Biological Molecules
... It is activated by the removal of a length of the amino acid chain to leave two chains of amino acids held together by three disulfide bonds. ...
... It is activated by the removal of a length of the amino acid chain to leave two chains of amino acids held together by three disulfide bonds. ...
Syllabus 2012/2013 for Faculty of Medicine (English Division)
... 1. The structure of protein amino acids. 2. Reactions with amino and carboxyl group. Dehydratation of amino acids. 3. The classification of amino acids according to both the polarity and the structural features of their side chains (e. g. polar, nonpolar; aliphatic, aromatic; sulfur-containing; char ...
... 1. The structure of protein amino acids. 2. Reactions with amino and carboxyl group. Dehydratation of amino acids. 3. The classification of amino acids according to both the polarity and the structural features of their side chains (e. g. polar, nonpolar; aliphatic, aromatic; sulfur-containing; char ...
doc Midterm with answers
... B) fibrous proteins can often contain several types of secondary structure, whereas globular proteins usually consist largely of a single type of secondary structure. C) globular proteins are insoluble in water, and fibrous proteins are usually soluble. D) globular proteins are more likely than fibr ...
... B) fibrous proteins can often contain several types of secondary structure, whereas globular proteins usually consist largely of a single type of secondary structure. C) globular proteins are insoluble in water, and fibrous proteins are usually soluble. D) globular proteins are more likely than fibr ...
Problem Set 1 Solution
... in a cell? Explain why you selected this element. You would use radioactive sulphur (S35), which is in the side-chain of methionine. This essential amino acid is usually the first amino acid in most newly synthesized proteins. Sulphur is also present in the side-chains of cysteine, which is one of t ...
... in a cell? Explain why you selected this element. You would use radioactive sulphur (S35), which is in the side-chain of methionine. This essential amino acid is usually the first amino acid in most newly synthesized proteins. Sulphur is also present in the side-chains of cysteine, which is one of t ...
Biochem Midterm - Website of Neelay Gandhi
... B. Proteins are polymers of D-alpha amino acids joined by amide linkages between the carboxyl group of one amino acid and the amino group of its neighbor. C. The alpha helix is a type of tertiary structure D. A and B are both correct. 18. Which of the following is the reason why proline can’t partic ...
... B. Proteins are polymers of D-alpha amino acids joined by amide linkages between the carboxyl group of one amino acid and the amino group of its neighbor. C. The alpha helix is a type of tertiary structure D. A and B are both correct. 18. Which of the following is the reason why proline can’t partic ...
Chapter 2.3: Proteins
... bound by peptide bonds. There is no additional bonding between amino acids. 2.) How does the color of the beads affect polypeptide structure? • The specific order of amino acids (color of beads) determines chemical and bonding properties of ...
... bound by peptide bonds. There is no additional bonding between amino acids. 2.) How does the color of the beads affect polypeptide structure? • The specific order of amino acids (color of beads) determines chemical and bonding properties of ...
II. The Steps of Translation
... At least one kind of tRNA is present for each of the 20 amino acids used in protein synthesis. Some amino acids employ the services of two or three different tRNAs, so most cells contain as many as 32 different kinds of tRNA. The amino acid is attached to the appropriate tRNA by an activating enzyme ...
... At least one kind of tRNA is present for each of the 20 amino acids used in protein synthesis. Some amino acids employ the services of two or three different tRNAs, so most cells contain as many as 32 different kinds of tRNA. The amino acid is attached to the appropriate tRNA by an activating enzyme ...
Amino Acids and Proteins
... • Secondary structure: the ordered arrangements (conformations) of amino acids in localized regions of a polypeptide or protein • To determine from model building which conformations would be of greatest stability, Pauling and Corey assumed that 1. all six atoms of each peptide bond lie in the same ...
... • Secondary structure: the ordered arrangements (conformations) of amino acids in localized regions of a polypeptide or protein • To determine from model building which conformations would be of greatest stability, Pauling and Corey assumed that 1. all six atoms of each peptide bond lie in the same ...
SP12+ P12 (1+2) Urease: determination of inhibitor
... Seminar practicals (SP) and practicals (P) SP1+P1 (1+3) Basic stoichiometry. Preparation of solutions. SP2+ P2 (1+3) Optical methods in medical chemistry. SP3+ P3 (1+3) Gas laws. Ions in solution. Osmotic pressure. ...
... Seminar practicals (SP) and practicals (P) SP1+P1 (1+3) Basic stoichiometry. Preparation of solutions. SP2+ P2 (1+3) Optical methods in medical chemistry. SP3+ P3 (1+3) Gas laws. Ions in solution. Osmotic pressure. ...
