Chapter 6 - Sites @ Suffolk University
... "molecular" is somewhat misleading. For that reason, the term "gram formula mass" is often used instead; it has, however, no convenient abbreviated form, and chemists will often be found referring to "grams per mole ammonium sulfate" even though purists may frown. Chemists make frequent use of the c ...
... "molecular" is somewhat misleading. For that reason, the term "gram formula mass" is often used instead; it has, however, no convenient abbreviated form, and chemists will often be found referring to "grams per mole ammonium sulfate" even though purists may frown. Chemists make frequent use of the c ...
Chapter 16: Reaction Rates
... Collision orientation and the activated complex Why do most collisions fail to produce products? What other factors must be considered? Figure 16.4a and b show one possible answer to this question. These illustrations indicate that in order for a collision to lead to a reaction, the carbon atom in a ...
... Collision orientation and the activated complex Why do most collisions fail to produce products? What other factors must be considered? Figure 16.4a and b show one possible answer to this question. These illustrations indicate that in order for a collision to lead to a reaction, the carbon atom in a ...
g - Highline Community College
... • Solid or Liquid = pure solid or liquid in its most stable form at exactly 1 atm pressure and temperature of interest usually 25 °C ...
... • Solid or Liquid = pure solid or liquid in its most stable form at exactly 1 atm pressure and temperature of interest usually 25 °C ...
STOICHIOMETRY
... theoretical yield Often, either accidentally or deliberately, one of the reagents in a reaction is present in excess while another reagent is the limiting reagent, i.e., there is not enough of it to use up all the reagent which is in excess. Only the quantity of limiting reagent can be used to d ...
... theoretical yield Often, either accidentally or deliberately, one of the reagents in a reaction is present in excess while another reagent is the limiting reagent, i.e., there is not enough of it to use up all the reagent which is in excess. Only the quantity of limiting reagent can be used to d ...
A Classification of AP Chemistry Reactions
... The second type of redox that involve oxygen-containing compounds such as nitrates, sulfates, permanganates, dichromates, etc. First of all, since these are redox reactions, one thing must be oxidized and another must be reduced. Jotting down oxidation numbers can be helpful. Second, almost all of t ...
... The second type of redox that involve oxygen-containing compounds such as nitrates, sulfates, permanganates, dichromates, etc. First of all, since these are redox reactions, one thing must be oxidized and another must be reduced. Jotting down oxidation numbers can be helpful. Second, almost all of t ...
Chapter 7
... Matter. Calculate H for the process in which 50.0 g of water is converted from liquid at 10.0°C to vapor at 25.0°C. Break the problem into two steps: Raise the temperature of the liquid first then completely vaporize it. The total enthalpy change is the sum of the changes in each step. ...
... Matter. Calculate H for the process in which 50.0 g of water is converted from liquid at 10.0°C to vapor at 25.0°C. Break the problem into two steps: Raise the temperature of the liquid first then completely vaporize it. The total enthalpy change is the sum of the changes in each step. ...
practice spring final exam
... 36. How much space do 5.7x1028 molecules of oxygen gas occupy? (A) 4227 L (B) 2.1x106 mL (C) 1.53x1051 L (D) 2.1x106 L 37. The mass of one mole of Ca(OH)2 is: (A) 29 g (B) 38 g (C) 57 g (D) 74 g 38. How many moles are in 100 g of O2 gas? (A) 1 mol (B) 1.3 mol (C) 3.1 mol (D) 6.3 mol 39. You have 3 L ...
... 36. How much space do 5.7x1028 molecules of oxygen gas occupy? (A) 4227 L (B) 2.1x106 mL (C) 1.53x1051 L (D) 2.1x106 L 37. The mass of one mole of Ca(OH)2 is: (A) 29 g (B) 38 g (C) 57 g (D) 74 g 38. How many moles are in 100 g of O2 gas? (A) 1 mol (B) 1.3 mol (C) 3.1 mol (D) 6.3 mol 39. You have 3 L ...
Document
... limiting reactant, and the theoretical yield of ammonia is 49.0 g. CHECK The units of the answer (g NH3) are correct. The magnitude (49.0 g) seems reasonable given that 86.3 g NO is the limiting reactant. NO contains one oxygen atom per nitrogen atom and NH 3 contains three hydrogen atoms per nitrog ...
... limiting reactant, and the theoretical yield of ammonia is 49.0 g. CHECK The units of the answer (g NH3) are correct. The magnitude (49.0 g) seems reasonable given that 86.3 g NO is the limiting reactant. NO contains one oxygen atom per nitrogen atom and NH 3 contains three hydrogen atoms per nitrog ...
aq - Byron High School
... Solve: (a) When bonded to a nonmetal, hydrogen has an oxidation number of +1 (rule 3b). Because the H2S molecule is neutral, the sum of the oxidation numbers must equal zero (rule 4). Letting x equal the oxidation number of S, we have 2(+1) + x = 0. Thus, S has an oxidation number of –2. (b) Because ...
... Solve: (a) When bonded to a nonmetal, hydrogen has an oxidation number of +1 (rule 3b). Because the H2S molecule is neutral, the sum of the oxidation numbers must equal zero (rule 4). Letting x equal the oxidation number of S, we have 2(+1) + x = 0. Thus, S has an oxidation number of –2. (b) Because ...
