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G o rxn
G o rxn

... (a) Standard Conditions, PH2O = 1 atm, i.e., Q = 1 Grxn = Gorxn + RTlnQ = +8.59 kJ/mol + RT ln(1) = +8.59 kJ/mol (spontaneous in the reverse direction) (b) At pressure of 0.0313 atm, i.e., Q = Kp = 0.0313 Grxn = Gorxn + RTlnQ = +8.59 kJ/mol + RT ln (0.0313) = +8.59 kJ/mol - 8.59 kJ/mol = 0 (c) A ...
CHEMISTRY SEC 06 SYLLABUS
CHEMISTRY SEC 06 SYLLABUS

... The examination will consist of two written papers, each of two hours’ duration, and an assessment of practical work in chemistry. Questions will be set in English and must be answered in English. The examination will be structured as follows: Paper I consists of a written paper and a practical comp ...
CHEMISTRY SEC 06 SYLLABUS
CHEMISTRY SEC 06 SYLLABUS

... The examination will consist of two written papers, each of two hours’ duration, and an assessment of practical work in chemistry. Questions will be set in English and must be answered in English. The examination will be structured as follows: Paper I consists of a written paper and a practical comp ...
CHEMISTRY SEC 06 SYLLABUS
CHEMISTRY SEC 06 SYLLABUS

... The examination will consist of two written papers, each of two hours’ duration, and an assessment of practical work in chemistry. Questions will be set in English and must be answered in English. The examination will be structured as follows: Paper I consists of a written paper and a practical comp ...
Questions - Scheikundeolympiade
Questions - Scheikundeolympiade

... QUESTION 28: Cryoscopy (4 points) Chemists often need a bath in which to carry out a process that has a temperature below the water freezing point (0 °C) and well above the CO2 sublimation point (78 °C). In this case they mix water ice prepared at its melting point and NaCl. Depending on the quanti ...
No Slide Title
No Slide Title

... gas. Determine the enthalpy change for 1 mol of gaseous propane given the following thermochemical data: C3H8(g) + 5O2(g)  3CO2(g) + 4H2O(l) H = -2220 kJ C(s) + O2(g)  CO2(g) H = -394 kJ H2(g) + ½O2(g)  H2O(l) H = -286 kJ 2. Diborane (B2H6) is a highly reactive boron hydride which was once ...
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Class_X–Science__term_I

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Form 3 Chem. Term 1 Notes.FINAL.
Form 3 Chem. Term 1 Notes.FINAL.

... A mole of a substance is the amount of substance which contains as many particles as there are carbon atoms in 12g of carbon - 12 isotopes. The number of particles is one mole of any substance is 6.023 x 1023. This number is called the Avagadro number or Avagadro’s constant. The amount of any substa ...
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C7 Revision Notes 2015

... Ethane 2C2H6(g) + 7O2(g)  4CO2(g) + 6H20(g) These are balanced equations with state symbols ...
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CHEMICAL EQUILIBRIUM

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Ceramics for catalysis

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... 35. The solubility of a gas in water at 25 oC and a partial pressure of 1.0 atm is 6.7 x 10-4 mol/L. What is the molar concentration of the gas dissolved in water if its partial pressure is 0.80 atm? A) 6.7 x 10-4 M D) 1.8 x 10-4 M Choice E ...
Holt Modern Chemistry Workbook
Holt Modern Chemistry Workbook

... A molecular compound is any chemical compound whose simplest units are molecules. In other words, a single molecule of any molecular compound is an individual unit that is capable of existing on its own. A molecule may contain two or more atoms of the same element, as in oxygen. Or, a molecule may c ...
Chemistry
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... 53. The increasing order of reactivity of halides, ethyl chloride (I), isopropyl chloride (II), ter-butyl chloride (III) in SN1 reactions is : (A) I < III < II (B) I < II < III (C) I > II > III (D) I > III > II 54. Which of the following reagents can convert acetic acid into ethanol ? (A) Sn + HCl ...
Study Modules XII Chemistry 2017
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... Ans: let no. of atoms of A be N No. of octahedral voids = N No. of tetrahedral voids = 2N i)There will be one atom of B in the octahedral void ii)There will be one atom of B in tetrahedral void (1/2 X 2N) Therefore, total 2 atoms of B for each atom of A Therefore formula of the compound = AB2 10. in ...
Chemistry A level transition - baseline assessment
Chemistry A level transition - baseline assessment

