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Review Answers
Review Answers

Chapter1. OSCILLATIONS
Chapter1. OSCILLATIONS

Chapter 9
Chapter 9

... (a) We use Fig. 9-21 of the text (which treats both angles as positive-valued, even though one of them is in the fourth quadrant; this is why there is an explicit minus sign in Eq. 9-80 as opposed to it being implicitly in the angle). We take the cue ball to be body 1 and the other ball to be body 2 ...
(1) (modja thinks)
(1) (modja thinks)

... Monday, 12/2/2013 A.A.22 – Solving multi-step equations with variables on one side ...
Newton`s Second Law
Newton`s Second Law

... Suppose the same 35 kg crate was not moving at a constant speed, but rather accelerating at 0.70 m/s/s. Calculate the applied force. The coefficient of kinetic friction is still 0.30. ...
Force
Force

... others act only when two objects are in contact with one another. – Contact forces exist when two objects are in contact with one another. – Long-range (FIELD) forces act over distances without a need for direct contact. Electromagnetic forces and gravity are long-range forces. ...
Single Point of Contact Manipulation of Unknown Objects
Single Point of Contact Manipulation of Unknown Objects

... • Given a set of particles, we can simulate a behavior many times, assuming a different particle to be the ‘truth’ each time. • We can look at the statistics of these trials to see what effect a given behavior will have on the belief state. – Some behaviors tend to reduce the variance or entropy of ...
Chapter 5 Uniform Circular Motion and Centripetal Force
Chapter 5 Uniform Circular Motion and Centripetal Force

Physical Science Semester Exam Study Guide
Physical Science Semester Exam Study Guide

... b. 2nd Law – Description: F = m x a Example: Getting hit by a boulder hurts more than getting hit by a pebble at the same speed. c. 3rd Law – Description: For every action there is an equal and opposite reaction. Example: Explosion from rocket goes downward, rocket goes up. 42. Define inertia. Tende ...
Solving A Linear System By Substitution
Solving A Linear System By Substitution

... Here is a linear system:  x  y  1 2x  3y  2 y  x 1 First choose one equation and isolate one of the variables. You will get the same solution whether you solve for x first or y first. You should begin by solving for the variable that is easier to isolate. Which of the above equations would ...
Learning Outcomes
Learning Outcomes

... knowledge developed through this process, with emphasis on how well students have understood the underlying physical ideas, as well as some of the mathematical formulations of these ideas. ...
Physics II - Magnetism - Ms. Gamm
Physics II - Magnetism - Ms. Gamm

Physics, Chapter 12: Periodic Motion
Physics, Chapter 12: Periodic Motion

Unit Review
Unit Review

University Physics-1 Ch-10 NAME: HOMEWORK CHAPTER 10
University Physics-1 Ch-10 NAME: HOMEWORK CHAPTER 10

Newton`s Laws
Newton`s Laws

... Every object continues in its state of rest, or of motion in a straight line at constant speed, unless compelled to change that state by forces exerted on it. Also called Law of Inertia: things move according to their own inertia Things keep on doing what they are doing Examples: Hockey puck on ice, ...
Chapter 6 Study Questions Name
Chapter 6 Study Questions Name

... b. Mass d. Velocity Newton's second law of motion states that an object's acceleration a. increases as its mass decreases and as the force acting on it increases. b. decreases as its mass decreases and as the force acting on it increases. c. increases as its mass increases and as the force acting on ...
PHS4550 - Cowley College
PHS4550 - Cowley College

... Rationalize the behavior of physical systems with Newton’s first law. Understand the concept of mass and inertia, and apply these concepts to correct formulations of physical systems. Rationalize the behavior of physical systems based upon Newton’s third law and solve applications and correct formul ...
Chapter 3
Chapter 3

... object transfers all of its momentum to the other object during the collision • If the collision involves a stationary object and a moving object, immediately after the collision, the previously stationary object will be moving, and the previously moving object will be stationary ...
Free Body Diagrams and Net Force
Free Body Diagrams and Net Force

ch 13 - Simple Harmonic Motion
ch 13 - Simple Harmonic Motion

... Note: ω is the angular speed of Q (circular motion) and the angular frequency of SHM. These quantities are equal! When you start a body oscillating in SHM, the value of angular frequency ω is not yours to choose; it is predetermined by the values of k and m. the units k are N/m or kg/s2, so the unit ...
Newton`s Laws Outlines
Newton`s Laws Outlines

... 4,000N. What is the acceleration of the boxcar? d. A fully equipped astronaut has a mass of 150kg. If the astronaut has a weight of 555N standing on the surface of Mars, what is the acceleration due to gravity on Mars? 5. Find the Net Force. a. What is the net force needed to accelerate a 50.0 kg bo ...
Section 8-2 Center of Mass
Section 8-2 Center of Mass

Lecture04
Lecture04

... 1. Identify all forces acting on the object -Pushes or Pulls -Frictional forces -Tension in a string -Gravitational Force (or weight = mg where g is 9.8 m/s2) - “Normal forces” (one object touching another). 2. Draw a “Freebody Diagram” -draw the object, show all forces acting on that object as vect ...
Exam II Difficult Problems
Exam II Difficult Problems

... • Three objects are attached to a massless rigid rod that has an axis of rotation as shown. Assuming all of the mass of each object is located at the point shown for each, calculate the moment of inertia of this system. ...
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Equations of motion

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