Chapter 8 Quantities in Chemical Reactions
... • MTBE (methyl tertiary butyl ether, CH3OC(CH3)3) was the additive of choice by the oil companies. • MTBE is a compound that does not biodegrade readily. • MTBE made its way into drinking water through gasoline spills at gas stations, from boat motors, and from leaking underground storage tanks. • E ...
... • MTBE (methyl tertiary butyl ether, CH3OC(CH3)3) was the additive of choice by the oil companies. • MTBE is a compound that does not biodegrade readily. • MTBE made its way into drinking water through gasoline spills at gas stations, from boat motors, and from leaking underground storage tanks. • E ...
Acid Base Equilibria
... Note: Some substances can act as an acid in one reaction and as a base in another, e.g. Water is a Bronsted – Lowry base in its reaction with HCl and a Bronsted – Lowry acid in its reaction with NH3. Such substances are said to AMPHOTERIC. Conjugate acid – base pairs Conjugate acids and bases is ano ...
... Note: Some substances can act as an acid in one reaction and as a base in another, e.g. Water is a Bronsted – Lowry base in its reaction with HCl and a Bronsted – Lowry acid in its reaction with NH3. Such substances are said to AMPHOTERIC. Conjugate acid – base pairs Conjugate acids and bases is ano ...
Chapter_4_Reactions_in_Aqueous_Solution
... (a) By rule 2 we see that lithium has an oxidation number of +1 (Li+) and oxygen’s oxidation number is −2 (O2−). (b) This is the formula for nitric acid, which yields a H+ ion and a N ion in solution. From rule 4 we see that H has an oxidation number of +1. Thus the other group (the nitrate ion) mus ...
... (a) By rule 2 we see that lithium has an oxidation number of +1 (Li+) and oxygen’s oxidation number is −2 (O2−). (b) This is the formula for nitric acid, which yields a H+ ion and a N ion in solution. From rule 4 we see that H has an oxidation number of +1. Thus the other group (the nitrate ion) mus ...
aq - Moodle@FCT
... (a) By rule 2 we see that lithium has an oxidation number of +1 (Li+) and oxygen’s oxidation number is −2 (O2−). (b) This is the formula for nitric acid, which yields a H+ ion and a N ion in solution. From rule 4 we see that H has an oxidation number of +1. Thus the other group (the nitrate ion) mus ...
... (a) By rule 2 we see that lithium has an oxidation number of +1 (Li+) and oxygen’s oxidation number is −2 (O2−). (b) This is the formula for nitric acid, which yields a H+ ion and a N ion in solution. From rule 4 we see that H has an oxidation number of +1. Thus the other group (the nitrate ion) mus ...
Activation of Nitrous Oxide and Selective Epoxidation of Alkenes
... There is ongoing interest in oxidation catalyzed by polyoxometalates (POMs).10 Here, we describe the activation of N2O by a Mn(III)-substituted polyoxometalate, Q10[MnIII2ZnW(ZnW9O34)2] (Q ) (C8H17)3CH3N+), Figure 1, and subsequent highly selective catalytic epoxidation of alkenes. Previously, it wa ...
... There is ongoing interest in oxidation catalyzed by polyoxometalates (POMs).10 Here, we describe the activation of N2O by a Mn(III)-substituted polyoxometalate, Q10[MnIII2ZnW(ZnW9O34)2] (Q ) (C8H17)3CH3N+), Figure 1, and subsequent highly selective catalytic epoxidation of alkenes. Previously, it wa ...
Thermodynamics and Equilibrium
... spontaneously because doing so lowers its energy, but it does not move back up the hill spontaneously because an input of energy is required to do so. Thus, it would be tempting to conclude that processes should be spontaneous if they are exothermic. However, there are many examples of spontaneous e ...
... spontaneously because doing so lowers its energy, but it does not move back up the hill spontaneously because an input of energy is required to do so. Thus, it would be tempting to conclude that processes should be spontaneous if they are exothermic. However, there are many examples of spontaneous e ...
Chemistry - Birkenhead School
... Visualise and represent 2D and 3D forms including two dimensional representations of 3D objects. Content Opportunities for skills development Students should be able to: draw dot and cross diagrams for the molecules H2, Cl2, O2, N2, HCl, H2O, NH3 and CH4 represent the covalent bonds in small mol ...
... Visualise and represent 2D and 3D forms including two dimensional representations of 3D objects. Content Opportunities for skills development Students should be able to: draw dot and cross diagrams for the molecules H2, Cl2, O2, N2, HCl, H2O, NH3 and CH4 represent the covalent bonds in small mol ...
Chapter 14 Review
... A. Increasing the system volume shifts the equilibrium to the right. B. Increasing the temperature shifts the equilibrium to the right. C. A catalyst speeds up the approach to equilibrium and shifts the position of equilibrium to the right. D. Decreasing the total pressure of the system shifts the e ...
... A. Increasing the system volume shifts the equilibrium to the right. B. Increasing the temperature shifts the equilibrium to the right. C. A catalyst speeds up the approach to equilibrium and shifts the position of equilibrium to the right. D. Decreasing the total pressure of the system shifts the e ...