Physics 1. Mechanics Problems
... Whether the equilibrium is stable or not is determined by the second derivative (d2 U/dx2 ) = −A + 2Bx. If (d2 U/dx2 ) < 0 the point is a maximum and the equilibrium is unstable, if (d2 U/dx2 ) > 0 the point is a minimum and the equilibrium is stable. In x = x1 = 0 we have (d2 U/dx2 ) = −A < 0 so th ...
... Whether the equilibrium is stable or not is determined by the second derivative (d2 U/dx2 ) = −A + 2Bx. If (d2 U/dx2 ) < 0 the point is a maximum and the equilibrium is unstable, if (d2 U/dx2 ) > 0 the point is a minimum and the equilibrium is stable. In x = x1 = 0 we have (d2 U/dx2 ) = −A < 0 so th ...
Pdf - Text of NPTEL IIT Video Lectures
... So, that will be given as half I p and theta dot square, because it is oscillating with theta and velocity is theta dot. So, we can see that both the linear and rotational kinetic energy is there in this. And now we are having a displacement or the extension of the spring because of this displaceme ...
... So, that will be given as half I p and theta dot square, because it is oscillating with theta and velocity is theta dot. So, we can see that both the linear and rotational kinetic energy is there in this. And now we are having a displacement or the extension of the spring because of this displaceme ...
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... vA2 x vB 2 x 300 m/s 2 320 m/s The 0.150 kg glider (A) is moving to the left at 3.20 m/s and the 0.300 kg glider (B) is moving to the left at 0.20 m/s. EVALUATE: We can use our v A2 x and vB 2 x to show that Px is constant and K1 K2 IDENTIFY: When the spring is compressed the maximum amou ...
... vA2 x vB 2 x 300 m/s 2 320 m/s The 0.150 kg glider (A) is moving to the left at 3.20 m/s and the 0.300 kg glider (B) is moving to the left at 0.20 m/s. EVALUATE: We can use our v A2 x and vB 2 x to show that Px is constant and K1 K2 IDENTIFY: When the spring is compressed the maximum amou ...
Force and Motion II 3.0
... More precisely, the amplitude A is the maximum displacement of the cart away from the equilibrium point. The period T is the time it takes the cart to complete one oscillation (one back-and-forth motion) Note that the function x(t) = Asin(2πt/T) is bounded, −A ≤ x ≤ A, and periodic, x(t+T) = x(t). E ...
... More precisely, the amplitude A is the maximum displacement of the cart away from the equilibrium point. The period T is the time it takes the cart to complete one oscillation (one back-and-forth motion) Note that the function x(t) = Asin(2πt/T) is bounded, −A ≤ x ≤ A, and periodic, x(t+T) = x(t). E ...
Impulse and Momentum
... motion. The work-energy theorem and the impulse-momentum theorem are two different descriptions of the same change. Which description is more useful to you depends on the situation: what things you know, and what ...
... motion. The work-energy theorem and the impulse-momentum theorem are two different descriptions of the same change. Which description is more useful to you depends on the situation: what things you know, and what ...
