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Transcript
國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
☆☆請在答案紙上作答☆☆
第 1 頁,共 14 頁
本試卷共有九個摘要,48 題試題。根據試題之前的摘要內容回答試題。每一試題 2 分
(41-48 題除外,每題 2.5 分)。
一、
1. The purpose of the RT-PCR method is to
(A) extract viruses from urban sludge
(B) remove PCR inhibitors
(C) quantify enterovirus RNA levels
(D) quantify poliovirus RNA levels
-1-
國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
☆☆請在答案紙上作答☆☆
第 2 頁,共 14 頁
2. The amplified PCR products were detected by
(A) fluorogenic probes
(B) RNeasy mini kit
(C) PVP
(D) Ribogreen method
3. The Mahoney type I poliovirus RNA served as
(A) control samples
(B) amplification templates
(C) standard samples
(D) amplification inhibitors
4. Which of the following is not mentioned as a desired characteristic of the RT-PCR method?
(A) high sensitivity
(B) high through-put
(C) low cost
(D) high reproducibility
5. Which journal this article would be most likely to appear in?
(A) Journal of Biological Chemistry
(B) Trends in Neurosciences
(C) Biotechniques
(D) Ecology
二、
-2-
國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
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第 3 頁,共 14 頁
6. Which of the following is an important characteristic for a circadian oscillator
(A) unusual neuronal activity
(B) spontaneous cycle of neuronal activity
(C) being controlled by SCN
(D) being connected to other parts of the brains
7. SCN
(A) is the only circadian oscillator in mammals
(B) is an endocrine tissue
(C) dictates our physiological and behavioral rhythms
(D) is a universal circadian oscillator for all animals
8. Which of the following statements is true
(A) a circadian oscillator is independent of the external world
(B) a circadian oscillator is synchronized to the external world
(C) the number of SCN neurons is far more than 10000
(D) the molecular mechanism of timekeeping is mostly unraveled
9. Our physiological and behavioral rhythms are
(A) unchangable
(B) controlled by circadian oscillators
(C) independent of any circadian oscillators
(D) not synchronized to the external world
10. Which journal this article would be most likely to appear in?
(A) Journal of Biological Chemistry
(B) Trends in Neurosciences
(C) Biotechniques
(D) Ecology
三、
Glyceraldehyde-3-phosphate dehydrogenase (GAPDH) and triosephosphate isomerase (TPI) are
essential to glycolysis, the major route of carbohydrate breakdown in eukaryotes. In animals and other
heterotrophic eukaryotes, both enzymes are localized in the cytosol; in photosynthetic eukaryotes,
GAPDH and TPI exist as isoenzymes that function in the glycolytic pathway of the cytosol and in the
-3-
國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
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第 4 頁,共 14 頁
Calvin cycle of chloroplasts. Recent studies showed that diatoms—photosynthetic protists that acquired
their plastids through secondary symbiotic engulfment of a eukaryotic rhodophyte—possess an
additional isoenzyme each of both GAPDH and TPI. Surprisingly, these new forms are expressed as a
TPI-GAPDH fusion protein which is imported into mitochondria prior to its assembly into a tetrameric
bifunctional enzyme complex. Homologs of this translational fusion are shown to be conserved and
expressed also in nonphotosynthetic, heterokont-flagellated oomycetes. Phylogenetic analyses show
that mitochondrial GAPDH and its N-terminal TPI fusion branch deeply within their respective
eukaryotic protein phylogenies, suggesting that diatom mitochondria may have retained an ancestral
state of glycolytic compartmentation that existed at the onset of mitochondrial symbiosis. These
findings strongly support the view that nuclear genes for enzymes of glycolysis in eukaryotes were
acquired from mitochondrial genomes and provide new insights into the evolutionary history
(host-symbiont relationships) of diatoms and other heterokont-flagellated protists.
11. According to the preceding discussion, how many GAPDH isoenzymes can be found in a diatom
cell?
(A)
(B)
(C)
(D)
None
1
2
3
12. A triosephosphate isomerase (TPI) isoenzyme can not be found in:
(A) the cytosol of an animal cell
(B) mitochondria of a diatom cell
(C) mitochondria of an animal cell
(D) chloroplasts of a plant cell
13. According to the preceding paragraph, which of the following statements concerning the
relationship between diatoms and oomycetes is most likely to be true?
