Chapter 8
... 1. Some oxy-acids, when heated, decompose to form water and the nonmetal oxide. Example: Sulfuric acid is heated Example: Nitric acid is heated 2. Some metallic hydroxides (bases), when heated, decompose to form the metal oxide and water. Example: Sodium hydroxide is heated Example: Calcium hydroxid ...
... 1. Some oxy-acids, when heated, decompose to form water and the nonmetal oxide. Example: Sulfuric acid is heated Example: Nitric acid is heated 2. Some metallic hydroxides (bases), when heated, decompose to form the metal oxide and water. Example: Sodium hydroxide is heated Example: Calcium hydroxid ...
Classifying Reactions: A good summary
... 1. This all may seem like too much, but remember, you only need to recognize five out of the eight reactions on any given exam. 2. You earn a point for just writing the reactants in chemical form. 3. Don't forget to cancel out spectators. 4. Get familiar with the chemicals: what are they going to do ...
... 1. This all may seem like too much, but remember, you only need to recognize five out of the eight reactions on any given exam. 2. You earn a point for just writing the reactants in chemical form. 3. Don't forget to cancel out spectators. 4. Get familiar with the chemicals: what are they going to do ...
August 2007
... In an electrolytic cell, 0.061 g of Zn(s) was plated in 10.0 minutes from a solution of ZnCl2(aq). What current was used? ...
... In an electrolytic cell, 0.061 g of Zn(s) was plated in 10.0 minutes from a solution of ZnCl2(aq). What current was used? ...
E:\My Documents\sch4u\SCH4U review McKay answers.wpd
... CH3F, has a higher boiling point because it is polar and has greater London forces. 3) The element iodine exists as solid crystals composed of I2 molecules. A chemist wishing to dissolve iodine has a choice of two solvents; water and tetrachloromethane. Which of these two solvents would be the best ...
... CH3F, has a higher boiling point because it is polar and has greater London forces. 3) The element iodine exists as solid crystals composed of I2 molecules. A chemist wishing to dissolve iodine has a choice of two solvents; water and tetrachloromethane. Which of these two solvents would be the best ...
Topic 20 Organic Chemistry
... 2. Compound A is a bromoalkane. When compound A reacts with warm dilute sodium hydroxide solution an organic compound B is formed which has a relative molar mass of 74.12 and contains 64.81 % carbon, 13.60 % hydrogen and 21.59 % oxygen by mass. Compound B can be oxidised by an acidified solution of ...
... 2. Compound A is a bromoalkane. When compound A reacts with warm dilute sodium hydroxide solution an organic compound B is formed which has a relative molar mass of 74.12 and contains 64.81 % carbon, 13.60 % hydrogen and 21.59 % oxygen by mass. Compound B can be oxidised by an acidified solution of ...
Part II - American Chemical Society
... b. Would the A factor for the chemical reaction NO(g) + N2O(g) → NO2(g) + N2(g) be expected to be larger or smaller than the A factor in the above reaction if each reaction occurs in a single step? Outline your reasoning. c. Calculate the rate constant for this reaction at 75 ˚C. d. The following tw ...
... b. Would the A factor for the chemical reaction NO(g) + N2O(g) → NO2(g) + N2(g) be expected to be larger or smaller than the A factor in the above reaction if each reaction occurs in a single step? Outline your reasoning. c. Calculate the rate constant for this reaction at 75 ˚C. d. The following tw ...
Reactions of Metals and Their Compounds
... Do you remember what they are? • CORE electrons: Electrons that are in full shells. If we use the example of Na (sodium) , the electrons in the first shell ( 2 electrons) and the electrons in the second shell ( 8 electrons) are both found in full shells. These are the core electrons. • VALENCE elec ...
... Do you remember what they are? • CORE electrons: Electrons that are in full shells. If we use the example of Na (sodium) , the electrons in the first shell ( 2 electrons) and the electrons in the second shell ( 8 electrons) are both found in full shells. These are the core electrons. • VALENCE elec ...
KEY Final Exam Review - Iowa State University
... a. What is the rate law for the reaction? k[BF3][NH3] seen by exp 1&2;4&5 b. What is the overall order of the reaction? 2 c. Calculate the Rate constant with proper units. Using exp 1 k=(0.2130)M/s/(0.250M)(0.250M)=3.41M-1s-1 could use any of the five to calculate this. kave=3.408M-1s-1 d. What is t ...
... a. What is the rate law for the reaction? k[BF3][NH3] seen by exp 1&2;4&5 b. What is the overall order of the reaction? 2 c. Calculate the Rate constant with proper units. Using exp 1 k=(0.2130)M/s/(0.250M)(0.250M)=3.41M-1s-1 could use any of the five to calculate this. kave=3.408M-1s-1 d. What is t ...
Gibbs energy approach for aqueous processes with HF, HNO3, and
... The multiphase thermodynamics provide a valuable method for the estimation of the chemical states that are involved in modern pulp and paper processes. These processes are developed in the way that require an ever-smaller input of added chemicals, fresh water and simultaneously increased amount of r ...
... The multiphase thermodynamics provide a valuable method for the estimation of the chemical states that are involved in modern pulp and paper processes. These processes are developed in the way that require an ever-smaller input of added chemicals, fresh water and simultaneously increased amount of r ...