Exam II
... 9. (16 pts) Odd carbon number fatty acids leave a breakdown product that is different than that formed from even number fatty acids. What is it? Show how this can be converted into something that can enter a primary metabolic pathway. Draw the mechanism of this/these steps. Propionyl CoA biotin dep ...
... 9. (16 pts) Odd carbon number fatty acids leave a breakdown product that is different than that formed from even number fatty acids. What is it? Show how this can be converted into something that can enter a primary metabolic pathway. Draw the mechanism of this/these steps. Propionyl CoA biotin dep ...
SP12+ P12 (1+2) Urease: determination of inhibitor
... Seminar practicals (SP) and practicals (P) SP1+P1 (1+3) Basic stoichiometry. Preparation of solutions. SP2+ P2 (1+3) Optical methods in medical chemistry. SP3+ P3 (1+3) Gas laws. Ions in solution. Osmotic pressure. ...
... Seminar practicals (SP) and practicals (P) SP1+P1 (1+3) Basic stoichiometry. Preparation of solutions. SP2+ P2 (1+3) Optical methods in medical chemistry. SP3+ P3 (1+3) Gas laws. Ions in solution. Osmotic pressure. ...
Exam II answer key
... 9. (16 pts) Odd carbon number fatty acids leave a breakdown product that is different than that formed from even number fatty acids. What is it? Show how this can be converted into something that can enter a primary metabolic pathway. Draw the mechanism of this/these steps. Propionyl CoA biotin dep ...
... 9. (16 pts) Odd carbon number fatty acids leave a breakdown product that is different than that formed from even number fatty acids. What is it? Show how this can be converted into something that can enter a primary metabolic pathway. Draw the mechanism of this/these steps. Propionyl CoA biotin dep ...
No Slide Title
... Catecholamine synthesis and release are two separate but related processes that influence the level of catecholaminergic neurotransmission. Neuropeptide Y (NPY) is a 36 amino acid peptide that is highly homologous to peptide YY (PYY). NPY exerts its various biological effects through at least six cl ...
... Catecholamine synthesis and release are two separate but related processes that influence the level of catecholaminergic neurotransmission. Neuropeptide Y (NPY) is a 36 amino acid peptide that is highly homologous to peptide YY (PYY). NPY exerts its various biological effects through at least six cl ...
Protein Structure
... that the –OH group has been replaced by an –SH group. That is, it’s like alanine with an -SH attached. Cysteine often forms disulfide bridges with other cysteines, which help stabilize the three dimensional structure of proteins. • Methionine (Met, M) has a linear R group that is 2 carbons, a sulfur ...
... that the –OH group has been replaced by an –SH group. That is, it’s like alanine with an -SH attached. Cysteine often forms disulfide bridges with other cysteines, which help stabilize the three dimensional structure of proteins. • Methionine (Met, M) has a linear R group that is 2 carbons, a sulfur ...
Chem 410 Chapter 11: Polyprotic Acids and Bases Part 1 How
... Although we can draw the amino acid structure as on the left, it doesn’t exist in pure water of pH 7. At a neutral pH, the amino acid undergoes an intramolecular acid/base reaction between the amine group (NH2) and the carboxylic acid group. So the carboxylic acid proton is deprotonated while the am ...
... Although we can draw the amino acid structure as on the left, it doesn’t exist in pure water of pH 7. At a neutral pH, the amino acid undergoes an intramolecular acid/base reaction between the amine group (NH2) and the carboxylic acid group. So the carboxylic acid proton is deprotonated while the am ...
Chemistry of Life Chap 5
... Fats are solid at room temp and are rich in saturated fatty acids. Oils are liquids at room temp and are rich in unsaturated fatty acids. Phospholipids are special lipids in which phosphate replaces one of the 3 fatty acids in fat molecule. They have ionic part usually an amine attached to phosphate ...
... Fats are solid at room temp and are rich in saturated fatty acids. Oils are liquids at room temp and are rich in unsaturated fatty acids. Phospholipids are special lipids in which phosphate replaces one of the 3 fatty acids in fat molecule. They have ionic part usually an amine attached to phosphate ...
L-Arginine A Versatile, Conditionally Essential Amino Acid
... of thousands of metabolically active enzymes. Amino acids provide the body with the nitrogen that is essential for growth and maintenance of all tissues and structures. Proteins and amino acids also serve as a source of energy, providing about 4 calories per gram. Aside from these general functions, ...
