The decomposition of hydrogen peroxide to form water and oxygen
... and well organized. Specific answers are preferable to broad, diffuse responses. For calculations, clearly show the method used and the steps involved in arriving at your answers. It is to your advantage to do this, since you may obtain partial credit if you do and you will receive little or no cred ...
... and well organized. Specific answers are preferable to broad, diffuse responses. For calculations, clearly show the method used and the steps involved in arriving at your answers. It is to your advantage to do this, since you may obtain partial credit if you do and you will receive little or no cred ...
X012/12/02
... colour just appears, stop the timer and record the time (in seconds). 4. Repeat this procedure four times but each time use a different concentration of potassium iodide solution. (i) In step 4 of the procedure, what should be done to obtain potassium iodide solutions of different concentration ...
... colour just appears, stop the timer and record the time (in seconds). 4. Repeat this procedure four times but each time use a different concentration of potassium iodide solution. (i) In step 4 of the procedure, what should be done to obtain potassium iodide solutions of different concentration ...
O 2 (g) - Valdosta State University
... Summary: Matter and Energy Dispersal • A final state of a system can be more probable than the initial state if: – The atoms and molecules can be more ____________ and/or – ___________ can be dispersed over a greater number of atoms and molecules. ...
... Summary: Matter and Energy Dispersal • A final state of a system can be more probable than the initial state if: – The atoms and molecules can be more ____________ and/or – ___________ can be dispersed over a greater number of atoms and molecules. ...
Word - chemmybear.com
... Sn° and gases like O2, F2, Cl2 the ions usually form oxidize to the “-ic” ion. Example: 2Fe°(s) + 3Cl2(g) + heat 2FeCl3(s) 2. When you identify an oxidation product, make certain you also have a reduction product. Ex: “Free halogens + dilute OH- hypohalite ions," the halide ions (such as Cl-) as a p ...
... Sn° and gases like O2, F2, Cl2 the ions usually form oxidize to the “-ic” ion. Example: 2Fe°(s) + 3Cl2(g) + heat 2FeCl3(s) 2. When you identify an oxidation product, make certain you also have a reduction product. Ex: “Free halogens + dilute OH- hypohalite ions," the halide ions (such as Cl-) as a p ...
Questions 3-4 from AP exam 2006
... 2006 AP® CHEMISTRY FREE-RESPONSE QUESTIONS 3. Answer the following questions that relate to the analysis of chemical compounds. (a) A compound containing the elements C , H , N , and O is analyzed. When a 1.2359 g sample is burned in excess oxygen, 2.241 g of CO2(g) is formed. The combustion analys ...
... 2006 AP® CHEMISTRY FREE-RESPONSE QUESTIONS 3. Answer the following questions that relate to the analysis of chemical compounds. (a) A compound containing the elements C , H , N , and O is analyzed. When a 1.2359 g sample is burned in excess oxygen, 2.241 g of CO2(g) is formed. The combustion analys ...
Towards a Theory of Organizations
... statements. It intends to give a means for describing organization in systems with a maximum of accuracy, independent of their constituting parts, be they molecules, symbols of communication, or departments of a company. These exact statements shall be applied to five examples of systems, stemming f ...
... statements. It intends to give a means for describing organization in systems with a maximum of accuracy, independent of their constituting parts, be they molecules, symbols of communication, or departments of a company. These exact statements shall be applied to five examples of systems, stemming f ...
S - Valdosta State University
... property of the system. Often at equilibrium. – Here entropy can be obtained at any T by measuring the heat required rise the temperature from 0K, with the slow addition of heat in very small amounts. – DS = qrev/T ...
... property of the system. Often at equilibrium. – Here entropy can be obtained at any T by measuring the heat required rise the temperature from 0K, with the slow addition of heat in very small amounts. – DS = qrev/T ...
chem 13 news 2010 - University of Waterloo
... 5. Carefully detach the last page. It is the datasheet. 6. Now answer the exam questions. Questions are not in order of difficulty. Indicate your choice on the STUDENT RESPONSE sheet by marking one letter beside the question number. • Mark only one answer for each question. • Questions are all of th ...
... 5. Carefully detach the last page. It is the datasheet. 6. Now answer the exam questions. Questions are not in order of difficulty. Indicate your choice on the STUDENT RESPONSE sheet by marking one letter beside the question number. • Mark only one answer for each question. • Questions are all of th ...
Sample Exercise 19.1 Identifying Spontaneous Processes
... (a) Equation 19.12 tells us that ΔG° is the sum of the enthalpy term ΔH° and the entropy term –T ΔS°. The temperature dependence of ΔG° comes from the entropy term. We expect ΔS° for this reaction to be negative because the number of molecules of gas is smaller in the products. Because ΔS° is negati ...
... (a) Equation 19.12 tells us that ΔG° is the sum of the enthalpy term ΔH° and the entropy term –T ΔS°. The temperature dependence of ΔG° comes from the entropy term. We expect ΔS° for this reaction to be negative because the number of molecules of gas is smaller in the products. Because ΔS° is negati ...
chapter 6: chemical reactions: an introduction
... The starting materials are called reactants and are shown on the left side of the chemical equation. The substances formed in a reaction are called products and are shown on the right side of the equation. The same kinds of atoms must be present before and after a chemical reaction because atoms are ...
