Physics 121 Exam Sheet - BYU Physics and Astronomy
... In the absence of a force (a free object) moves with a = 0, i.e., if at rest, it remains at rest. If moving, it continues to move in a straight line at a constant speed. This is a law describing an inertial reference frame. If it appears to be violated, the observer’s reference frame is not in an in ...
... In the absence of a force (a free object) moves with a = 0, i.e., if at rest, it remains at rest. If moving, it continues to move in a straight line at a constant speed. This is a law describing an inertial reference frame. If it appears to be violated, the observer’s reference frame is not in an in ...
Wave on a string To measure the acceleration due to gravity on a
... Wave on a string To measure the acceleration due to gravity on a distant planet, an astronaut hangs a 0.070 kg ball from the end of a wire. The wire has a length of 1.5 m and a linear density of 3.1 10-4 kg/m. Using electronic equipment, the astronaut measures the time for a transverse pulse to trav ...
... Wave on a string To measure the acceleration due to gravity on a distant planet, an astronaut hangs a 0.070 kg ball from the end of a wire. The wire has a length of 1.5 m and a linear density of 3.1 10-4 kg/m. Using electronic equipment, the astronaut measures the time for a transverse pulse to trav ...
Guide_Test1
... 1. What is Newton’s 3rd law? 2. Newton’s 3rd law is valid during an interaction. Action and reaction forces are equal in magnitude but opposite in direction. They act on different objects. 3. You should be able to state the action and reaction force during an interaction. For eg, motion of a rocket, ...
... 1. What is Newton’s 3rd law? 2. Newton’s 3rd law is valid during an interaction. Action and reaction forces are equal in magnitude but opposite in direction. They act on different objects. 3. You should be able to state the action and reaction force during an interaction. For eg, motion of a rocket, ...
Day 3
... of the water sits on a rocky cliff that extends 19 ft from its base. A sailor on the deck of a ship sights the top of the lighthouse at an angle of 30.0o above the horizontal. If the sailor’s eye level is 14 ft above the water, how far is the ship from the rocks? ...
... of the water sits on a rocky cliff that extends 19 ft from its base. A sailor on the deck of a ship sights the top of the lighthouse at an angle of 30.0o above the horizontal. If the sailor’s eye level is 14 ft above the water, how far is the ship from the rocks? ...
Newton's Laws powerpoint - South Webster High School
... Deceleration is negative acceleration or slowing down Centripetal acceleration changing direction ...
... Deceleration is negative acceleration or slowing down Centripetal acceleration changing direction ...
Announcements
... l x increases uniformly with time l In each time increment Δt, there is an equal displacement Δx l Note that the velocity is given by the slope of the x vs t graph ...
... l x increases uniformly with time l In each time increment Δt, there is an equal displacement Δx l Note that the velocity is given by the slope of the x vs t graph ...
Part I - Otterbein
... • We conclude v=dx/dt=2[4.9m/s2]t a=dv/dt=2[4.9m/s2]=9.8m/s2 • Hence the force exerted on the ball must be • F = 9.8/4 kg m/s2 = 2.45 N – Note that the force does not change, since the acceleration does not change: a constant force acts on the ball and accelerates it steadily. ...
... • We conclude v=dx/dt=2[4.9m/s2]t a=dv/dt=2[4.9m/s2]=9.8m/s2 • Hence the force exerted on the ball must be • F = 9.8/4 kg m/s2 = 2.45 N – Note that the force does not change, since the acceleration does not change: a constant force acts on the ball and accelerates it steadily. ...
Newton`s Second Law, X
... If the forces can be resolved directly from the free-body diagram (often the case in 2-D problems), use the scalar form of the equation of motion. In more complex cases (usually 3-D), a Cartesian vector is written for every force and a vector analysis is often best. A Cartesian vector formulation of ...
... If the forces can be resolved directly from the free-body diagram (often the case in 2-D problems), use the scalar form of the equation of motion. In more complex cases (usually 3-D), a Cartesian vector is written for every force and a vector analysis is often best. A Cartesian vector formulation of ...
Chapter 2 Outline
... 4. Displacement – distance and direction in a straight line from starting point to ending point B. Speed - how quickly an object changes position 1. distance traveled per unit of time 2. s = d / t 3. Constant speed – speed stays the same the entire trip 4. Average speed – total distance divided by t ...
... 4. Displacement – distance and direction in a straight line from starting point to ending point B. Speed - how quickly an object changes position 1. distance traveled per unit of time 2. s = d / t 3. Constant speed – speed stays the same the entire trip 4. Average speed – total distance divided by t ...
Symbols a = acceleration t = time d = distance s = speed Ѵ = velocity
... d = Ѵit+ ½ gt2 (distance) = (initial velocity X time) + ½ ( gravity's acceleration x time squared ) ...
... d = Ѵit+ ½ gt2 (distance) = (initial velocity X time) + ½ ( gravity's acceleration x time squared ) ...
Acceleration
... toward a destination is positive displacement; travel back toward the starting position is negative displacement. – The displacement at the end of a walk can be zero for this reason. ...
... toward a destination is positive displacement; travel back toward the starting position is negative displacement. – The displacement at the end of a walk can be zero for this reason. ...
rigid-body motion
... • Rigid bodies also have orientation • Treating rotation properly is complicated • Rotation is not a vector (rotations do not commute, i.e., order of rotations matters) • No analog to x, v, a in rotations? ...
... • Rigid bodies also have orientation • Treating rotation properly is complicated • Rotation is not a vector (rotations do not commute, i.e., order of rotations matters) • No analog to x, v, a in rotations? ...
Physics 5153 Classical Mechanics Velocity Dependent Potentials
... To show that the Lorentz force satisfies Eq. 12, we will work in Cartesian coordinates. First, ~ is equivalent to the standard potential that we use. Therefore, we we note that the term −e∇φ only need to consider the term ...
... To show that the Lorentz force satisfies Eq. 12, we will work in Cartesian coordinates. First, ~ is equivalent to the standard potential that we use. Therefore, we we note that the term −e∇φ only need to consider the term ...