(A) Diatoms and oomycetes are close relatives.
(B) Diatoms are plants whereas oomycetes are not.
(C) Oomycetes acquire their TPI-GAPDH fusion protein gene from diatoms.
(D) Diatoms acquire their TPI-GAPDH fusion protein gene from oomycetes.
-4-
國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
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第 5 頁,共 14 頁
14. The functional conformation of the TPI-GAPDH enzyme complex in diatoms is composed of:
(A) one TPI subunit and one GAPDH subunit
(B) a single TPI-GAPDH fusion protein
(C) two identical TPI-GAPDH fusion proteins
(D) four identical TPI-GAPDH fusion proteins
15. Discovery of the mitochondrium-localized TPI-GAPDH enzyme complex in diatoms lends support
to the view that:
(A) Diatoms depend on their mitochondria for glycolytic enzymes.
(B) The diatom mitochondrium represents an evolutionarily primitive stage of this ubiquitous
organelle.
(C) The diatom mitochondrium is an evolutionary vestige descended from a secondary
photosynthetic endosymbiotic protist.
(D) Diatoms carry out carbon fixation in their mitochondria using the Calvin cycle
四、
Enzymes that participate in biosynthetic pathways of essential amino acids have been recognized
as targets for a number of safe and effective herbicides. The biosynthetic pathway to the
branched-chain amino acids valine, leucine, and isoleucine is of special importance in this respect. At
least three classes of very potent and extensively used herbicides, the sulfonylureas, the
imidazolinones, and the sulfonanilides, are known to inhibit the first common enzyme in this
pathway, acetohydroxy acid synthase (AHAS; EC 4.1.3.18). The second common enzyme in the
pathway, ketol-acid reductoisomerase (KARI; EC 1.1.1.86), is the target for two additional
inhibitors with potential herbicidal activity, 2-dimethylphosphinoyl-2-hydroxyacetate and
N-isopropyl oxalylhydroxamate(IpOHA). Sulfometuron methyl (SMM), which belongs to the
sulfonylurea class of herbicides and inhibits AHAS activity, is an extremely potent herbicide and
bacteriostatic agent. The potency of SMM has been ascribed in part to the toxicity of one of the
substrates of AHAS, 2-ketobutyrate, which accumulates upon inhibition of the enzyme. It has been
proposed that high 2-ketobutyrate levels interfere with a number of metabolic pathways, including
synthesis of coenzyme A, by several mechanisms. IpOHA also causes the accumulation in bacterial
growth media of a substrate of the enzyme which it inhibits, acetolactate. However, there are no
reports in the literature on the intracellular concentrations of the KARI substrate acetolactate or
acetohydroxybutyrate. In the enterobacteria, transcription of ilvC, the gene which encodes KARI, is
-5-
國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
☆☆請在答案紙上作答☆☆
第 6 頁,共 14 頁
induced by the enzyme’s substrates. Thus, an increase in substrate concentrations due to partial
inhibition of the enzyme should lead to a compensating enhancement of the rate of the reaction by
increasing enzyme synthesis (as well as by mass action, if KARI normally works well below its Km).
16. In plant and bacterial cells, biosynthesis of which of the following substances can be inhibited by
the herbicide 2-dimethylphosphinoyl-2-hydroxyacetate?
(A) ketobutyrate
(B) sulfometuron methyl
(C) isoleucine
(D) acetohydroxy acid synthase
17. In enterobacteria, synthesis of the enzyme ketol-acid reductoisomerase increases in direct response
to an increase in the concentration of:
(A) coenzyme A
(B) valine
(C) ketobutyrate
(D) acetolactate
18. Which of the following manipulations causes the toxic accumulation of 2-ketobutyrate in plant cells?
(A) inhibiting the enzyme ketol-acid reductoisomerase
(B) stimulating the expression of the gene ilvC
(C) administering the compound sulfometuron methyl
(D) administering the compound N-isopropyl oxalylhydroxamate
19. Which of the following enzymes or compounds does not participate directly in the synthesis of
branched chain amino acids?
(A) acetohydroxy acid synthase
(B) coenzyme A
(C) ketol-acid reductoisomerase
(D) acetolactate
20. In keeping with the reasoning in this paragraph, the authors are most likely trying to address
which of the following questions?
(A)What are the toxic effects of N-isopropyl oxalylhydroxamate on cellular metabolism?
