Download Decimal Numbers Grade 5

ID : ww-5-Decimal-Numbers [1]
Grade 5
Decimal Numbers
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Answer t he quest ions
(1)
At a construction site, there are 14.5 loads of bricks, and the total weight of all the loads
together is 720.94 kgs. What is the weight of one load?
(2)
What is the value of 0.3762 ÷ 0.06?
(3)
What is the smallest number should be added to 5.05 to give an even number?
(4) What is the place value of 2 in 8491.0632?
(5)
What is the smallest number should be subtracted f rom 7.55 to give a prime number?
Choose correct answer(s) f rom given choice
(6) T he place 1000000 times smaller than the Hundreds place is called :
a. T he T housandths Place
b. T he T en thousandths Place
c. T he T housands Place
d. T he T ens Place
(7) Sarah drove 63.75 kms to visit her grandmother. When she reached her grandmother's house
she noticed the car had used up 3.4 litres of petrol. How many kilometers did she travel per litre
of petrol?
(8)
a. 18.73 km
b. 18.75 km
c. 18.85 km
d. 18.92 km
What do you get when you subtract 758.11 f rom 819.33?
a. 62.72
b. 61.22
c. 6.122
d. 59.12
(9) A slug can move a distance of 33.6 meters in 3.5 hours. What distance can it travel in 4 days?
a. 920.2 m
b. 925.6 m
c. 918.9 m
d. 921.6 m
(10) Which number is 0.47 larger than the largest 2-digit number?
a. 10.47
b. 98.53
c. 99.47
d. 9.53
(11) What do you get when you subtract the sum of 321.55 and 34.98 f rom 454.95?
a. 34.98
b. 98.42
c. 741.52
d. 168.38
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ID : ww-5-Decimal-Numbers [2]
Fill in t he blanks
(12) Barbara's f ather gave her $189 to spend. She spent $67.55 to buy some toys and $60.03 to buy
some books. She now has $
lef t.
(13) Kevin purchased 45 pins to share with his classmates. If it cost him $11.7 to buy them, then the
price of each item is $
(14) Solve the f ollowing:
A)
C)
(15)
+ 41.41 = 1014.6
244.63 -
= 7.58
B)
D)
756.39 -
= 25.78
- 705.3 = 59.14
21 T ens + 35 T en thousandths =
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ID : ww-5-Decimal-Numbers [3]
Answers
(1)
49.72 kg
Step 1
T he number of loads of bricks = 14.5
Step 2
T otal weight of all the loads together = 720.94 kgs
Step 3
In order to f ind the weight of one load, we need to divide the total weight by the number of
loads.
Step 4
T heref ore, the weight of one load is 720.94 ÷ 14.5 = 49.72 kg.
(2)
6.27
(3)
0.95
(4) 2 T en thousandths
Step 1
Let’s use the place value chart and f ind where 2 is placed: 84910632
| Lakhs| T housands|
| T L| L|
Ones| T enths| Hundredths| T housandths| T en thousandths|
T T H| T H| H| T | O| . (1/10)|
8
4 9 1 .
0
(1/100)|
6
(1/1000)|
3
(1/10000)|
2
Legend:
T L - T en Lakhs, L - Lakhs, T T H - T en T housands, T H - T housands, H - Hundreds, T T ens, O - Ones.
Step 2
From the above table, we observe that 2 is placed under the T en thousandths place.
Step 3
Hence, the place value of 2 in 8491.0632 is 2 T en thousandths.
(5)
0.55
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ID : ww-5-Decimal-Numbers [4]
(6) b. T he T en thousandths Place
Step 1
In order to f ind the place value which is 1000000 times smaller than the Hundreds place, let
us divide 100 by 1000000:
100
= 0.0001
1000000
Step 2
Let us see what is the place of 1 in the number 0.0001:
| T housands| Ones| T enths| Hundredths| T housandths| T en thousandths|
| T T H| T H| H|T |O| . (1/10)|
0 .
0
(1/100)|
0
(1/1000)|
0
(1/10000)|
1
Legend:
T T H - T en T housands, T H - T housands, H - Hundreds, T - T ens, O - Ones.
We see that 1 is placed in the T en thousandths place.
Step 3
T heref ore, the place 1000000 times smaller than the Hundreds place is called the T en
thousandths place.
(7) b. 18.75 km
Step 1
Distance that Sarah drove to reach her grandmother's house = 63.75 kms
Step 2
Number of litres used while driving = 3.4 litres
Step 3
In order to know the number of kilometres per litre of petrol, we will need to divide the
number of kilometers traveled Sarah by the number of litres of petrol used.
Step 4
T hus, the number of kilometers Sarah travelled per litre of petrol = 63.75 ÷ 3.4 = 18.75
km/litre
Step 5
T heref ore, the kilometres per litre of petrol (mileage of the car) is 18.75 km/liter.