... Chemistry topic 9 – Organic chemistry – functional groups At GCSE you would have come across hydrocarbons such as alkanes (ethane etc) and alkenes (ethene etc). You may have come across molecules such as alcohols and carboxylic acids. At A level you will learn about a wide range of molecules that ha ...
Spring 2008
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... 26. For the reaction: aA(g) + bB(g) cC(g) + heat with a = 1, b=1 and c=1. An increase in total pressure (at const T) A. increases the number of moles of A B. decreases the number of moles of A C. does not change the number of moles of A Answer B There are more molecules in the gas phase on the LH si ...
Chemistry - Separation techniques
Chemistry - Separation techniques

... C3.1c use the names and symbols of common elements from a supplied periodic table to write formulae and balanced chemical equations where appropriate C3.1e construct balanced ionic equations C3.1f describe the physical states of products and reactants using state symbols (s, l, g and aq) C3.1k dedu ...
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Reactants Products

QUESTION BANK CHEMISTRY-XII THE SOLID STATE CHAPTER
QUESTION BANK CHEMISTRY-XII THE SOLID STATE CHAPTER

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LaBrake, Fundamentals Diagnostic Questions

... 73. Write the following word equation as a balanced chemical equation: Copper reacts with sulfuric acid to yield copper(II)sulfate, water, and sulfur dioxide. a) Cu + 2 H2SO4  CuSO4 + 2 H2O + SO2 (correct) b) 2 Cu + 3 H2S  Cu2S + 3 H2O + S2O c) Cu + H2SO4  Cu2SO4 + H2O + SO2 d) 2 Cu + 2 H2SO4  ...
Homo-coupling of terminal alkynes on a noble metal surface
Homo-coupling of terminal alkynes on a noble metal surface

... the condition that the terminal alkyne group retains initially its integrity. Surface mobility of the constituents is not an issue, because self-assembly of regular TEB arrays readily occurs at To200 K. Once two terminal alkyne moieties come in close proximity, a reaction intermediate can be achieve ...
Chapter 6 Thermochem 110 F11 IP
Chapter 6 Thermochem 110 F11 IP

... Thermochemistry is a branch of thermodynamics that deals with the heat involved with chemical and physical changes. ✔Energy flow is key in science; understanding it will help us to understand WHY things occur. When energy is transferred from one object to another, it appears as work and/or as heat T ...
Chemistry: Matter and Change
Chemistry: Matter and Change

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Stoichiometry



Stoichiometry /ˌstɔɪkiˈɒmɨtri/ is the calculation of relative quantities of reactants and products in chemical reactions.Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of product can be empirically determined, then the amount of the other reactants can also be calculated.As seen in the image to the right, where the balanced equation is:CH4 + 2 O2 → CO2 + 2 H2O.Here, one molecule of methane reacts with two molecules of oxygen gas to yield one molecule of carbon dioxide and two molecules of water. Stoichiometry measures these quantitative relationships, and is used to determine the amount of products/reactants that are produced/needed in a given reaction. Describing the quantitative relationships among substances as they participate in chemical reactions is known as reaction stoichiometry. In the example above, reaction stoichiometry measures the relationship between the methane and oxygen as they react to form carbon dioxide and water.Because of the well known relationship of moles to atomic weights, the ratios that are arrived at by stoichiometry can be used to determine quantities by weight in a reaction described by a balanced equation. This is called composition stoichiometry.Gas stoichiometry deals with reactions involving gases, where the gases are at a known temperature, pressure, and volume and can be assumed to be ideal gases. For gases, the volume ratio is ideally the same by the ideal gas law, but the mass ratio of a single reaction has to be calculated from the molecular masses of the reactants and products. In practice, due to the existence of isotopes, molar masses are used instead when calculating the mass ratio.
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