Fall 2002 Honors
... 15. (5 pts) Nitrogen and phosphorus are in the same group, so you would expect them to exhibit similar chemical properties. NCl3, PCl3, and PCl5 are all stable compounds that are easily synthesized in the lab. However, NCl5 has never been synthesized or observed. Why would phosphorus form two compou ...
... 15. (5 pts) Nitrogen and phosphorus are in the same group, so you would expect them to exhibit similar chemical properties. NCl3, PCl3, and PCl5 are all stable compounds that are easily synthesized in the lab. However, NCl5 has never been synthesized or observed. Why would phosphorus form two compou ...
Read the following text! TEXT A Organic chemistry is a subdiscipline
... olefins or alkenes which contain one or more double bonds, i.e. di-olefins (dienes) or poly-olefins alkynes, which have one or more triple bonds. Formaldehyde is an organic compound with the formula CH2O. It is a simple derivative of a hydrocarbon, hence its systematic name is methanal. The comm ...
... olefins or alkenes which contain one or more double bonds, i.e. di-olefins (dienes) or poly-olefins alkynes, which have one or more triple bonds. Formaldehyde is an organic compound with the formula CH2O. It is a simple derivative of a hydrocarbon, hence its systematic name is methanal. The comm ...
Chapter 3 – Stoichiometry of Formulas and Equations This chapter
... This chapter addresses two basic concepts: 1) the masses of molecules and salts at both the atomic and macroscopic levels and 2) the number relationship between reacting species. 3.1 The Mole You were introduced briefly to the atomic mass unit in the previous chapter as a convenient way of discussin ...
... This chapter addresses two basic concepts: 1) the masses of molecules and salts at both the atomic and macroscopic levels and 2) the number relationship between reacting species. 3.1 The Mole You were introduced briefly to the atomic mass unit in the previous chapter as a convenient way of discussin ...
H3AsO4 + 3 I- + 2 H3O+ H3AsO3 + I3- + H2O
... The periodic table is partitioned into different types of elements based on their electron arrangement. Elements with the same valence energy level form a row or period. Elements with the same number of valence electrons form a column or group. The elements in which an s or p sublevel is being fille ...
... The periodic table is partitioned into different types of elements based on their electron arrangement. Elements with the same valence energy level form a row or period. Elements with the same number of valence electrons form a column or group. The elements in which an s or p sublevel is being fille ...
Chemistry
... A variable number of structured questions including one or two data-based questions and a question on Planning. All questions are compulsory and answered on the question paper. The data-based question(s) constitute(s) 15–20 marks for this paper whilst the Planning question constitutes 12 marks for t ...
... A variable number of structured questions including one or two data-based questions and a question on Planning. All questions are compulsory and answered on the question paper. The data-based question(s) constitute(s) 15–20 marks for this paper whilst the Planning question constitutes 12 marks for t ...
Review Packet - Newton.k12.ma.us
... 38. Carbon monoxide can be combined with hydrogen to produce methanol, CH3OH. Methanol is used as an industrial solvent, as a reactant in synthesis, and as a clean-burning fuel for some racing cars. If you had 152.5 kg CO and 24.50 kg H2, how many kilograms of CH3OH could be produced? ...
... 38. Carbon monoxide can be combined with hydrogen to produce methanol, CH3OH. Methanol is used as an industrial solvent, as a reactant in synthesis, and as a clean-burning fuel for some racing cars. If you had 152.5 kg CO and 24.50 kg H2, how many kilograms of CH3OH could be produced? ...
August 2007
... The solution in one half-cell is initially an orange colour due to the mixture of the pale green Fe2+ ions and the orange Fe3+ ions. The other half is coloured blue due to the Cu2+ ions. Describe the colour changes the student would see in each half of the cell if the reaction proceeded until no fur ...
... The solution in one half-cell is initially an orange colour due to the mixture of the pale green Fe2+ ions and the orange Fe3+ ions. The other half is coloured blue due to the Cu2+ ions. Describe the colour changes the student would see in each half of the cell if the reaction proceeded until no fur ...
Step 2
... Hi. I’m Mike Marble. I’m about to have some acid poured onto me. Let’s see what happens… ...
... Hi. I’m Mike Marble. I’m about to have some acid poured onto me. Let’s see what happens… ...
Step 2 - The Grange School Blogs
... Hi. I’m Mike Marble. I’m about to have some acid poured onto me. Let’s see what happens… ...
... Hi. I’m Mike Marble. I’m about to have some acid poured onto me. Let’s see what happens… ...
AP Chemistry Review Preparing for the AP
... bond angles shrink as lone pairs are added (b/c if increased repulsion amongst the electrons causing the bond angles to squeeze) It would be a safe bet to assume that when a metal by itself it placed in acid you will get H2 gas and some aqueous salt and the negative ion is the spectator ion. Cu does ...