... The starting materials are called reactants and are shown on the left side of the chemical equation. The substances formed in a reaction are called products and are shown on the right side of the equation. The same kinds of atoms must be present before and after a chemical reaction because atoms are ...
Chemistry Unit Summaries - Oak Park Unified School District
... atoms and proposed a model that explains its atomic spectrum. Atoms are the basic building blocks of matter; they are the In this model the energy of the hydrogen atom depends on the smallest units of an element that can combine with other value of its quantum number n, where En = -2.18 x 1018 J/n2. ...
... atoms and proposed a model that explains its atomic spectrum. Atoms are the basic building blocks of matter; they are the In this model the energy of the hydrogen atom depends on the smallest units of an element that can combine with other value of its quantum number n, where En = -2.18 x 1018 J/n2. ...
Energetics 5
... A few reactions are endothermic as they result in an energy transfer from the surroundings to the system. In this case the products have more heat content than the reactants and $H is positive. The thermochemical equation for photosynthesis, for example, can be represented as: 6CO2(g) 6H2O(l) → C6 ...
... A few reactions are endothermic as they result in an energy transfer from the surroundings to the system. In this case the products have more heat content than the reactants and $H is positive. The thermochemical equation for photosynthesis, for example, can be represented as: 6CO2(g) 6H2O(l) → C6 ...
2010 `A` Levels Suggested Solutions
... This reaction is unusual as you’ve been taught that alcohols are neutral. But note that the use of conc HCl is to remove the organic impurity that cannot be separate by Step 5. The ONLY organic reactant used is butan-1-ol making it the only possible candidate as the organic impure that the question ...
... This reaction is unusual as you’ve been taught that alcohols are neutral. But note that the use of conc HCl is to remove the organic impurity that cannot be separate by Step 5. The ONLY organic reactant used is butan-1-ol making it the only possible candidate as the organic impure that the question ...
Combining the Benefits of Homogeneous and Heterogeneous
... In addition, OATS systems have been used for enzyme-catalyzed reactions. Enzymes function at moderate temperatures and provide synthetic approaches that may otherwise require multiple steps using less selective and active metal-catalysts. However, their applications are largely limited to aqueous me ...
... In addition, OATS systems have been used for enzyme-catalyzed reactions. Enzymes function at moderate temperatures and provide synthetic approaches that may otherwise require multiple steps using less selective and active metal-catalysts. However, their applications are largely limited to aqueous me ...
Redox I
... Reactions in Basic solution If the redox reaction takes place in BASIC solution, use steps 1-6 (as before) to balance the equation as if it took place in acidic solution. Then perform one more step: Step 7. (ONLY for redox reactions taking place in basic solution!) Add OH- to BOTH sides of the equat ...
... Reactions in Basic solution If the redox reaction takes place in BASIC solution, use steps 1-6 (as before) to balance the equation as if it took place in acidic solution. Then perform one more step: Step 7. (ONLY for redox reactions taking place in basic solution!) Add OH- to BOTH sides of the equat ...
Slide 1
... The temperature dependence of ΔG° comes from the entropy term. We expect ΔS° for this reaction to be negative because the number of molecules of gas is smaller in the products. Because ΔS° is negative, the term –T ΔS° is positive and grows larger with increasing temperature. As a result, ΔG° becomes ...
... The temperature dependence of ΔG° comes from the entropy term. We expect ΔS° for this reaction to be negative because the number of molecules of gas is smaller in the products. Because ΔS° is negative, the term –T ΔS° is positive and grows larger with increasing temperature. As a result, ΔG° becomes ...
19 BROWN Chemical Thermodynamics PPTSExercise
... The temperature dependence of ΔG° comes from the entropy term. We expect ΔS° for this reaction to be negative because the number of molecules of gas is smaller in the products. Because ΔS° is negative, the term –T ΔS° is positive and grows larger with increasing temperature. As a result, ΔG° becomes ...
... The temperature dependence of ΔG° comes from the entropy term. We expect ΔS° for this reaction to be negative because the number of molecules of gas is smaller in the products. Because ΔS° is negative, the term –T ΔS° is positive and grows larger with increasing temperature. As a result, ΔG° becomes ...
Equilibrium STUDY GUIDE by Keshara Senanayake ---
... If both sides have equal # of moles of gas a shift in either direction will not reduce the pressure. So a increase in pressure has no effect on the equilibrium situation. So an equilibrium reaction that has the same number of moles of gas on both sides of the equation will not be affected by the cha ...
... If both sides have equal # of moles of gas a shift in either direction will not reduce the pressure. So a increase in pressure has no effect on the equilibrium situation. So an equilibrium reaction that has the same number of moles of gas on both sides of the equation will not be affected by the cha ...
Chapter 7 lecture notes: Solutions
... Water is a unique solvent because so many substances can dissolve in it. ...
... Water is a unique solvent because so many substances can dissolve in it. ...