File
... 18. The combustion of ammonia in the presence of excess oxygen yields NO2 and H2O: 4 NH3 (g) + 7 O2 (g) → 4 NO2 (g) + 6 H2O (g) The combustion of 43.9 g of ammonia produces __________ g of NO2. A) 2.58 B) 178 C) 119 D) 0.954 19. What are the respective concentrations (M) of Fe3+ and I- afforded by ...
... 18. The combustion of ammonia in the presence of excess oxygen yields NO2 and H2O: 4 NH3 (g) + 7 O2 (g) → 4 NO2 (g) + 6 H2O (g) The combustion of 43.9 g of ammonia produces __________ g of NO2. A) 2.58 B) 178 C) 119 D) 0.954 19. What are the respective concentrations (M) of Fe3+ and I- afforded by ...
Exercise II
... This is known as a symmetrical or identity reaction since both the reactants (Cl, + CH3 Cl) and products (CH3 Cl + Cl, ) are identical. However, more general reactions involving different attacking and leaving groups form the basis of this reaction. The restriction of having identical attacking and ...
... This is known as a symmetrical or identity reaction since both the reactants (Cl, + CH3 Cl) and products (CH3 Cl + Cl, ) are identical. However, more general reactions involving different attacking and leaving groups form the basis of this reaction. The restriction of having identical attacking and ...
CHEM 30 REDOX
... from the knob -- the more the operator must turn the knob to return it to rest, the greater the level of alcohol. ...
... from the knob -- the more the operator must turn the knob to return it to rest, the greater the level of alcohol. ...
Chapter 4
... added gradually added to another solution of unknown concentration until the chemical reaction between the two solutions is complete. Equivalence point – the point at which the reaction is complete Indicator – substance that changes color at (or near) the ...
... added gradually added to another solution of unknown concentration until the chemical reaction between the two solutions is complete. Equivalence point – the point at which the reaction is complete Indicator – substance that changes color at (or near) the ...
AP Electrochemistry Class Packet Unit 10
... 3.C.3 Electrochemistry shows the interconversion between chemical and electrical energy in galvanic and electrolytic cells. 6.A.4 The magnitude of the equilibrium constant K, can be used to determine whether the equilibrium lies toward the reactant side or the product side. 6.A.2 The current s ...
... 3.C.3 Electrochemistry shows the interconversion between chemical and electrical energy in galvanic and electrolytic cells. 6.A.4 The magnitude of the equilibrium constant K, can be used to determine whether the equilibrium lies toward the reactant side or the product side. 6.A.2 The current s ...
Test 8 Review
... devised a model. The model is called an ideal gas (a gas which explains the behavior of all gases). This Ideal Gas Kinetic theory of gases (under ideal circumstances) model is based on the assumptions to the right, and can be 1. Gas are composed of particles that are in constant, rapid, random, line ...
... devised a model. The model is called an ideal gas (a gas which explains the behavior of all gases). This Ideal Gas Kinetic theory of gases (under ideal circumstances) model is based on the assumptions to the right, and can be 1. Gas are composed of particles that are in constant, rapid, random, line ...
chem16 part2 lect1 thermodynamics
... • The entropy of a pure, perfect, crystalline solid at 0 K is zero. • This law permits us to measure the absolute values of the entropy for substances. – To get the actual value of S, cool a substance to 0 K, or as close as possible, then measure the entropy increase as the substance heats from 0 to ...
... • The entropy of a pure, perfect, crystalline solid at 0 K is zero. • This law permits us to measure the absolute values of the entropy for substances. – To get the actual value of S, cool a substance to 0 K, or as close as possible, then measure the entropy increase as the substance heats from 0 to ...
GCSE ADDITIONAL CHEMISTRY (C2) REVISION BOOKLET
... malleable/brittle because the layers can/cannot slide over each other. This is because as the distortion to the metal lattice occurs, the electrons/ions can also move and hold the metal molecules/ions together. Nanoparticles are very small/large particles that have properties different from/the same ...
... malleable/brittle because the layers can/cannot slide over each other. This is because as the distortion to the metal lattice occurs, the electrons/ions can also move and hold the metal molecules/ions together. Nanoparticles are very small/large particles that have properties different from/the same ...
Curriculum Plan
... Describe the factors that affect reaction rate in terms of collision theory, Explain the concept of activation energy and activated complex, Define entropy, Describe an increase in the entropy of the universe as a driving force (2nd law of thermodynamics), Create and recognize an energy diagram for ...
... Describe the factors that affect reaction rate in terms of collision theory, Explain the concept of activation energy and activated complex, Define entropy, Describe an increase in the entropy of the universe as a driving force (2nd law of thermodynamics), Create and recognize an energy diagram for ...
Chapter 9 Stoichiometry
... Enthalpy is the amount of heat that a substance has at a given temperature and pressure (see Table 8.1 pg 190) The heat of a reaction is the heat that is released or absorbed during a chemical reaction. Heat of Reaction is represented by The symbol H ...
... Enthalpy is the amount of heat that a substance has at a given temperature and pressure (see Table 8.1 pg 190) The heat of a reaction is the heat that is released or absorbed during a chemical reaction. Heat of Reaction is represented by The symbol H ...
