Rotation Moment of inertia of a rotating body: w
... ● We have two forces acting on mass m: Gravity and tension from the string ● We have one torque caused by the tension in the string acting on the disk ● The linear motion of the mass is linked to the circular motion of the disk via the cord. ...
... ● We have two forces acting on mass m: Gravity and tension from the string ● We have one torque caused by the tension in the string acting on the disk ● The linear motion of the mass is linked to the circular motion of the disk via the cord. ...
Laws of Motion - SCHOOLinSITES
... lion. The total mass of the lion and stretcher is 175 kg, and the lion’s upward acceleration is 0.657 m/s2. What is the unbalanced force necessary to produce this acceleration of the ...
... lion. The total mass of the lion and stretcher is 175 kg, and the lion’s upward acceleration is 0.657 m/s2. What is the unbalanced force necessary to produce this acceleration of the ...
Chapter 10
... (a) What is the potential energy of the mass at the instant it is released? Choose potential energy to be zero at the bottom of the swing. (b) What is the speed of the mass as it passes its lowest point? This same pendulum is taken to another planet where its period is 1.0 second. (c) What is the ac ...
... (a) What is the potential energy of the mass at the instant it is released? Choose potential energy to be zero at the bottom of the swing. (b) What is the speed of the mass as it passes its lowest point? This same pendulum is taken to another planet where its period is 1.0 second. (c) What is the ac ...
Kinematics Multiples
... note that the horizontal component of the velocity did not change. This means that there was no net force in the horizontal direction. However, the vertical component of the velocity reversed directions, which requires an upward force (to stop and then reverse the direction of motion of the ball.) E ...
... note that the horizontal component of the velocity did not change. This means that there was no net force in the horizontal direction. However, the vertical component of the velocity reversed directions, which requires an upward force (to stop and then reverse the direction of motion of the ball.) E ...
File
... 1. Work is being done on the textbook when a student a. sits in a chair holding a 0.15kg textbook. b. lifts a 0.15kg textbook from the floor to a desk. c. walks across the classroom holding a 0.15kg textbook. d. leans against a 0.15kg textbook that is sitting on a desk. 2. The engine of a car exerts ...
... 1. Work is being done on the textbook when a student a. sits in a chair holding a 0.15kg textbook. b. lifts a 0.15kg textbook from the floor to a desk. c. walks across the classroom holding a 0.15kg textbook. d. leans against a 0.15kg textbook that is sitting on a desk. 2. The engine of a car exerts ...
Chapter 4-5 Review Ideas and Concepts You Are Responsible For
... Newton’s First Law of Motion: Inertia Define mass and inertia. Understand Newton's first law of motion. Newton’s Second Law of Motion: Concept of a System Define net force, external force, and system. Understand Newton’s second law of motion. Apply Newton’s second law to determine the weight of an o ...
... Newton’s First Law of Motion: Inertia Define mass and inertia. Understand Newton's first law of motion. Newton’s Second Law of Motion: Concept of a System Define net force, external force, and system. Understand Newton’s second law of motion. Apply Newton’s second law to determine the weight of an o ...
Inclined Planes:
... For two surfaces in contact it turns out that the frictional force is independent of the area of contact, independent of the relative speed of the two surfaces and is directly proportional to the normal reaction between the two surfaces. F = µN , where F is the frictional force, N is the normal reac ...
... For two surfaces in contact it turns out that the frictional force is independent of the area of contact, independent of the relative speed of the two surfaces and is directly proportional to the normal reaction between the two surfaces. F = µN , where F is the frictional force, N is the normal reac ...
P2 Knowledge Powerpoint – WIP Part 1
... When an object is moved up, its gravitational potential energy increases. When an object is moved down, its gravitational potential energy decreases Use this formula: Change in gradational potential energy (J) =weight (N) x change in height(m) Use this formula: Change in gravational otential energy ...
... When an object is moved up, its gravitational potential energy increases. When an object is moved down, its gravitational potential energy decreases Use this formula: Change in gradational potential energy (J) =weight (N) x change in height(m) Use this formula: Change in gravational otential energy ...