
WHEN EVERY FINITELY GENERATED FLAT MODULE IS
... associative algebra over a field. Nevertheless there are domains that are neither right nor left S-rings. See Section 3 for all this. From [6] it follows that we may assign to each sequence A1 , A2 , . . . as above a projective right module P such that this sequence converges if and only if P is fini ...
... associative algebra over a field. Nevertheless there are domains that are neither right nor left S-rings. See Section 3 for all this. From [6] it follows that we may assign to each sequence A1 , A2 , . . . as above a projective right module P such that this sequence converges if and only if P is fini ...
Completed representation ring spectra of nilpotent groups Algebraic & Geometric Topology [Logo here]
... to the abstract theory of these homotopy categories. We will write M∗ , M∗ (N ), and [M, N ]∗ for the groups π∗ (M ), π∗ (M ∧R N ), and π−∗ (FR (N, M )) respectively, where FR (N, M ) is the R-module function spectrum. (The underlying S-algebra R will be specified if it is ambiguous.) In the setting ...
... to the abstract theory of these homotopy categories. We will write M∗ , M∗ (N ), and [M, N ]∗ for the groups π∗ (M ), π∗ (M ∧R N ), and π−∗ (FR (N, M )) respectively, where FR (N, M ) is the R-module function spectrum. (The underlying S-algebra R will be specified if it is ambiguous.) In the setting ...
Math 210B. Spec 1. Some classical motivation Let A be a
... Let A be a commutative ring. We have defined the Zariski topology on the set Spec(A) of primes ideals of A by declaring the closed subsets to be those of the form V (I) = {p ⊇ I}. This is reminiscent of the classical situation where we worked with the set k n = MaxSpec(k[t1 , . . . , tn ])) for an a ...
... Let A be a commutative ring. We have defined the Zariski topology on the set Spec(A) of primes ideals of A by declaring the closed subsets to be those of the form V (I) = {p ⊇ I}. This is reminiscent of the classical situation where we worked with the set k n = MaxSpec(k[t1 , . . . , tn ])) for an a ...
Groups CDM Klaus Sutner Carnegie Mellon University
... A subgroup H of G is normal if for all x ∈ H, a ∈ G: axa−1 ∈ H. In other words, a subgroup is normal if it is invariant under the conjugation maps x 7→ axa−1 . Equivalently, aH = Ha. In a commutative group all subgroups are normal. The trivial group 1 and G itself are always normal subgroups (groups ...
... A subgroup H of G is normal if for all x ∈ H, a ∈ G: axa−1 ∈ H. In other words, a subgroup is normal if it is invariant under the conjugation maps x 7→ axa−1 . Equivalently, aH = Ha. In a commutative group all subgroups are normal. The trivial group 1 and G itself are always normal subgroups (groups ...
Construction of relative difference sets in p
... both constructions are in elementary abelian groups. Jungnickel [5] extended the p = 2, j odd case to include any 2-group with exponent less than 2(j+3)‘2that has a Z2 piece split off (note: his result also works on non-abelian groups, but what is stated above is his result together with [6] for abe ...
... both constructions are in elementary abelian groups. Jungnickel [5] extended the p = 2, j odd case to include any 2-group with exponent less than 2(j+3)‘2that has a Z2 piece split off (note: his result also works on non-abelian groups, but what is stated above is his result together with [6] for abe ...
Flatness
... theorem characterizing flatness via the first Tor. So, let F· → M be a free resolution of M . Then A/xA ⊗ F· is again an exact sequence, since the homology is TorA i (A/xA, M ), and these are all 0 since x is not a zero divisor. Thus, A/xA ⊗ F· is a resolution of M/xM , showing that the Tors coincid ...
... theorem characterizing flatness via the first Tor. So, let F· → M be a free resolution of M . Then A/xA ⊗ F· is again an exact sequence, since the homology is TorA i (A/xA, M ), and these are all 0 since x is not a zero divisor. Thus, A/xA ⊗ F· is a resolution of M/xM , showing that the Tors coincid ...
B Sc MATHEMATICS ABSTRACT ALGEBRA UNIVERSITY OF CALICUT Core Course
... (31) Let G be a cyclic group of order 6. Then the number of elements g G such that G = < g > is : ( a) 5 (b) 3 (c) 2 (d) 4 (32) Which of the following is true? (a) Every cyclic group has a unique generator (b) In a cyclic group, every element is a generator (c) Every cyclic group has at least two ...
... (31) Let G be a cyclic group of order 6. Then the number of elements g G such that G = < g > is : ( a) 5 (b) 3 (c) 2 (d) 4 (32) Which of the following is true? (a) Every cyclic group has a unique generator (b) In a cyclic group, every element is a generator (c) Every cyclic group has at least two ...
A PROPERTY OF SMALL GROUPS A connected group of Morley
... (3) G is not locally finite. A group of bounded exponent cannot have finitely generated subgroups of arbitrary large finite size, as the size of a Sylow of every finite subgroup is bounded (a Sylow subgroup has a non-trivial centre, the centraliser of any element of which contains the whole Sylow). ...
... (3) G is not locally finite. A group of bounded exponent cannot have finitely generated subgroups of arbitrary large finite size, as the size of a Sylow of every finite subgroup is bounded (a Sylow subgroup has a non-trivial centre, the centraliser of any element of which contains the whole Sylow). ...
Title BP operations and homological properties of
... Let <3i$ be the category of all associative AP^P-comodules and comodule maps. An associative fiP^BP-comodule has a ΰP^-projective resolution in 3ϊ$. In [3] we introduced the concept of iSίP-injective weaker slightly than that of In § 3 we prove Theorem 0.4. Let M be an associative BP*BP-comodule wit ...
... Let <3i$ be the category of all associative AP^P-comodules and comodule maps. An associative fiP^BP-comodule has a ΰP^-projective resolution in 3ϊ$. In [3] we introduced the concept of iSίP-injective weaker slightly than that of In § 3 we prove Theorem 0.4. Let M be an associative BP*BP-comodule wit ...
4. Rings 4.1. Basic properties. Definition 4.1. A ring is a set R with
... Exercise 4.22. Formulate and prove an analog of Theorem 4.9 for noncommutative rings (“R 6= 0 is a division ring if and only if ...”). Exercise 4.23. Show that R = M2 (R) has no ideals 6= 0, R (or you can do it for Mn (R) if feeling more ambitious). Now M2 (R) is certainly not a division ring (why n ...
... Exercise 4.22. Formulate and prove an analog of Theorem 4.9 for noncommutative rings (“R 6= 0 is a division ring if and only if ...”). Exercise 4.23. Show that R = M2 (R) has no ideals 6= 0, R (or you can do it for Mn (R) if feeling more ambitious). Now M2 (R) is certainly not a division ring (why n ...
Subfactors and Modular Tensor Categories
... whose centers realize the Evans-Gannon modular data? What about analogous series for Asaeda-Haagerup modular data and other families of quadratic categories? Does every MTC come from conformal field theory (e.g. as the representation category of a VOA)? Two MTC’s are Witt equivalent if their tensor ...
... whose centers realize the Evans-Gannon modular data? What about analogous series for Asaeda-Haagerup modular data and other families of quadratic categories? Does every MTC come from conformal field theory (e.g. as the representation category of a VOA)? Two MTC’s are Witt equivalent if their tensor ...