... of thousands of metabolically active enzymes. Amino acids provide the body with the nitrogen that is essential for growth and maintenance of all tissues and structures. Proteins and amino acids also serve as a source of energy, providing about 4 calories per gram. Aside from these general functions, ...
STUDY PROBLEMS AND CALCULATIONS: UV/VIS
... Protein A: pI=6.5, Mw=20,000 Da; Protein B: pI=7.8, Mw=20,000 Da; Protein C: pI=6.5, Mw=83,000 Da 8. The following mixture of amino acids was separated by ion-exchange chromatography: Asp (pI=2.77), Cys (pI=4.60), and Phe (pI=5.48). The column was equilibrated with the buffer of pH=2 and eluted with ...
... Protein A: pI=6.5, Mw=20,000 Da; Protein B: pI=7.8, Mw=20,000 Da; Protein C: pI=6.5, Mw=83,000 Da 8. The following mixture of amino acids was separated by ion-exchange chromatography: Asp (pI=2.77), Cys (pI=4.60), and Phe (pI=5.48). The column was equilibrated with the buffer of pH=2 and eluted with ...
Protein synthesis: Twenty three amino acids and
... amino acid, but also cysteine. This was based on a sensitive selection for ‘suppression’ of a mutation of the codon for an essential cysteine in the active site of thymidylate synthase. Mutations that caused such a phenotype were shown to map to the valS gene, which encodes valyltRNA synthetase. The ...
... amino acid, but also cysteine. This was based on a sensitive selection for ‘suppression’ of a mutation of the codon for an essential cysteine in the active site of thymidylate synthase. Mutations that caused such a phenotype were shown to map to the valS gene, which encodes valyltRNA synthetase. The ...
CLW-web page-05
... The stereocontrolled synthesis of oxygen heterocycles is an important goal and our interest in this area stems from the wealth of structural diversity of marine natural products assembled on a tetrahydropyran core. Prins-type cyclisations have the potential to give versatile and efficient approaches ...
... The stereocontrolled synthesis of oxygen heterocycles is an important goal and our interest in this area stems from the wealth of structural diversity of marine natural products assembled on a tetrahydropyran core. Prins-type cyclisations have the potential to give versatile and efficient approaches ...
Supplementary Methods
... antagomirs. i.e., cholesterol conjugated RNAs, the synthesis started from a controlledpore glass solid support carrying a cholesterol- hydroxyprolinol linker2. Antagomirs with phosphorothioate backbone at a given position were achieved by oxidation of phosphite with phenylacetyl disulfide (PADS) dur ...
... antagomirs. i.e., cholesterol conjugated RNAs, the synthesis started from a controlledpore glass solid support carrying a cholesterol- hydroxyprolinol linker2. Antagomirs with phosphorothioate backbone at a given position were achieved by oxidation of phosphite with phenylacetyl disulfide (PADS) dur ...
WEEK 10
... nitrogen and carbon form stable multiple bonds. Carbon can bond to oxygen by a double bond either within a biological compound or in the gaseous substance carbon dioxide, a waste product produced by many living organisms. Carbon also bonds very stably to hydrogen and to nitrogen. O2 is vital to many ...
... nitrogen and carbon form stable multiple bonds. Carbon can bond to oxygen by a double bond either within a biological compound or in the gaseous substance carbon dioxide, a waste product produced by many living organisms. Carbon also bonds very stably to hydrogen and to nitrogen. O2 is vital to many ...
Macromolecules
... ladder. Nucleotides within each strand are joined by covalent phosphodiester bonds (-OP-O-) in a condensation reaction. Each nucleotide subunit is made of a modified ribose sugar molecule (called deoxyribose as it has lost an oxygen) joined to a phosphate group and one of four bases (adenine, A; gua ...
... ladder. Nucleotides within each strand are joined by covalent phosphodiester bonds (-OP-O-) in a condensation reaction. Each nucleotide subunit is made of a modified ribose sugar molecule (called deoxyribose as it has lost an oxygen) joined to a phosphate group and one of four bases (adenine, A; gua ...
Course Name:
... Have the knowledge of relating to the structure of the biomolecules to their function in the cell. Have the knowledge of the interactions of the biological molecules. Have an understanding of the relation of the structure of biological molecules and their function and interaction with each other. Ha ...
... Have the knowledge of relating to the structure of the biomolecules to their function in the cell. Have the knowledge of the interactions of the biological molecules. Have an understanding of the relation of the structure of biological molecules and their function and interaction with each other. Ha ...
