
Constructing A Square
... not going to have 3 90° angles like a square has 4 90° angles. So, the first step I would take is to know regular polygons, the sides and angles that are included in the shape. The second step I would take is to play around with the tools to construct equal sided and equal angled figures. Extension ...
... not going to have 3 90° angles like a square has 4 90° angles. So, the first step I would take is to know regular polygons, the sides and angles that are included in the shape. The second step I would take is to play around with the tools to construct equal sided and equal angled figures. Extension ...
Chapter 6 Test Review
... Assume that ABC is a right triangle with hypotenuse AB. Solve the right triangle completely, leaving angles in degrees-minutes (to the nearest minute) or degree-decimal (to the nearest tenth) as indicated in the problem. Round side lengths to three decimal places. 1. B 56 48', c 63.1 ...
... Assume that ABC is a right triangle with hypotenuse AB. Solve the right triangle completely, leaving angles in degrees-minutes (to the nearest minute) or degree-decimal (to the nearest tenth) as indicated in the problem. Round side lengths to three decimal places. 1. B 56 48', c 63.1 ...
Weber problem

In geometry, the Weber problem, named after Alfred Weber, is one of the most famous problems in location theory. It requires finding a point in the plane that minimizes the sum of the transportation costs from this point to n destination points, where different destination points are associated with different costs per unit distance.The Weber problem generalizes the geometric median, which assumes transportation costs per unit distance are the same for all destination points, and the problem of computing the Fermat point, the geometric median of three points. For this reason it is sometimes called the Fermat–Weber problem, although the same name has also been used for the unweighted geometric median problem. The Weber problem is in turn generalized by the attraction–repulsion problem, which allows some of the costs to be negative, so that greater distance from some points is better.