... bond angles shrink as lone pairs are added (b/c if increased repulsion amongst the electrons causing the bond angles to squeeze) It would be a safe bet to assume that when a metal by itself it placed in acid you will get H2 gas and some aqueous salt and the negative ion is the spectator ion. Cu does ...
7.1 Describing Reactions
... To calculate how much oxygen is required to make 144 grams of water, begin with a balanced chemical equation for the reaction. 2H2 + O2 2H2O • Determine how many moles of water you are trying to ...
... To calculate how much oxygen is required to make 144 grams of water, begin with a balanced chemical equation for the reaction. 2H2 + O2 2H2O • Determine how many moles of water you are trying to ...
7.1 Describing Reactions
... To calculate how much oxygen is required to make 144 grams of water, begin with a balanced chemical equation for the reaction. 2H2 + O2 2H2O • Determine how many moles of water you are trying to ...
... To calculate how much oxygen is required to make 144 grams of water, begin with a balanced chemical equation for the reaction. 2H2 + O2 2H2O • Determine how many moles of water you are trying to ...
Slide 1
... To calculate how much oxygen is required to make 144 grams of water, begin with a balanced chemical equation for the reaction. 2H2 + O2 2H2O • Determine how many moles of water you are trying to ...
... To calculate how much oxygen is required to make 144 grams of water, begin with a balanced chemical equation for the reaction. 2H2 + O2 2H2O • Determine how many moles of water you are trying to ...
7.1 Describing Reactions
... To calculate how much oxygen is required to make 144 grams of water, begin with a balanced chemical equation for the reaction. 2H2 + O2 2H2O • Determine how many moles of water you are trying to ...
... To calculate how much oxygen is required to make 144 grams of water, begin with a balanced chemical equation for the reaction. 2H2 + O2 2H2O • Determine how many moles of water you are trying to ...
equilibrium questions - Southington Public Schools
... (c) For the metal carbonate, MCO3, the value of the solubility-product constant, Ksp is 7.4×10-14 at 25°C. On the basis of this information and your results in part (b), which compound, M(OH)2 or MCO3, has the greater molar solubility in water at 25°C? Justify your answer with a calculation. (d) MCO ...
... (c) For the metal carbonate, MCO3, the value of the solubility-product constant, Ksp is 7.4×10-14 at 25°C. On the basis of this information and your results in part (b), which compound, M(OH)2 or MCO3, has the greater molar solubility in water at 25°C? Justify your answer with a calculation. (d) MCO ...
Chapter 17 - Cengage Learning
... Increases in the temperature and concentration of reactants bring about more collisions, and the rate of reaction increases. The collision model explains many observations about reactions. Not all molecules that collide react. Colliding molecules must have a minimum amount of energy for a reaction t ...
... Increases in the temperature and concentration of reactants bring about more collisions, and the rate of reaction increases. The collision model explains many observations about reactions. Not all molecules that collide react. Colliding molecules must have a minimum amount of energy for a reaction t ...
111 Exam III OUTLINE TRO 1-3-11
... H. HETEROGENEOUS EQUILIBRIA When equilibrium between substances involve two or more phases it is called Heterogeneous Equilibria. The concentration of a pure solid or a pure liquid in their standard states is constant (at constant T° and P). Therefore, the concentrations of solids or liquids involve ...
... H. HETEROGENEOUS EQUILIBRIA When equilibrium between substances involve two or more phases it is called Heterogeneous Equilibria. The concentration of a pure solid or a pure liquid in their standard states is constant (at constant T° and P). Therefore, the concentrations of solids or liquids involve ...
Practice Problem - HCC Southeast Commons
... Practice Problem: What stereoisomers would result from reaction of (+)-lactic acid with (S)-1-phenyl ethylamine, and what is the relationship between them? ...
... Practice Problem: What stereoisomers would result from reaction of (+)-lactic acid with (S)-1-phenyl ethylamine, and what is the relationship between them? ...
Oxidation of benzoin with anchored vanadyl and
... carried out in the absence of catalyst, was very slow and low yields of benzil were obtained even when the reaction was allowed to proceed for a longer time (up to 32 h). Experiments were carried out using (i) the organic polymer without ligand and metal complex and (ii) the organic polymer function ...
... carried out in the absence of catalyst, was very slow and low yields of benzil were obtained even when the reaction was allowed to proceed for a longer time (up to 32 h). Experiments were carried out using (i) the organic polymer without ligand and metal complex and (ii) the organic polymer function ...
