
AGENDAS FOR THE WEEK:
... themselves to share their answers from the worksheet. (Students who would like to eat candy will share their answers). The concept of transformations will be explained further with a PowerPoint using graphs for students to visualize. This will help students connect the vertex forms on their papers t ...
... themselves to share their answers from the worksheet. (Students who would like to eat candy will share their answers). The concept of transformations will be explained further with a PowerPoint using graphs for students to visualize. This will help students connect the vertex forms on their papers t ...
math 1314 exam 2 double click to test - saldivar-epcc
... 16) The amount of paint needed to cover the walls of a room varies jointly as the perimeter of the room and the height of the wall. If a room with a perimeter of 30 feet and 8-foot walls requires 2.4 quarts of paint, find the amount of paint needed to cover the walls of a room with a perimeter of 4 ...
... 16) The amount of paint needed to cover the walls of a room varies jointly as the perimeter of the room and the height of the wall. If a room with a perimeter of 30 feet and 8-foot walls requires 2.4 quarts of paint, find the amount of paint needed to cover the walls of a room with a perimeter of 4 ...
Scheme of Work - Level 2 Award and Level 3 Award in Algebra
... Experience of using letters to represent quantities Understand and recall BIDMAS Substitute positive and negative numbers into algebraic expressions Rearrange to change the subject of a formula LINKS TO LEVEL 2 CONTENT Module 6 ...
... Experience of using letters to represent quantities Understand and recall BIDMAS Substitute positive and negative numbers into algebraic expressions Rearrange to change the subject of a formula LINKS TO LEVEL 2 CONTENT Module 6 ...
College of Engineering and Computer Science Mechanical
... and as given. Provide a general solution and give details of your work. If we define z = y’, the second order equation can be written as y’’ = z’ = 4y’ = 4z. Thus, we have a system of two simultaneous first order equations ...
... and as given. Provide a general solution and give details of your work. If we define z = y’, the second order equation can be written as y’’ = z’ = 4y’ = 4z. Thus, we have a system of two simultaneous first order equations ...