chapter 21 chemistry of the main-group elements i
... MgF2 vs. MgCl2 solubility in water. F is smaller than Cl, hence, electrostatic attraction between Mg2+ and the halide is greater in F than Cl. If we assume that hydration of the ions is similar, we expect that MgF2 is less soluble than MgCl2. (Note: Ksp given for MgF2, which is sparingly soluble ...
... MgF2 vs. MgCl2 solubility in water. F is smaller than Cl, hence, electrostatic attraction between Mg2+ and the halide is greater in F than Cl. If we assume that hydration of the ions is similar, we expect that MgF2 is less soluble than MgCl2. (Note: Ksp given for MgF2, which is sparingly soluble ...
Answers to Selected Exercises
... oxidation number decreases. 3.35 Metals in region A are most easily oxidised. Nonmetals in region D are least easily oxidised. 3.37 (a) +4 (b) +4 (c) +7 (d) +1 (e) 0 (f) -1 3.39 (a) Ni ¡ Ni 2+, Ni is oxidised; Cl2 ¡ 2 Cl -, Cl is reduced (b) Fe 2+ ¡ Fe, Fe is reduced; Al ¡ Al3+, Al is oxidised (c) C ...
... oxidation number decreases. 3.35 Metals in region A are most easily oxidised. Nonmetals in region D are least easily oxidised. 3.37 (a) +4 (b) +4 (c) +7 (d) +1 (e) 0 (f) -1 3.39 (a) Ni ¡ Ni 2+, Ni is oxidised; Cl2 ¡ 2 Cl -, Cl is reduced (b) Fe 2+ ¡ Fe, Fe is reduced; Al ¡ Al3+, Al is oxidised (c) C ...
Pdf - Text of NPTEL IIT Video Lectures
... components remains same; or it can be defined as, the rate of change of enthalpy with respect to the number of moles of that particular component for which the chemical potential is defined when the entropy pressure and the number of moles of other components are fixed. Similarly, it can be defined ...
... components remains same; or it can be defined as, the rate of change of enthalpy with respect to the number of moles of that particular component for which the chemical potential is defined when the entropy pressure and the number of moles of other components are fixed. Similarly, it can be defined ...
Limiting - Faculty Web Pages
... unreacted H2 to find the last molecule of unreacted Cl2 in a flask full of HCl. However, if we reacted one mole of H2 with two moles of Cl2, the last molecule of unreacted H2 would be surrounded by 1 mole of unreacted Cl2 in the flask. In most cases you will get a much better % yield if an excess of ...
... unreacted H2 to find the last molecule of unreacted Cl2 in a flask full of HCl. However, if we reacted one mole of H2 with two moles of Cl2, the last molecule of unreacted H2 would be surrounded by 1 mole of unreacted Cl2 in the flask. In most cases you will get a much better % yield if an excess of ...
CHEM*1040 General Chemistry I – Winter 2010
... Online “Dry” Computer Lab Activities (refer to the Lab Schedule - courselink.uoguelph.ca) Each computer lab consists of two parts: the experiment and the marking module. Both are delivered on the website. The experiments can be accessed at ANY time (i.e., they are all open now!) and can be done as m ...
... Online “Dry” Computer Lab Activities (refer to the Lab Schedule - courselink.uoguelph.ca) Each computer lab consists of two parts: the experiment and the marking module. Both are delivered on the website. The experiments can be accessed at ANY time (i.e., they are all open now!) and can be done as m ...
Chem12 Buffer/Titration : Probs
... 28) Which one of the following equations contains the conjugate acidbase pair from which a buffer solution can be prepared ? a) HI(aq) + H2O(l) <-> H3O +(aq) + I-(aq) b) HBr(aq) + H2O(l) <-> H3O + (aq) + Br-(aq) c) H2SO 4(aq) + H2O(l) <-> H3O +(aq) + HSO4-(aq) d) H2CO3(aq) + H2O(l) <-> H3O+(aq) + HC ...