CFE Higher Chemistry in Society Homework EB
... 3. Which conditions would give the best yield of Hydrogen at equilibrium in this reaction? CH4(g) + HO(g)↔CO(g) + 3H2(g) Δ= +210kJ A High temperature and low pressure B High temperature and high pressure C Low temperature and low pressure D Low temperature and high pressure 4. In which reaction belo ...
... 3. Which conditions would give the best yield of Hydrogen at equilibrium in this reaction? CH4(g) + HO(g)↔CO(g) + 3H2(g) Δ= +210kJ A High temperature and low pressure B High temperature and high pressure C Low temperature and low pressure D Low temperature and high pressure 4. In which reaction belo ...
Chapter 15: Kinetics
... 2A + B →3C +D If the rate of disappearance of A is equal to -0.084 mol/L s at the start of the reaction what are the rates of change for B, C and D at this time? Rate of change of B = Rate of change of C = Rate of change of D = a) B= 0.042 M/s; C= 0.056 M/s; D= - 0.042 mol/L s b) B = -0.042M/s; C = ...
... 2A + B →3C +D If the rate of disappearance of A is equal to -0.084 mol/L s at the start of the reaction what are the rates of change for B, C and D at this time? Rate of change of B = Rate of change of C = Rate of change of D = a) B= 0.042 M/s; C= 0.056 M/s; D= - 0.042 mol/L s b) B = -0.042M/s; C = ...
Enzymes: “Helper” Protein molecules
... Each enzyme is the specific helper to a specific reaction each enzyme needs to be the right shape for the job enzymes are named for the reaction they help ...
... Each enzyme is the specific helper to a specific reaction each enzyme needs to be the right shape for the job enzymes are named for the reaction they help ...
Aldehydes, Ketones and Carboxylic Acids
... The hybridisation of carbon changes from sp2 to sp3 in this process, and a tetrahedral alkoxide intermediate is produced. This intermediate captures a proton from the reaction medium to give the electrically neutral product. The net result is addition of Nu– and H+ across the carbon oxygen double bo ...
... The hybridisation of carbon changes from sp2 to sp3 in this process, and a tetrahedral alkoxide intermediate is produced. This intermediate captures a proton from the reaction medium to give the electrically neutral product. The net result is addition of Nu– and H+ across the carbon oxygen double bo ...
Sulfuric Acid
... Chemical Properties Hydrogen chloride is thermally stable up to approximately 1500 ◦C, but appreciable dissociation occurs above this temperature. Completely dry hydrogen chloride is not very reactive: mild steel is not measurably attacked. Moreover, reactions involving dry hydrogen chloride oft ...
... Chemical Properties Hydrogen chloride is thermally stable up to approximately 1500 ◦C, but appreciable dissociation occurs above this temperature. Completely dry hydrogen chloride is not very reactive: mild steel is not measurably attacked. Moreover, reactions involving dry hydrogen chloride oft ...
Lewis acid catalysis
In Lewis acid catalysis of organic reactions, a metal-based Lewis acid acts as an electron pair acceptor to increase the reactivity of a substrate. Common Lewis acid catalysts are based on main group metals such as aluminum, boron, silicon, and tin, as well as many early (titanium, zirconium) and late (iron, copper, zinc) d-block metals. The metal atom forms an adduct with a lone-pair bearing electronegative atom in the substrate, such as oxygen (both sp2 or sp3), nitrogen, sulfur, and halogens. The complexation has partial charge-transfer character and makes the lone-pair donor effectively more electronegative, activating the substrate toward nucleophilic attack, heterolytic bond cleavage, or cycloaddition with 1,3-dienes and 1,3-dipoles.Many classical reactions involving carbon–carbon or carbon–heteroatom bond formation can be catalyzed by Lewis acids. Examples include the Friedel-Crafts reaction, the aldol reaction, and various pericyclic processes that proceed slowly at room temperature, such as the Diels-Alder reaction and the ene reaction. In addition to accelerating the reactions, Lewis acid catalysts are able to impose regioselectivity and stereoselectivity in many cases.Early developments in Lewis acid reagents focused on easily available compounds such as TiCl4, BF3, SnCl4, and AlCl3. The relative strengths of these (and other) Lewis acids may be estimated from NMR spectroscopy by the Childs method or the Gutmann-Beckett method. Over the years, versatile catalysts bearing ligands designed for specific applications have facilitated improvement in both reactivity and selectivity of Lewis acid-catalyzed reactions. More recently, Lewis acid catalysts with chiral ligands have become an important class of tools for asymmetric catalysis.Challenges in the development of Lewis acid catalysis include inefficient catalyst turnover (caused by catalyst affinity for the product) and the frequent requirement of two-point binding for stereoselectivity, which often necessitates the use of auxiliary groups.