(B) How does inhibition of conenzyme A synthesis contribute to the toxic effects of
sulfometuron methyl?
(C) How are acetohydroxy acid synthase activity and ilvC expression regulated in plants?
(D)How do weeds and bacteria develop resistance to herbicides N-isopropyl
oxalylhydroxamate and sulfometuron methyl?
-6-
國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
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第 7 頁,共 14 頁
五、
Therapy for patients with advanced thyroid carcinoma is limited. Clinical and in vitro studies
suggest that some patients with advanced thyroid cancer may respond to therapy with retinoic acid.
mRNA expression of the six retinoic acid (RAR) and retinoid X receptor (RXR) isoforms
(RARalpha, -beta, -gamma and RXRalpha, -beta, -gamma) was measured in four human thyroid
cell lines, and protein expression was subsequently measured in 10 thyroid cancer cell lines. Two
isoforms, RARbeta and RXRgamma, were differentially expressed in the four cell lines.
Comparison of 10 thyroid tumors and matched normal thyroid tissue confirmed differential tumor
expression of RARbeta and RXRgamma and lack of the RXRgamma isoform in normal thyroid
tissue. Cell lines expressing both RARbeta and RXRgamma demonstrated significant growth
suppression when treated with retinoids, whereas cell lines lacking these isoforms were unaffected.
Expression of RARbeta, the isoform associated with suppression of tumor growth in other cancer
types, was not affected by treatment with retinoids in the thyroid cancer cell lines. LG346 increased
apoptosis and decreased cells in the S-phase in an anaplastic carcinoma cell line, suggesting that
this retinoid causes growth suppression of these cells by multiple mechanisms.
21. How many retinoic acid receptor isoforms in human cells?
(A) ten (B) six (C) four (D) three
22. The treatment with retinoids in the thyroid cancer cell may NOT results in ?
(A) expression of RARbeta
(B) apoptosis
(C) growth suppression
(D) all of the above
23. What is the reason that advanced thyroid cancer may not respond to therapy with retinoic acid?
(A) therapy is limited
(B) absence of RARbeta and RXRgamma
(C) lacks S-phase
(D) LG346 increased apoptosis
24. In normal thyroid tissue, which enzyme does not be expressed?
(A) RARbeta
(B) RXRgamma
(C) RARalpha
(D) RXRalpha
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國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
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第 8 頁,共 14 頁
六、
An antiserum, or an antibody, constitutes a useful reagent in protein biochemistry. However, it
is a reagent which is specific to the immunogen/antigen couple and often it must be prepared
in-house, especially when a novel protein is under investigation. Preparation of an antiserum starts
with the immunogen, which is usually a protein isolated by one or more of the methods described in
the previous chapters. The more pure the immunogen, the more specific will be the antibodies
which it elicits. For most purposes, therefore, it is best to use as pure an immunogen as possible.
Alternatively, for the production of so-called peptide antibodies, the immunogen might be a
synthetic peptide of ten or more residues. The peptide is chosen from the amino acid sequence of
the Ag of interest, i.e. the complete protein which it is hoped the Abs will recognize. For peptide
antibodies to recognize the whole protein, it is necessary that the peptide sequence chosen be
accessible, i.e. it must be on the surface of the protein. This can be readily determined if the 3-D
structure of the protein is known. If the 3-D structure is not known, then the peptide can be chosen
by analysis of the amino acid sequence of the Ag of interest for hydrophobicity (since hydrophilic
residues will tend to be on the surface) or mobility (since residues on the surface, and especially at
the N- or C-terminus are likely to be more mobile).
