
0081_hsm11a1_te_03tr.indd
... Match each statement with an equation. There is one extra equation. 1. A number plus 11 is 14. 2. 7 is 1/4 of some number. 3. Six less than the sum of 11 and 9 is 14. 4. The quotient of a number n and 7 is 2. 5. Nine more than twice a number n is 12. ...
... Match each statement with an equation. There is one extra equation. 1. A number plus 11 is 14. 2. 7 is 1/4 of some number. 3. Six less than the sum of 11 and 9 is 14. 4. The quotient of a number n and 7 is 2. 5. Nine more than twice a number n is 12. ...
Grade Level:
... Essential Questions: a. 1. How is solving an equation, related to the current topic, similar to solving equations in topics covered in previous units? 2. Compare (find a similarity and/or difference) the current mathematical concept to previously learned topics. Give specific mathematical examples? ...
... Essential Questions: a. 1. How is solving an equation, related to the current topic, similar to solving equations in topics covered in previous units? 2. Compare (find a similarity and/or difference) the current mathematical concept to previously learned topics. Give specific mathematical examples? ...
Geogebra quick start
... Right click on the axes and turn them off Draw a circle (Circle menu) Draw a line through the centre and any point on the circle (Circle menu) Find the intersection points of the line and the circle (command menu) Draw a triangle through the points of intersection and any other point on the circle ( ...
... Right click on the axes and turn them off Draw a circle (Circle menu) Draw a line through the centre and any point on the circle (Circle menu) Find the intersection points of the line and the circle (command menu) Draw a triangle through the points of intersection and any other point on the circle ( ...
The alogorithm
... statement "bj = bj – mb1". We shall pursue this further as we continue with algorithm. After eliminating x1, the equations 2, …, n, only contain the variables x2, …, xn. Next we eliminate x2 from equations 3, …, n by subtracting multiples of equation 2 from each of the other equations. To eliminate ...
... statement "bj = bj – mb1". We shall pursue this further as we continue with algorithm. After eliminating x1, the equations 2, …, n, only contain the variables x2, …, xn. Next we eliminate x2 from equations 3, …, n by subtracting multiples of equation 2 from each of the other equations. To eliminate ...