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ID : ww-5-Decimal-Numbers [5]
(8)
b. 61.22
Step 1
Decimals with the same number of decimal places are called Like Decimals. T he numbers
given here are theref ore Like Decimals.
Step 2
We need to subtract 758.11 f rom 819.33. T heref ore, 819.33 must be placed on top and
758.11 below. T he digits of the two numbers must be placed according to their place values.
Step 3
Let us now do the subtraction of the two numbers digit by digit, starting f rom the
hundredths and borrowing if needed:
T housands Hundreds T ens Ones . T enth Hundredth
-
8
1
9
.
3
3
7
5
8
.
1
1
0
6
1
.
2
2
Step 4
Hence, when we subtract 758.11 f rom 819.33, we get 61.22.
(9) d. 921.6 m
(10) c. 99.47
Step 1
T he largest 2-digit number is 99 (a whole number).
Step 2
T he number 0.47 larger than 99 can be f ound by adding the numbers 0.47 and 99.
Step 3
Let us f irst convert the whole number 99 into decimal f orm. In decimal f orm, 99 can be
written as 99.00. Decimals with the same number of decimal places are called like decimals.
Step 4
Now, our task is to add the Like Decimals 0.47 and 99.00. Let us add them starting f rom the
hundredths and carry over if needed. T he decimal point in the answer will be placed as
being placed in the addends:
Hundred
T housands
T en
T housands
T housands Hundreds T ens Ones . T enth Hundredth
9
+
9
9
.
0
0
0
.
4
7
9
.
4
7
Step 5
Hence, the number 0.47 larger than the largest 2-digit number is 99.47.
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ID : ww-5-Decimal-Numbers [6]
(11) b. 98.42
Step 1
Let us f irst f ind the sum of the Like Decimal numbers 321.55 and 34.98. Decimals with the
same number of decimal places are called Like Decimals.
Step 2
Let us add starting f rom the hundredths and carry over if needed. T he decimal point in the
answer will be placed as being placed in the addends:
T en T housands T housands Hundreds T ens Ones . T enth Hundredth
3
+
3
2
1
.
5
5
3
4
.
9
8
5
6
.
5
3
Step 3
Let us now subtract the sum 356.53 f rom 454.95 by placing the digits of these two Like
Fractions according to their place values
T en T housands T housands Hundreds T ens Ones . T enth Hundredth
-
4
5
4
.
9
5
3
5
6
.
5
3
0
9
8
.
4
2
Step 4
Hence, when we subtract the sum of 321.55 and 34.98 f rom 454.95, we get 98.42.
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ID : ww-5-Decimal-Numbers [7]
(12)
61.42
Step 1
T he amount of money that Barbara's f ather gave her = $189
Step 2
T he amount that Barbara spent in buying toys = $67.55
Step 3
T he amount that Barbara spent in buying books = $60.03
Step 4
Let us add the amount she spent in buying toys and books to f ind her total expense:
T oys
= $67.55
Books
= $60.03
T otal expense = $127.58
Step 5
In order to f ind the amount lef t with her, we need to subtract the amount Barbara's f ather
gave and the amount Barbara spent.
Step 6
Bef ore subtracting the two numbers, let us make sure they are written as Like Decimals.
Decimals with the same number of decimal places are called Like Decimals. T hus, let us
write $189 as $189.00, and subtract $127.58 f rom it
Step 7
Let us subtract the amount Barbara spent ($127.58) f rom the amount her f ather gave
($189) digit by digit. T he numbers must be placed according to their place values. T he
greater number must be placed on top and the lesser one below:
T housands Hundreds T ens Ones . T enth Hundredth
-
1
8
9
.
0
0
1
2
7
.
5
8
0
6
1
.
4
2
Step 8
Hence, Barbara is lef t with $61.42.
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ID : ww-5-Decimal-Numbers [8]
(13)
0.26
Step 1
Cost of 45 pins that Kevin purchased = $11.7
Step 2
T heref ore, the cost of 1 pins = 11.7 ÷ 45 = $0.26
Step 3
Hence, the cost of each pins is $0.26.
(14) A)
B)
C)
D)
(15)
973.19
730.61
237.05
764.44
210.0035
Step 1
First, let us convert the number names into numerals as below:
21 T ens = 21 × 10 = 210
35 T en thousandths = 35 ÷ 10000 = 0.0035
Step 2
Let’s now add the two numbers:
| T housands|
Lakhs|
| T L| L|
Ones| T enths| Hundredths| T housandths| T en thousandths|
T T H| T H| H| T | O| . (1/10)|
T otal
(1/100)|
(1/1000)|
(1/10000)|
2 1 0 .
0
0
0
0
0 .
0
0
3
5
2 1 0 .
0
0
3
5
Legend:
T L - T en Lakhs, L - Lakhs, T T H - T en T housands, T H - T housands, H - Hundreds, T T ens, O - Ones.
Step 3
T hus, 21 T ens + 35 T en thousandths = 210.0035
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