Thermodynamics: Lecture 2
... was established. The conversion factor J, is 4.18Joules/calorie in honor of Joule. Some of his experiments were very simple. He let fixed weight to rotate paddle in water and measured the rise in temperature. Similarly he passed current through resistor and measured the rise in temperature. Now we k ...
... was established. The conversion factor J, is 4.18Joules/calorie in honor of Joule. Some of his experiments were very simple. He let fixed weight to rotate paddle in water and measured the rise in temperature. Similarly he passed current through resistor and measured the rise in temperature. Now we k ...
Thermodynamics I Chapter 2 Properties of Pure Substances
... Values for compressed liquid is taken as the same as that of saturated liquid at the same temperature ex. T=25oC, P=1 bar (compressed liquid) h25C,1b ≈ hf@T=25C ...
... Values for compressed liquid is taken as the same as that of saturated liquid at the same temperature ex. T=25oC, P=1 bar (compressed liquid) h25C,1b ≈ hf@T=25C ...
Particular Integrals
... • ax2 + bx + c; • Ae−5x ; • a cos x + b sin x; • a sin(3x) + b cos(3x); • ax + b + cex ; • a100 x100 + a99 x99 + . . . + a1 x + a0 + b cos(100x) + c sin(100x) + de100x . Some of these suggestions could need modifying by adding in additional powers of x if it turns out that they form part of the comp ...
... • ax2 + bx + c; • Ae−5x ; • a cos x + b sin x; • a sin(3x) + b cos(3x); • ax + b + cex ; • a100 x100 + a99 x99 + . . . + a1 x + a0 + b cos(100x) + c sin(100x) + de100x . Some of these suggestions could need modifying by adding in additional powers of x if it turns out that they form part of the comp ...
Algebra Expressions and Real Numbers
... Use the discriminant to find the number and types of solutions, but don't solve the equation. a. x 2 5 x 6 0 ...
... Use the discriminant to find the number and types of solutions, but don't solve the equation. a. x 2 5 x 6 0 ...
