biology 1 - Saddleback College
... Review you lecture notes in detail. Highlight new terms & concepts. Use the text to complete and correct your notes. Don’t forget to use your text glossary & index to help define terms and find subjects. This exam will focus on lecture on sex-linked characteristics, genetic disorders, DNA Replicatio ...
... Review you lecture notes in detail. Highlight new terms & concepts. Use the text to complete and correct your notes. Don’t forget to use your text glossary & index to help define terms and find subjects. This exam will focus on lecture on sex-linked characteristics, genetic disorders, DNA Replicatio ...
X-inactivation
... = site of transcription and processing of rRNAs, site of assembly of rRNA and proteins into two ribosomal subunits (subunits join to form cytoplasmic ribosomes) nucleoli disappear during mitosis, formed at telophase at specific sites of acrocentric chromosomes (satellite stalks of chromosomes Nos 13 ...
... = site of transcription and processing of rRNAs, site of assembly of rRNA and proteins into two ribosomal subunits (subunits join to form cytoplasmic ribosomes) nucleoli disappear during mitosis, formed at telophase at specific sites of acrocentric chromosomes (satellite stalks of chromosomes Nos 13 ...
Lecture NoteIV
... 4-1.2.3. Purification of DNA In addition to DNA, a cell extract contains significant quantities of protein and RNA which can be further purified by following methods4-1.2.3.1. Organic extraction and enzymatic digestion for the removal of contaminants It involves the addition of a mixture of phenol a ...
... 4-1.2.3. Purification of DNA In addition to DNA, a cell extract contains significant quantities of protein and RNA which can be further purified by following methods4-1.2.3.1. Organic extraction and enzymatic digestion for the removal of contaminants It involves the addition of a mixture of phenol a ...
Transposition and transposable elements
... • comprise 45% of human chromosomal DNA “middle repetitive DNA” • contribute to spontaneous mutation, genetic rearrangements, horizontal transfer of genetic material • aid speciation and genomic change (in bacteria transposons are often associated with antibiotic resistance genes) • cells must depre ...
... • comprise 45% of human chromosomal DNA “middle repetitive DNA” • contribute to spontaneous mutation, genetic rearrangements, horizontal transfer of genetic material • aid speciation and genomic change (in bacteria transposons are often associated with antibiotic resistance genes) • cells must depre ...
Recombinant DNA Lab
... Recombinant DNA refers to DNA of one organism inserted into the DNA of another. A Transformation refers to the process of creating recombinant DNA. The major tools of recombinant DNA technology are bacterial enzymes called restriction enzymes. Each enzyme recognizes a short, specific nucleotide sequ ...
... Recombinant DNA refers to DNA of one organism inserted into the DNA of another. A Transformation refers to the process of creating recombinant DNA. The major tools of recombinant DNA technology are bacterial enzymes called restriction enzymes. Each enzyme recognizes a short, specific nucleotide sequ ...
Document
... WiseGEEK:Clear Answers for Common Questions.(20032013). What are Some Disadvantages of cloning? http://wisegeek.org/what-are-some-disadvantages-ofcloning.htm ...
... WiseGEEK:Clear Answers for Common Questions.(20032013). What are Some Disadvantages of cloning? http://wisegeek.org/what-are-some-disadvantages-ofcloning.htm ...
Genetics Vocabulary Review
... * Knowing the vocabulary is half the battle . . . You must also know how to apply the terminology in order to answer questions about the ...
... * Knowing the vocabulary is half the battle . . . You must also know how to apply the terminology in order to answer questions about the ...
1 Introduction 2 Central Dogma of molecular biology 3 DNA
... base and the 5’ position a phosphate group. The sugar in DNA is de-oxyribose and that’s why the name de-oxyribonucleotide. DNA’s nucleotides are of two types: purines (A and G) and pyrimidines (C and T). They differ in the base. Nucleotides are connected using the phosphate group of one nucleotide w ...
... base and the 5’ position a phosphate group. The sugar in DNA is de-oxyribose and that’s why the name de-oxyribonucleotide. DNA’s nucleotides are of two types: purines (A and G) and pyrimidines (C and T). They differ in the base. Nucleotides are connected using the phosphate group of one nucleotide w ...
Identification of disease genes Mutational analyses Monogenic
... - Recessive mutations Two independent non-consanguineous individuals —> 4 mutations in the same gene If large consanguineous families with high LOD score, two families (mutations) may be sufficient. If only ONE large consanguineous family with high LOD score, there is a need to demonstrate that the ...
... - Recessive mutations Two independent non-consanguineous individuals —> 4 mutations in the same gene If large consanguineous families with high LOD score, two families (mutations) may be sufficient. If only ONE large consanguineous family with high LOD score, there is a need to demonstrate that the ...
File - Molecular Biology 2
... Modern cloning vectors contain a cluster of unique restriction sites called a polylinker or a multiple cloning site (Figure 1.2). Many cloning vectors are modified versions of plasmids, the extra-chromosomal, double-stranded circular molecules of DNA present in bacteria. Plasmids range from about 1 ...
... Modern cloning vectors contain a cluster of unique restriction sites called a polylinker or a multiple cloning site (Figure 1.2). Many cloning vectors are modified versions of plasmids, the extra-chromosomal, double-stranded circular molecules of DNA present in bacteria. Plasmids range from about 1 ...
Chapter 6 and 9 - Wando High School
... 15. Explain why genes that are close together would experience less crossing over than those that are further apart. The further the genes are from each other on the chromosome, the more likely that crossing over would occur between them 16. The four haploid cells produced by meiosis will become ___ ...
... 15. Explain why genes that are close together would experience less crossing over than those that are further apart. The further the genes are from each other on the chromosome, the more likely that crossing over would occur between them 16. The four haploid cells produced by meiosis will become ___ ...