25. When a novel protein is under investigation, it is better to prepare its antibody by?
(A) the investigator
(B) the company
(C) the competitor
(D) anyone
26. How to increase the specificity of the antibodies?
(A) more pure antibodies
(B) more pure antigen
(C) more pure hydrophobicity
(D) more pure antiserum
27. The peptide antibodies are made by using?
(A) Antiserum
(B) synthetic peptide
(C) 3-D structure of the protein
(D) hydrophobicity
-8-
國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
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第 9 頁,共 14 頁
28. In general, the immunogen is?
(A) DNA
(B) RNA
(C) Protein
(D) lipid
29. What information can help to determine whether a specific peptide is on the surface of the protein?
(A) 3-D structure of the protein
(B) the hydrophobicity of the peptide
(C) mobility of the peptide
(D) all of the above
30. Why the peptide used for making peptide antibodies is better on the surface of the protein?
(A) it is easy to prepare
(B) to determine the 3-D structure of the protein
(C) for peptide antibodies to recognize the whole protein
(D) all of the above
七、
Dosage compensation ensures equal expression of X-linked genes in XX females and XY
males. In mammals, this process results in inactivation of one female X-chromosome (XCI) in a
random or imprinted manner. In the random form (eutherian), a zygotic counting mechanism
initiates dosage compensation and enables a choice mechanism to randomly designate one active
(Xa) and one inactive (Xi) X. In the imprinted form, zygotic counting and choice are superseded by
parental imprints that direct exclusive paternal X-silencing. Imprinted XCI is found in ancestral
marsupials but vestiges remain in the extraembryonic tissues of eutherians such as mice.
An epigenetic mark for random and imprinted XCI has long been postulated. The marks are
placed at the Xinactivation center (Xic), which includes the cis-acting noncoding gene, Xist, and its
antisense counterpart, Tsix. Xist RNA accumulation along the Xi initiates the silencing step, while
Tsix represses silencing by blocking Xist RNA accumulation. A cis-acting center for choice and
imprinting lies at the 5´ end of Tsix, as its deletion abolishes random choice in epiblast-derived cells
to favor inactivation of the mutated X and disrupts maternal Xist imprinting in extraembryonic
tissues. Thus, while imprinted XCI is parentally directed and random XCI is zygotically controlled,
both work through Tsix to regulate Xist.
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國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
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第 10 頁,共 14 頁
To date, only X-linked cis-elements have been identified as XCI regulators. Yet, virtually all
models invoke transacting factors, which interact with the X-linked sites. In one model for
imprinted XCI, a maternal-specific trans-factor confers resistance to XCI. In models for random
XCI, an autosomally expressed “blocking factor” protects a single X from silencing. We have
proposed that Tsix is the cis-target of both trans-factors.
31. Which of the following animals has imprinted form of X chromosome inactivation?
(A) human
(B) kangaroo
(C) orangutan
(D) cow
32. In the imprinted form of X chromosome inactivation, the X chromosomes originated from ______
were inactive.
(A) father
(B) mother
(C) both parents
(D) none of above
33. The Xinactivation center does not include
(A) Tsix
(B) Xist
(C) cis-acting center for choice and imprinting
(D) blocking factor
34. The synonym of superseded is
(A) supervised
(B) substituted
(C) separated
(D) summarized
35. The synonym of abolished is
(A) accumulated
(B) finished
(C) retreated
(D) ensured
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國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
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第 11 頁,共 14 頁
36. What is the essence of the cis-acting center for choice and imprinting?
(A) DNA
(B) RNA
(C) protein
(D) none of above
37. The X chromosomes are inactivated if
(A) Tsix gene is transcribed
(B) Xist gene is transcribed
(C) both genes are transcribed
(D) none of the genes are transcribed
38. Which of the following has not been identified according to the assay?
(A) Blocking factor
(B) XCI regulators
(C) Xist
(D) Tsix
39. Which of the following statements is not true?
(A) The X chromosome is active if the Xist mRNA is not produced.
(B) The X chromosome is active if a maternal-specific transcription factor is present.
(C) The X chromosome is not active if a X-linked blocking factor is not present.
(D) The X chromosome is not active if the XCI regulator is not bound by transcription factors.
40. Where is the cis-acting center for
choice and imprinting is located
on the figure in the right?
(A) A
Tsix
A
Xist
B
C
D
(B) B
(C) C
(D) D
八、
Transgenic animals have been routinely produced by microinjecting or electroporating naked DNA
into 1-cell-stage embryos or unfertilized eggs. However, these techniques are inapplicable to
- 11 -
國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
科目:專業英文
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第 12 頁,共 14 頁
live-bearing fish and many crustacean species for which unfertilized or newly fertilized eggs are not
readily obtainable. In the present study, replication-defective pantropic retroviral vectors carrying a
reporter gene (neo(R) or beta-gal) were used to directly transform the immature ovary or testis of a
live-bearing fish (Poeciliopsis lucida) and crayfish (Procambarus clarkii). The fraction of the progeny
derived from these treated individuals shown to contain the neo(R) reporter gene by an assay based on
polymerase chain reaction (PCR) was significant. The PCR-positive individuals were crossed with
nontransgenic individuals, and about 50% of the resulting progeny carried the transgene, suggesting that
the F(1) animals are germline transgenic. Integration of the transgenes was confirmed by detecting the
junction fragments of the genomic DNA associated with transgene constructs. Expression of reporter
genes was detected by a reverse transcription-nested PCR assay. These results showed that transgenic
live-bearing fish and crustaceans could be easily produced by directly transforming the immature gonads
with replication-defective pantropic retroviral vectors. (Sarmasik A, et al. 2001. Mar. Biotechnol.
