Full Text
... modular group H(3) = PSL(2, Z). In [5], to solve the problem for N = 2 and N = 3, Kern-Isberner and Rosenberger used the some facts about the group structures of the Hecke groups H( 2) and H( 3) where λq = 2cos(π/q) and q = 4, 6, respectively. Aside from the modular group, these Hecke groups are th ...
... modular group H(3) = PSL(2, Z). In [5], to solve the problem for N = 2 and N = 3, Kern-Isberner and Rosenberger used the some facts about the group structures of the Hecke groups H( 2) and H( 3) where λq = 2cos(π/q) and q = 4, 6, respectively. Aside from the modular group, these Hecke groups are th ...
COS 338_day17
... If Protection A costs $1,000 per year, use it. If Protection A costs $4,000 per year, don’t use it. ...
... If Protection A costs $1,000 per year, use it. If Protection A costs $4,000 per year, don’t use it. ...
Search - Temple University
... That is, what sequence of indexes are compared with the key for a specific input key? Write the binary search algorithm for it Advantages and disadvantages compared with linear search (also called sequential search) How to use Arrays.binarySearch ( ) ...
... That is, what sequence of indexes are compared with the key for a specific input key? Write the binary search algorithm for it Advantages and disadvantages compared with linear search (also called sequential search) How to use Arrays.binarySearch ( ) ...
Enriched Pre-Algebra Chapter 4 Test Review Short Answer Each
... Write a proportion to determine the missing measure. Round to the nearest tenth, if necessary. 14. The Eiffel Tower in Paris casts a shadow that is about 558.7 feet long. At the same time, a nearby tourist casts a shadow that is 3.4 feet long. If the tourist is 6 feet tall, what is the height of the ...
... Write a proportion to determine the missing measure. Round to the nearest tenth, if necessary. 14. The Eiffel Tower in Paris casts a shadow that is about 558.7 feet long. At the same time, a nearby tourist casts a shadow that is 3.4 feet long. If the tourist is 6 feet tall, what is the height of the ...
Shor`s Algorithm for Factorizing Large Integers
... several hundred digits long), factorize n as a product of primes. We will assume (both for simplicity and with a view to RSA cryptanalysis) that n = pq where p and q are large unknown primes. We must determine p and q. ...
... several hundred digits long), factorize n as a product of primes. We will assume (both for simplicity and with a view to RSA cryptanalysis) that n = pq where p and q are large unknown primes. We must determine p and q. ...
PowerPoint
... 2(H) Write linear inequalities in two variables given a table of values, a graph, and a verbal description. A.5(B) Solve linear inequalities in one variable, including those for which the application of the distributive property is necessary and for which variables are included on both sides. Mathem ...
... 2(H) Write linear inequalities in two variables given a table of values, a graph, and a verbal description. A.5(B) Solve linear inequalities in one variable, including those for which the application of the distributive property is necessary and for which variables are included on both sides. Mathem ...
Chapter 1 Security Problems in Computing
... The public key is the set of integers of a knapsack problem (the general knapsack); the private key is a corresponding superincreasing knapsack (or simple knapsack). A sample general knapsack: (17, 38, 73, 4, 11, 1) A sample superincreasing knapsack: (1, 4, 11, 17, 38, 73), where each item ak ...
... The public key is the set of integers of a knapsack problem (the general knapsack); the private key is a corresponding superincreasing knapsack (or simple knapsack). A sample general knapsack: (17, 38, 73, 4, 11, 1) A sample superincreasing knapsack: (1, 4, 11, 17, 38, 73), where each item ak ...
Algebra 1 Essentials Chapter 3 Quiz
... Identify the choice that best completes the statement or answers the question. Solve the equation. ____ ...
... Identify the choice that best completes the statement or answers the question. Solve the equation. ____ ...
Homework 4: Solutions
... this is equal to previous(y) next(y) x, which in turn is equal to next(y) since previous(y) = x so that previous(y) x = 0. To start the traversal, we must know the address of two nodes in direct succession of each other. Starting in the head, which still has the previous and next pointers, we ...
... this is equal to previous(y) next(y) x, which in turn is equal to next(y) since previous(y) = x so that previous(y) x = 0. To start the traversal, we must know the address of two nodes in direct succession of each other. Starting in the head, which still has the previous and next pointers, we ...
On Designatedly Verified (Non-interactive) Watermarking Schemes
... multimedia information. A straightforward way to protect against above attacks is to completely encrypt the data and thereby require the end user to have the ...
... multimedia information. A straightforward way to protect against above attacks is to completely encrypt the data and thereby require the end user to have the ...
Factoring and DL
... 61. On or about June 30, 1992, Plaintiff submitted a CJ Request to Defendant STATE DEPARTMENT to determine whether publication of 1) the paper entitled "The Snuffle Encryption System," 2) source code for the encryption portion of Snuffle, and 3) source code for the decryption portion of Snuffle requ ...
... 61. On or about June 30, 1992, Plaintiff submitted a CJ Request to Defendant STATE DEPARTMENT to determine whether publication of 1) the paper entitled "The Snuffle Encryption System," 2) source code for the encryption portion of Snuffle, and 3) source code for the decryption portion of Snuffle requ ...
Writing Expressions
... 13 - n = thirteen decreased by a number or a number less than thirteen or thirteen minus a number 5n = five times a number n + 8 = a number increased by eight or eight more than a number or a number plus eight ...
... 13 - n = thirteen decreased by a number or a number less than thirteen or thirteen minus a number 5n = five times a number n + 8 = a number increased by eight or eight more than a number or a number plus eight ...
Extended Hidden Number Problem and Its
... guideline for a cryptanalyst deciding which method to choose by the kind and amount of information she has. In §4, we define EHNP, present a lattice-based algorithm for searching candidate solution in polynomial time, and investigate correctness of that solution. To give an illustrative presentation ...