I- Introduction
... The Scope of Analytical Chemistry: Analytical chemistry has bounds which are amongst the widest of any technological discipline. An analyst must be able to design, carry out, and interpret his measurements within the context of the fundamental technological problem with which he is presented. The se ...
... The Scope of Analytical Chemistry: Analytical chemistry has bounds which are amongst the widest of any technological discipline. An analyst must be able to design, carry out, and interpret his measurements within the context of the fundamental technological problem with which he is presented. The se ...
Chemistry Final Exam Review
... • activated complex, activation energy, heat of reaction (∆H) - exothermic vs. endothermic • enthalpy (∆H) - exothermic vs. endothermic ...
... • activated complex, activation energy, heat of reaction (∆H) - exothermic vs. endothermic • enthalpy (∆H) - exothermic vs. endothermic ...
Example 1-2
... convenience, we divide compounds into three categories called soluble, slightly soluble and insoluble. Insoluble is a relative term and does not mean that no solute dissolves! Compounds are classified as insoluble if their solubility is less than 0.1 g/100 mL of water. On the other hand, soluble com ...
... convenience, we divide compounds into three categories called soluble, slightly soluble and insoluble. Insoluble is a relative term and does not mean that no solute dissolves! Compounds are classified as insoluble if their solubility is less than 0.1 g/100 mL of water. On the other hand, soluble com ...
Chem 12 UNIT TWO CHEMICAL EQUILIBRIUM 7.1 REVERSIBLE
... ENTROPY TO CHEMICAL EQUILIBRIUM: These two tendencies decide where the balance will be struck between PRODUCTS and REACTANTS during a chemical or physical change. Entropy and energy (ENTHALPY) determine which side of the reaction wins and how much it wins by... eg. 20% reactants and 80% products at ...
... ENTROPY TO CHEMICAL EQUILIBRIUM: These two tendencies decide where the balance will be struck between PRODUCTS and REACTANTS during a chemical or physical change. Entropy and energy (ENTHALPY) determine which side of the reaction wins and how much it wins by... eg. 20% reactants and 80% products at ...
Net ionic equation
... Net Ionic Equations To this point we have written chemical equations in terms of neutral species (molecules, or formula units). However, in aqueous solution it is often more appropriate to write equations in terms of ions. There are three ways we normally write chemical equations: 1) Molecular equa ...
... Net Ionic Equations To this point we have written chemical equations in terms of neutral species (molecules, or formula units). However, in aqueous solution it is often more appropriate to write equations in terms of ions. There are three ways we normally write chemical equations: 1) Molecular equa ...
Lecture 13 11-20-02
... volume of titrant needed to reach the equivalence point, we draw a vertical line that intersects the x-axis at this volume. Next, we determine the pH for two or three volumes before the equivalence point and for two or three volumes after the equivalence point. To save time we only calculate pH valu ...
... volume of titrant needed to reach the equivalence point, we draw a vertical line that intersects the x-axis at this volume. Next, we determine the pH for two or three volumes before the equivalence point and for two or three volumes after the equivalence point. To save time we only calculate pH valu ...
MC84 - Southchemistry.com
... The reaction of silver metal and dilute nitric acid proceeds according to the equation above. If 0.10 mole of powdered silver is added to 10. milliliters of 6.0-molar nitric acid, the number of moles of NO gas that can be formed is (A) 0.015 mole (B) 0.020 mole (C) 0.030 mole (D) 0.045 mole (E) 0.09 ...
... The reaction of silver metal and dilute nitric acid proceeds according to the equation above. If 0.10 mole of powdered silver is added to 10. milliliters of 6.0-molar nitric acid, the number of moles of NO gas that can be formed is (A) 0.015 mole (B) 0.020 mole (C) 0.030 mole (D) 0.045 mole (E) 0.09 ...
2010 - SAASTA
... changed, the reaction which tends to cancel the effect of the changes will be favoured. In the above example, four moles of gas are converted into 2 moles of gas in the forward reaction and thus when the pressure is increased, the equilibrium will shift in such a way as to decrease the pressure, thu ...
... changed, the reaction which tends to cancel the effect of the changes will be favoured. In the above example, four moles of gas are converted into 2 moles of gas in the forward reaction and thus when the pressure is increased, the equilibrium will shift in such a way as to decrease the pressure, thu ...
Combined
... 1. (a) Sodium hydroxide solution reacts with carbon dioxide gas [1] in air to form sodium carbonate: 2NaOH(aq) + CO2(g) Na2CO3(aq) + H2O(l) [1] The sodium carbonate formed reacts with dilute hydrochloric acid [1] to give colourless bubbles of carbon dioxide gas: Na2CO3(aq) + 2HCl(aq) 2NaCl(aq) + ...
... 1. (a) Sodium hydroxide solution reacts with carbon dioxide gas [1] in air to form sodium carbonate: 2NaOH(aq) + CO2(g) Na2CO3(aq) + H2O(l) [1] The sodium carbonate formed reacts with dilute hydrochloric acid [1] to give colourless bubbles of carbon dioxide gas: Na2CO3(aq) + 2HCl(aq) 2NaCl(aq) + ...