9A EXPERIMENT Rotational Motion 1
... 2. With the air supply on, attach the hanging mass (M) to one end of a string and wind the other end around the central pulley. The string should also pass over the side pulley such that the hanging mass is just below the side pulley. Measure and record the position of the hanging mass above the fl ...
... 2. With the air supply on, attach the hanging mass (M) to one end of a string and wind the other end around the central pulley. The string should also pass over the side pulley such that the hanging mass is just below the side pulley. Measure and record the position of the hanging mass above the fl ...
Study Sheet for Chemistry and Physics Chemistry Atomic Structure
... increase and decrease at the same rate Physics Speed – distance traveled over time (see Formulas and Units section on how to calculate) – example 65km/h Velocity – speed in a SPECIFIC direction – Example 65km/h NW Acceleration – rate at which velocity changes, so any change in speed or direction is ...
... increase and decrease at the same rate Physics Speed – distance traveled over time (see Formulas and Units section on how to calculate) – example 65km/h Velocity – speed in a SPECIFIC direction – Example 65km/h NW Acceleration – rate at which velocity changes, so any change in speed or direction is ...
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... 5. A river flows due east at 1.50 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant velocity of 10.0 m/s 35º northwest relative to the water. (a) What is the velocity of the boat relative to the shore? (b) If the river is 500 m wide, how far downstream h ...
... 5. A river flows due east at 1.50 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant velocity of 10.0 m/s 35º northwest relative to the water. (a) What is the velocity of the boat relative to the shore? (b) If the river is 500 m wide, how far downstream h ...
Spring: Potential energy function
... A block of mass M is on a horizontal surface and is attached to a spring, spring constant k. If the spring is compressed an amount A and the block released from rest, how far from unstretched position will it go before stopping if there is no friction between the block and the surface? ...
... A block of mass M is on a horizontal surface and is attached to a spring, spring constant k. If the spring is compressed an amount A and the block released from rest, how far from unstretched position will it go before stopping if there is no friction between the block and the surface? ...
Force and Motion
... Gravity – A force of attraction between objects that is due to their masses Law of Universal Gravitation- All objects in the universe attract each other through gravitational force. The size of the force depends on the masses of the objects and the distance between them Weight – A measure of gravita ...
... Gravity – A force of attraction between objects that is due to their masses Law of Universal Gravitation- All objects in the universe attract each other through gravitational force. The size of the force depends on the masses of the objects and the distance between them Weight – A measure of gravita ...
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... particle equals to the torque of the net force acting on the particle. •For any system of particles (including both rigid and non-rigid bodies), the rate of change of the total angular momentum equals the sum of the torques of all forces acting on all the particles. The torques of the internal force ...
... particle equals to the torque of the net force acting on the particle. •For any system of particles (including both rigid and non-rigid bodies), the rate of change of the total angular momentum equals the sum of the torques of all forces acting on all the particles. The torques of the internal force ...
(linear) momentum
... must lie on an axis of symmetry. The centre of mass is different from its centre of gravity. Each portion of a system is acted on by the gravitational force. The net effect of all of these forces is equivalent to the effect of a single force Mg acting at a special point called the center of gravity. ...
... must lie on an axis of symmetry. The centre of mass is different from its centre of gravity. Each portion of a system is acted on by the gravitational force. The net effect of all of these forces is equivalent to the effect of a single force Mg acting at a special point called the center of gravity. ...
Physics Lecture Notes (abridged)
... b. solve unknown in the x-direction with vx = dx/t 2. helpful shortcuts when a ball is kicked at ground level across a horizontal field a. vy = -vyo when the ball hits the ground b. vy = 0 when the ball reaches its highest point c. it takes half the time to reach its highest point F. Uniform circula ...
... b. solve unknown in the x-direction with vx = dx/t 2. helpful shortcuts when a ball is kicked at ground level across a horizontal field a. vy = -vyo when the ball hits the ground b. vy = 0 when the ball reaches its highest point c. it takes half the time to reach its highest point F. Uniform circula ...
PHYSICS 111 HOMEWORK SOLUTION, week 4, chapter 5, sec 1
... Three blocks are in contact with one another on a frictionless, horizontal surface as shown in the figure below. A horizontal force is applied to m1 . Take m1 = 2.00kg, m2 = 3.00 kg, m3 = 4.55 kg, and F = 22.5 N. • a) Draw a separate free-body diagram for each block. • b) Find the acceleration of th ...
... Three blocks are in contact with one another on a frictionless, horizontal surface as shown in the figure below. A horizontal force is applied to m1 . Take m1 = 2.00kg, m2 = 3.00 kg, m3 = 4.55 kg, and F = 22.5 N. • a) Draw a separate free-body diagram for each block. • b) Find the acceleration of th ...
Motion 10sci
... Average speed can be calculated by total distance divided by total time but journeys over distance are not travelled at a constant speed but change over time. They can be calculated in segments Distance time graphs can be drawn from the data gathered to show speed at different points in the journey ...
... Average speed can be calculated by total distance divided by total time but journeys over distance are not travelled at a constant speed but change over time. They can be calculated in segments Distance time graphs can be drawn from the data gathered to show speed at different points in the journey ...
ROUND ALL NUMERICAL ANSWERS TO 3 SIGNIFICANT
... 2. As a ball collides with a wall, the force on the ball goes linearly from zero to maximum in 3 ms (10-3 s), the force is then constant for 2 ms, the force then falls linearly to zero in 3 ms. The ball has mass of 50 g and an initial velocity of 30 m/s perpendicular to the wall. The ball rebounds w ...
... 2. As a ball collides with a wall, the force on the ball goes linearly from zero to maximum in 3 ms (10-3 s), the force is then constant for 2 ms, the force then falls linearly to zero in 3 ms. The ball has mass of 50 g and an initial velocity of 30 m/s perpendicular to the wall. The ball rebounds w ...
Physics 1. Mechanics Problems
... Problem 10.2. A particle, initially resting in the coordinate origin, suddenly breaks up into three particles with the masses m1 , m2 , and m3 . The particle m1 has the charge q > 0. It starts moving into negative x-direction in the homogeneous magnetic field B = (0, 0, B). After having completed ha ...
... Problem 10.2. A particle, initially resting in the coordinate origin, suddenly breaks up into three particles with the masses m1 , m2 , and m3 . The particle m1 has the charge q > 0. It starts moving into negative x-direction in the homogeneous magnetic field B = (0, 0, B). After having completed ha ...
Free fall
... Both numerator and denominator are proportional to “m”, if force is gravity • SO....acceleration is the same, regardless of the mass • We’ll return to this point when we consider ...
... Both numerator and denominator are proportional to “m”, if force is gravity • SO....acceleration is the same, regardless of the mass • We’ll return to this point when we consider ...
Newton`s Laws - strikerphysics11
... acting on a body into components both parallel and perpendicular to the surface on which the body rests. The normal force is found by ensuring an equilibrium of all components perpendicular to the surface. ...
... acting on a body into components both parallel and perpendicular to the surface on which the body rests. The normal force is found by ensuring an equilibrium of all components perpendicular to the surface. ...
