we encountered. For example some assume that only one or two structures are involved at any time, or that all structures are explicitly spcifi ...
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Modular representation theory

Modular representation theory is a branch of mathematics, and that part of representation theory that studies linear representations of finite groups over a field K of positive characteristic. As well as having applications to group theory, modular representations arisenaturally in other branches of mathematics, such as algebraic geometry, coding theory, combinatorics and number theory.Within finite group theory, character-theoretic results provedby Richard Brauer using modular representation theory playedan important role in early progress towards theclassification of finite simple groups, especially for simple groups whose characterization was not amenable to purely group-theoretic methods because their Sylow 2 subgroups were too small in an appropriate sense. Also, a general result on embedding of elements of order in finite groups called the Z* theorem, proved by George Glauberman using the theory developed by Brauer, was particularly useful in the classification program.If the characteristic of K does not divide the order of the group, G, then modular representations are completely reducible, as with ordinary(characteristic 0) representations, by virtue of Maschke's theorem. The proof of Maschke's theorem relies on being able to divide by the group order, which is not meaningful when the order of G is divisible by the characteristic of K. In that case, representations need not becompletely reducible, unlike the ordinary (and the coprime characteristic) case. Much of the discussion below implicitly assumesthat the field K is sufficiently large (for example, K algebraically closed suffices), otherwise some statements need refinement.
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