DNA Structure, Function and Replication 1
... the cell must make a second copy of all the DNA in each chromosome; this process is called DNA replication. 6. Explain why DNA replication is needed before a cell divides into two daughter cells. ...
... the cell must make a second copy of all the DNA in each chromosome; this process is called DNA replication. 6. Explain why DNA replication is needed before a cell divides into two daughter cells. ...
Notes Packet - Ms. Ottolini`s Biology Wiki!
... C. The potential applications (uses) of the Human Genome Project are wide-ranging. The project can be used to identify genes that can cause genetic diseases when mutated. It can also be used to develop treatments such as gene therapy (discussed later in the notes) that target a particular mutated g ...
... C. The potential applications (uses) of the Human Genome Project are wide-ranging. The project can be used to identify genes that can cause genetic diseases when mutated. It can also be used to develop treatments such as gene therapy (discussed later in the notes) that target a particular mutated g ...
DNA extraction from cheek cells protocol I mailed to you
... you chew food. Before a cell can divide, the cell must make a second copy of all the DNA in each chromosome; this process is called DNA replication. 6. Explain why DNA replication is needed before a cell divides into two daughter cells. ...
... you chew food. Before a cell can divide, the cell must make a second copy of all the DNA in each chromosome; this process is called DNA replication. 6. Explain why DNA replication is needed before a cell divides into two daughter cells. ...
Microbial GeneticsIII MB - E
... 3. The transport of bacterial DNA to other bacteria via bacteriaphages is called (1) conjugation (2) transformation (3) transduction 4. This type of recombination commonly occurs between a pair of homologous DNA sequences (1) general recombination (2) site-specific recombination (3) replicative reco ...
... 3. The transport of bacterial DNA to other bacteria via bacteriaphages is called (1) conjugation (2) transformation (3) transduction 4. This type of recombination commonly occurs between a pair of homologous DNA sequences (1) general recombination (2) site-specific recombination (3) replicative reco ...
Complete the following chart using your genetic code chart worksheet:
... 3. A mutation in which a single base is added or deleted from DNA is called a. A frameshift mutation b. A point mutation c. Translocation d. Nondisjunction 4. When part of one chromosome breaks off and is added to a different chromosome, the result is a. Translocation b. Insertion c. Inversion d. De ...
... 3. A mutation in which a single base is added or deleted from DNA is called a. A frameshift mutation b. A point mutation c. Translocation d. Nondisjunction 4. When part of one chromosome breaks off and is added to a different chromosome, the result is a. Translocation b. Insertion c. Inversion d. De ...
Study guide unit 3
... 5. How are maggots used to determine the post mortem interval? 6. What types of insects feed on a corpse? 7. How do weather conditions, CO2, burial depth, and water affect the fly life cycle? 8. What are some of the animals that feed on a corpse submerged in water? 9. What tissues do the following p ...
... 5. How are maggots used to determine the post mortem interval? 6. What types of insects feed on a corpse? 7. How do weather conditions, CO2, burial depth, and water affect the fly life cycle? 8. What are some of the animals that feed on a corpse submerged in water? 9. What tissues do the following p ...
Evolution of Plant Genomes Narrative
... monocots and dicots. The grapevine genome provided important evidence that appears to have resolved this question. Grape is considered an ancestor of the rosids, the group of species that include A. thaliana. Using the same dot blot approach, it was shown that most regions of the grape genome share ...
... monocots and dicots. The grapevine genome provided important evidence that appears to have resolved this question. Grape is considered an ancestor of the rosids, the group of species that include A. thaliana. Using the same dot blot approach, it was shown that most regions of the grape genome share ...
Molecular Biology BIO 250
... Know what linkage is. How is the behavior of linked genes during meiosis different from genes that Mendel studied? Which one of Mendel’s laws does not apply when two genes are linked? How is genetic distance between two genes located on the same chromosome calculated using linkage? Who discovere ...
... Know what linkage is. How is the behavior of linked genes during meiosis different from genes that Mendel studied? Which one of Mendel’s laws does not apply when two genes are linked? How is genetic distance between two genes located on the same chromosome calculated using linkage? Who discovere ...
Prof. Kamakaka`s Lecture 15 Notes
... Amount of DNA varies between species Amount of DNA varies in eukaryotes Salamander genomes are 20 times larger than human genomes Barley genome is 10 times larger than the rice genome Barley and rice are related. Measurements of DNA length Amount of DNA/nucleus = C value ...
... Amount of DNA varies between species Amount of DNA varies in eukaryotes Salamander genomes are 20 times larger than human genomes Barley genome is 10 times larger than the rice genome Barley and rice are related. Measurements of DNA length Amount of DNA/nucleus = C value ...
Genomic library
A genomic library is a collection of the total genomic DNA from a single organism. The DNA is stored in a population of identical vectors, each containing a different insert of DNA. In order to construct a genomic library, the organism's DNA is extracted from cells and then digested with a restriction enzyme to cut the DNA into fragments of a specific size. The fragments are then inserted into the vector using DNA ligase. Next, the vector DNA can be taken up by a host organism - commonly a population of Escherichia coli or yeast - with each cell containing only one vector molecule. Using a host cell to carry the vector allows for easy amplification and retrieval of specific clones from the library for analysis.There are several kinds of vectors available with various insert capacities. Generally, libraries made from organisms with larger genomes require vectors featuring larger inserts, thereby fewer vector molecules are needed to make the library. Researchers can choose a vector also considering the ideal insert size to find a desired number of clones necessary for full genome coverage.Genomic libraries are commonly used for sequencing applications. They have played an important role in the whole genome sequencing of several organisms, including the human genome and several model organisms.