... guideline for a cryptanalyst deciding which method to choose by the kind and amount of information she has. In §4, we define EHNP, present a lattice-based algorithm for searching candidate solution in polynomial time, and investigate correctness of that solution. To give an illustrative presentation ...
Heap Sort
... data structure implemented as an array of objects, where the search keys correspond to the array indices ► Insert and find operations involve straight forward array accesses: O(1) time complexity ...
... data structure implemented as an array of objects, where the search keys correspond to the array indices ► Insert and find operations involve straight forward array accesses: O(1) time complexity ...
Devireddy
... Wired Equivalent Privacy (WEP), a security protocol for wireless local area networks (WLANs) defined in the 802.11b standard. LANs are more secure than WLANs. WLANs, which are over radio waves are more vulnerable to tampering. WEP provides security by encrypting data ...
... Wired Equivalent Privacy (WEP), a security protocol for wireless local area networks (WLANs) defined in the 802.11b standard. LANs are more secure than WLANs. WLANs, which are over radio waves are more vulnerable to tampering. WEP provides security by encrypting data ...
ppt
... One-way functions are essential to the two guards password problem • Are we done? Given a noninteracive identification protocol want to define a one-way function • Define function f(r) as the mapping that Alice does in the setup phase between her random bits r and the information y given to Bob and ...
... One-way functions are essential to the two guards password problem • Are we done? Given a noninteracive identification protocol want to define a one-way function • Define function f(r) as the mapping that Alice does in the setup phase between her random bits r and the information y given to Bob and ...
Issue 43 Key RSC Discussion
... of the 4-way handshake, along with the current receive sequence counter (KeyRSC) for messages protected under that key. Since the WTP maintains the active KeyRSC, the AC currently has no way to know precisely what the correct value is at the point at which message 3 is constructed. To work around th ...
... of the 4-way handshake, along with the current receive sequence counter (KeyRSC) for messages protected under that key. Since the WTP maintains the active KeyRSC, the AC currently has no way to know precisely what the correct value is at the point at which message 3 is constructed. To work around th ...
Chapter 19: Security - Murray State University
... 2004 Deitel & Associates, Inc. All rights reserved. ...
... 2004 Deitel & Associates, Inc. All rights reserved. ...
How to Encrypt with the LPN Problem
... Related work. We briefly review the related work building cryptographic primitives based on hard learning problems. We have already cited the authentication protocol HB+ [19], which was itself derived from a simpler protocol named HB by Hopper and Blum [17]. Both protocols possess a proof of securi ...
... Related work. We briefly review the related work building cryptographic primitives based on hard learning problems. We have already cited the authentication protocol HB+ [19], which was itself derived from a simpler protocol named HB by Hopper and Blum [17]. Both protocols possess a proof of securi ...
Data security based on multipath routing.
... Replicating the CA, introduces the problem of maintaining the synchronization across the multiple CA’s ...
... Replicating the CA, introduces the problem of maintaining the synchronization across the multiple CA’s ...
離散對數密碼系統 - 國立交通大學資訊工程學系NCTU Department of
... Algorithms for Discrete Logarithm • Shanks’ algorithm (1972) – Compute L1 = {(i, gmi), i = 0, 1, …, m-1} L2 = {(i, ag-i), i = 0, 1, …, m-1} – where m = ceiling((p-1) ½) Sort L1 and L2 with respect to the 2nd coordinate. – Find the same 2nd coordinate from L1 and L2, say, (q, gmq), (r, ag-r), to get ...
... Algorithms for Discrete Logarithm • Shanks’ algorithm (1972) – Compute L1 = {(i, gmi), i = 0, 1, …, m-1} L2 = {(i, ag-i), i = 0, 1, …, m-1} – where m = ceiling((p-1) ½) Sort L1 and L2 with respect to the 2nd coordinate. – Find the same 2nd coordinate from L1 and L2, say, (q, gmq), (r, ag-r), to get ...
An IPSec-based Host Architecture for Secure
... Host architecture: Design tenets • The security mechanism should be independent of the routing method. • Separate key management from data handling • Use existing components when possible (In particular, IPSec) • Minimize changes to OS kernel • Maintain ability to plug-in different crypto ...
... Host architecture: Design tenets • The security mechanism should be independent of the routing method. • Separate key management from data handling • Use existing components when possible (In particular, IPSec) • Minimize changes to OS kernel • Maintain ability to plug-in different crypto ...
Diffie–Hellman key exchange
Diffie–Hellman key exchange (D–H) is a specific method of securely exchanging cryptographic keys over a public channel and was one of the first public-key protocols as originally conceptualized by Ralph Merkle. D–H is one of the earliest practical examples of public key exchange implemented within the field of cryptography. The Diffie–Hellman key exchange method allows two parties that have no prior knowledge of each other to jointly establish a shared secret key over an insecure channel. This key can then be used to encrypt subsequent communications using a symmetric key cipher.The scheme was first published by Whitfield Diffie and Martin Hellman in 1976. By 1975, James H. Ellis, Clifford Cocks and Malcolm J. Williamson within GCHQ, the British signals intelligence agency, had also shown how public-key cryptography could be achieved; however, their work was kept secret until 1997.Although Diffie–Hellman key agreement itself is a non-authenticated key-agreement protocol, it provides the basis for a variety of authenticated protocols, and is used to provide perfect forward secrecy in Transport Layer Security's ephemeral modes (referred to as EDH or DHE depending on the cipher suite).The method was followed shortly afterwards by RSA, an implementation of public-key cryptography using asymmetric algorithms.U.S. Patent 4,200,770, from 1977, is now expired and describes the now public domain algorithm. It credits Hellman, Diffie, and Merkle as inventors.