... 28) Which one of the following equations contains the conjugate acidbase pair from which a buffer solution can be prepared ? a) HI(aq) + H2O(l) <-> H3O +(aq) + I-(aq) b) HBr(aq) + H2O(l) <-> H3O + (aq) + Br-(aq) c) H2SO 4(aq) + H2O(l) <-> H3O +(aq) + HSO4-(aq) d) H2CO3(aq) + H2O(l) <-> H3O+(aq) + HC ...
Unit 5 Chemical Kinetics Section 5.1 Rates of Chemical Reaction
... temperature increases the number of reactant particles having energy greater than the activation energy of the reaction, thus producing more fruitful collisions. Moreover, the increase in temperature also increases the average kinetic energy of the particles. This will result in higher velocities of ...
... temperature increases the number of reactant particles having energy greater than the activation energy of the reaction, thus producing more fruitful collisions. Moreover, the increase in temperature also increases the average kinetic energy of the particles. This will result in higher velocities of ...
Chlorine atom spin±orbit branching ratios and total
... product formation dynamics and its collision energy dependence as observed in the present studies can be rationalized in the framework of a reaction mechanism originally proposed by Liu and co-workers to explain the results of their Cl H2 ! H HCl reactive scattering experiments [17]. In the lat ...
... product formation dynamics and its collision energy dependence as observed in the present studies can be rationalized in the framework of a reaction mechanism originally proposed by Liu and co-workers to explain the results of their Cl H2 ! H HCl reactive scattering experiments [17]. In the lat ...
Stoichiometry Notes
... an unknown substance and the solute of the standard solution. The completion of the reaction is indicated by the end point of the reaction, which is observed by the colour change either due to the indicator or due to the solute itself. Whether the reactions during the analysis are either between an ...
... an unknown substance and the solute of the standard solution. The completion of the reaction is indicated by the end point of the reaction, which is observed by the colour change either due to the indicator or due to the solute itself. Whether the reactions during the analysis are either between an ...
here
... alternative unit has a different relationship to the base unit, and we must remember all of those crazy numbers. We have to remember that there are 12 inches in a foot, 3 feet in a yard, and 5,280 feet in a mile, while at the same time remembering that for volume there are 8 ounces in a cup, 2 cups ...
... alternative unit has a different relationship to the base unit, and we must remember all of those crazy numbers. We have to remember that there are 12 inches in a foot, 3 feet in a yard, and 5,280 feet in a mile, while at the same time remembering that for volume there are 8 ounces in a cup, 2 cups ...
PPT - Gmu - George Mason University
... The Chemistry 211/212 General Chemistry courses taught at George Mason are intended for those students enrolled in a science /engineering oriented curricula, with particular emphasis on chemistry, biochemistry, and biology The material on these slides is taken primarily from the course text but the ...
... The Chemistry 211/212 General Chemistry courses taught at George Mason are intended for those students enrolled in a science /engineering oriented curricula, with particular emphasis on chemistry, biochemistry, and biology The material on these slides is taken primarily from the course text but the ...
File - Roden`s AP Chemistry
... AgBr(s) Ag (aq) + Br (aq); As KBr dissolves, the con- (a) Calculate the molality of a 20.0 percent by weight centration of Br- ions increase and force the equilibrium aqueous solution of NH4Cl. (Molecular weight: to shift to the left (LeChatelier’s principle) where the NH4Cl = 53.5) concentrations ...
... AgBr(s) Ag (aq) + Br (aq); As KBr dissolves, the con- (a) Calculate the molality of a 20.0 percent by weight centration of Br- ions increase and force the equilibrium aqueous solution of NH4Cl. (Molecular weight: to shift to the left (LeChatelier’s principle) where the NH4Cl = 53.5) concentrations ...
Chemical equilibrium
In a chemical reaction, chemical equilibrium is the state in which both reactants and products are present in concentrations which have no further tendency to change with time. Usually, this state results when the forward reaction proceeds at the same rate as the reverse reaction. The reaction rates of the forward and backward reactions are generally not zero, but equal. Thus, there are no net changes in the concentrations of the reactant(s) and product(s). Such a state is known as dynamic equilibrium.