more_1st_week
... Computer does these calculations in the base 2 number system so it is actually done as outlined above but with 1’s and 0’s. Example shows the philosophy of how it is done. Alternate approach ...
... Computer does these calculations in the base 2 number system so it is actually done as outlined above but with 1’s and 0’s. Example shows the philosophy of how it is done. Alternate approach ...
Chapter 2 - Forces In Motion
... All forces act in pairs called action-reaction force pairs If a force is exerted, another force occurs that is equal in size and opposite in direction to the first. ...
... All forces act in pairs called action-reaction force pairs If a force is exerted, another force occurs that is equal in size and opposite in direction to the first. ...
6-04a,04b -Momentum and Impulse Wkst-Key
... Use the impulse-momentum equation to answer questions 6-9: 6. Why is it important to “ follow through”when trying to hit a home run? Following through maximizes the length of time the bat is in contact with the ball. This maximizes the impulse, allowing the greatest change in momentum and the greate ...
... Use the impulse-momentum equation to answer questions 6-9: 6. Why is it important to “ follow through”when trying to hit a home run? Following through maximizes the length of time the bat is in contact with the ball. This maximizes the impulse, allowing the greatest change in momentum and the greate ...
Chapter 7 Energy of a system Conceptual question Q7.1 Can kinetic
... 6.00iˆ 2.00ˆjm / s . (a) What is its kinetic energy at this time? (b) Find the total work done on the object if its velocity changes to 8.00 ˆi 4.00 ˆj m / s . (Note: From the definition of the dot product, v2 = v·v.) ANS: (a) 60.0 J; (b) 60.0 J Potential Energy of a system ...
... 6.00iˆ 2.00ˆjm / s . (a) What is its kinetic energy at this time? (b) Find the total work done on the object if its velocity changes to 8.00 ˆi 4.00 ˆj m / s . (Note: From the definition of the dot product, v2 = v·v.) ANS: (a) 60.0 J; (b) 60.0 J Potential Energy of a system ...
Chapter 7 Energy of a system Conceptual question Q7.1 Can kinetic
... 6.00iˆ 2.00 ˆjm / s . (a) What is its kinetic energy at this time? (b) Find the total work done on the object if its velocity changes to 8.00 ˆi 4.00 ˆj m / s . (Note: From the definition of the dot product, v2 = v·v.) ANS: (a) 60.0 J; (b) 60.0 J Potential Energy of a system ...
... 6.00iˆ 2.00 ˆjm / s . (a) What is its kinetic energy at this time? (b) Find the total work done on the object if its velocity changes to 8.00 ˆi 4.00 ˆj m / s . (Note: From the definition of the dot product, v2 = v·v.) ANS: (a) 60.0 J; (b) 60.0 J Potential Energy of a system ...
momentum
... An object at rest remains at rest and an object in motion remains in motion at a constant speed and in a straight line unless acted on by an unbalanced force. -this law describes an object with a net force of zero acting on it EXPLAIN. -often referred to as the Law of Inertia (an object's resistance ...
... An object at rest remains at rest and an object in motion remains in motion at a constant speed and in a straight line unless acted on by an unbalanced force. -this law describes an object with a net force of zero acting on it EXPLAIN. -often referred to as the Law of Inertia (an object's resistance ...
momentum
... m1 = m2 – the particles exchange velocities When a very heavy particle collides head-on with a very light one initially at rest, the heavy particle continues in motion unaltered and the light particle rebounds with a speed of about twice the initial speed of the heavy particle. When a very lig ...
... m1 = m2 – the particles exchange velocities When a very heavy particle collides head-on with a very light one initially at rest, the heavy particle continues in motion unaltered and the light particle rebounds with a speed of about twice the initial speed of the heavy particle. When a very lig ...
pp\momentum - Dr. Robert MacKay
... Conservation of Momentum Collisions Explosions Elastic Collisions ...
... Conservation of Momentum Collisions Explosions Elastic Collisions ...
Newton`s second law File
... SITUATION 1: a pole vaulter needs maximum acceleration off the ground to gain the height required to clear the bar. he therefore needs maximum thrust (force). ...
... SITUATION 1: a pole vaulter needs maximum acceleration off the ground to gain the height required to clear the bar. he therefore needs maximum thrust (force). ...
AHSGE Review
... is the ability to do work, so it is very closely related to work. However, it can be present whether an object is in motion or at rest. The units are Joules, just like for work. Energy can be potential or kinetic. ...
... is the ability to do work, so it is very closely related to work. However, it can be present whether an object is in motion or at rest. The units are Joules, just like for work. Energy can be potential or kinetic. ...
Motion Along a Straight Line at Constant Acceleration
... zones and air bags increase safety by making the crash “last longer” During our Y12 presentations, change in momentum was connected to car safety. Now taking it further and considering the impulse of a force : ...
... zones and air bags increase safety by making the crash “last longer” During our Y12 presentations, change in momentum was connected to car safety. Now taking it further and considering the impulse of a force : ...
Investigation 3
... form to another (e.g., kinetic energy to potential energy and vice versa). Suppose a 1 kg ball is at the top of a 40 meter high cliff. In the first case, at position A, we drop the ball and in the second case we throw the ball downward so that it leaves our hand at 10 m/s. Position D is just before ...
... form to another (e.g., kinetic energy to potential energy and vice versa). Suppose a 1 kg ball is at the top of a 40 meter high cliff. In the first case, at position A, we drop the ball and in the second case we throw the ball downward so that it leaves our hand at 10 m/s. Position D is just before ...
Practice Questions
... Earth. At point X it is closest to Earth. At point Y it is furthest from Earth. Point Z is halfway between points X and Y, along the orbital path. Where is the angular momentum (relative to the Earth) of the satellite the highest? A) It is the same at all locations B) Point Y C) Point X D) Point Z ...
... Earth. At point X it is closest to Earth. At point Y it is furthest from Earth. Point Z is halfway between points X and Y, along the orbital path. Where is the angular momentum (relative to the Earth) of the satellite the highest? A) It is the same at all locations B) Point Y C) Point X D) Point Z ...