CHEM1100 Practice Exam 2 You have 120 minutes to complete this
... CHEM1100 Practice Exam 2 You have 120 minutes to complete this exam. Answer all questions. To receive credit you must show your reasoning and all calculations in the bluebook. Report numerical answers with the correct number of significant figures and with correct units. No speaking is allowed durin ...
... CHEM1100 Practice Exam 2 You have 120 minutes to complete this exam. Answer all questions. To receive credit you must show your reasoning and all calculations in the bluebook. Report numerical answers with the correct number of significant figures and with correct units. No speaking is allowed durin ...
Chemistry- CST Review
... 1. What causes gas pressure in terms of kinetic theory? Gas pressure is caused by the random motion of the gas molecules. 2. If someone sprays perfume at the front of the room, will the people in the back of the room eventually be able to smell it? Why? Explain completely. Yes, the perfume will be s ...
... 1. What causes gas pressure in terms of kinetic theory? Gas pressure is caused by the random motion of the gas molecules. 2. If someone sprays perfume at the front of the room, will the people in the back of the room eventually be able to smell it? Why? Explain completely. Yes, the perfume will be s ...
Semester Exam Review
... (c) How long must the reaction proceed to produce a concentration of Z equal to 0.20 molar, if the initial reaction concentrations are [X]o = 0.80 molar, [Y]o = 0.60 molar and [Z]0 = 0 molar? (d) Select from the mechanisms below the one most consistent with the observed data, and explain your choice ...
... (c) How long must the reaction proceed to produce a concentration of Z equal to 0.20 molar, if the initial reaction concentrations are [X]o = 0.80 molar, [Y]o = 0.60 molar and [Z]0 = 0 molar? (d) Select from the mechanisms below the one most consistent with the observed data, and explain your choice ...
Ch. 16 Study Guide
... 13. Pure solids and pure liquids are not included in the equilibrium constant expression. 14. Equilibrium constants are unitless even though molarity concentrations or partial pressures are used to calculate them. ...
... 13. Pure solids and pure liquids are not included in the equilibrium constant expression. 14. Equilibrium constants are unitless even though molarity concentrations or partial pressures are used to calculate them. ...
Ionic Equations
... sodium hydroxide and calcium bromide to give calcium hydroxide and sodium bromide ...
... sodium hydroxide and calcium bromide to give calcium hydroxide and sodium bromide ...
CHEM 481. Assignment 0. Review of General Chemistry. Answers
... 16. Calcium carbide, CaC2, is manufactured by reducing lime (CaO) with carbon at a high temperature. (The carbide is used to make acetylene, an industrially important organic chemical.) ∆ H° rxn = +464.8 kJ CaO(s) + 3 C(s) Æ CaC2(s) + CO(g) Is the reaction endothermic or exothermic? If 10.0 g of CaO ...
... 16. Calcium carbide, CaC2, is manufactured by reducing lime (CaO) with carbon at a high temperature. (The carbide is used to make acetylene, an industrially important organic chemical.) ∆ H° rxn = +464.8 kJ CaO(s) + 3 C(s) Æ CaC2(s) + CO(g) Is the reaction endothermic or exothermic? If 10.0 g of CaO ...
Answers to Assignment #1
... 16. Calcium carbide, CaC2, is manufactured by reducing lime (CaO) with carbon at a high temperature. (The carbide is used to make acetylene, an industrially important organic chemical.) CaO(s) + 3 C(s) à CaC2(s) + CO(g) ∆ H° rxn = +464.8 kJ Is the reaction endothermic or exothermic? If 10.0 g of CaO ...
... 16. Calcium carbide, CaC2, is manufactured by reducing lime (CaO) with carbon at a high temperature. (The carbide is used to make acetylene, an industrially important organic chemical.) CaO(s) + 3 C(s) à CaC2(s) + CO(g) ∆ H° rxn = +464.8 kJ Is the reaction endothermic or exothermic? If 10.0 g of CaO ...
Chapter 13…States of Matter
... 4. Calculate the amount of energy required to heat a 150 g chunk of aluminum from 20C to 40C. (Cp of aluminum = 0.220 cal/gC) H=mCpT (150g)(.22)(20) = 660 cal Chapters 17& 18…Reaction Rates & Equilibrium Define: 1. Equilibrium: the reaction occurs simultaneously in both directions. 2. Activate ...
... 4. Calculate the amount of energy required to heat a 150 g chunk of aluminum from 20C to 40C. (Cp of aluminum = 0.220 cal/gC) H=mCpT (150g)(.22)(20) = 660 cal Chapters 17& 18…Reaction Rates & Equilibrium Define: 1. Equilibrium: the reaction occurs simultaneously in both directions. 2. Activate ...
Slide 1 of 24
... Hindenburg erupted into a fireball. Within a short time, 210,000 cubic meters of hydrogen had burned and the airship was destroyed. The chemical reaction that occurred is “hydrogen combines with oxygen to produce water.” You will learn to represent this chemical reaction by a chemical equation. Slid ...
... Hindenburg erupted into a fireball. Within a short time, 210,000 cubic meters of hydrogen had burned and the airship was destroyed. The chemical reaction that occurred is “hydrogen combines with oxygen to produce water.” You will learn to represent this chemical reaction by a chemical equation. Slid ...