(NY).3(5):470-7.)
41. How to confirm that progeny of the treated individuals contained the gene neo(R) reporter gene ?
(A) by microinjection,
(B) by electroporation,
(C) by PCR reaction,
(D) by replication-defective pantropic retroviral vectors.
42. What is the integration of the transgenes?
(A) PCR-positive individuals were crossed with nontransgenic individuals,
(B) F(1) animals are germline transgenic,
(C) junction fragments of the genomic DNA,
(D) the genomic DNA associated with transgene constructs.
43. In this study, what was not detected in the reverse transcription-nested PCR assay?
(A) expression of the neo(R) genes,
(B) live-bearing fish and crustaceans were transformed successfully,
(C) transgenic live-bearing fish and crustaceans were produced,
(D) replication-defective pantropic retroviral vectors were transformed.
九、
We estimated a novel phylogeny of tilapiine cichlid fish (an assemblage endemic to Africa and
the Near East) within the African cichlid fishes on the basis of complete mitochondrial NADH
- 12 -
國立彰化師範大學九十三學年度碩士班招生考試試題
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第 13 頁,共 14 頁
dehydrogenase subunit 2 (ND2) gene sequences. The ND2 (1,047 bp) gene was sequenced in 39
tilapiine cichlids (38 species and 1 subspecies) and in an additional 14 nontilapiine cichlid species in
order to evaluate the traditional morphologically based hypothesis of the respective monophyly of the
tilapiine and haplochromine cichlid fish assemblages. The analyses included many additional cichlid
lineages, not only the so-called tilapiines, but also lineages from Lake Tanganyika, east Africa, the
Neotropics and an out-group from Madagascar with a wide range of parental care and mating systems.
Our results suggest, in contrast to the historical morphology-based hypotheses from Regan (1920,
1922 ), Trewavas (1983), and Stiassny (1991), that the tilapiines do not form a monophyletic group
because there is strong evidence that the genus Tilapia is not monophyletic but divided into at least five
distinct groups. In contrast to this finding, an allozyme analysis of Pouyaud and Agnese (1995), largely
based on the same samples as used here, found a clustering of the Tilapia species into only two groups.
This discrepancy is likely caused by the difference in resolution power of the two marker systems used.
Our data suggest that only type species Tilapia sparrmanii Smith (1840) should retain the genus name
TILAPIA: One particular group of tilapiines (composed of genera Sarotherodon, Oreochromis,
Iranocichla, and Tristramella) is more closely related to an evolutionarily highly successful lineage, the
haplochromine cichlids that compose the adaptive radiations of cichlid species flocks of east Africa. It
appears that the highly adaptable biology of tilapiines is the ancestral state for all African cichlids and
that the more stenotypic lifestyle of the haplochromine cichlids is derived from this condition. We
reconstructed the evolution of the highly variable parental care systems on the basis of the most
inclusive composite phylogeny to date of the African, Neotropical, and Madagascan cichlids with
special emphasis on a group of tilapiines comprising the substrate-spawning genus Tilapia, and the
mouthbrooding genera Sarotherodon and OREOCHROMIS: We demonstrate several independent
origins of derived mouthbrooding behaviors in the family Cichlidae. (Klett V & Meyer A. 2002. Mol.
Biol. Evol. 19(6):865-83.)
44. What was not sequenced to estimate the phylogeny of tilapiine cichlid fish within the African cichlid
fishes
(A) the complete mitochondrial DNA,
(B) mitochondrial NADH dehydrogenase subunit 2,
(C) complete ND2 gene,
(D) 1,047 bp of the ND2 gene of mtDNA.
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國立彰化師範大學九十三學年度碩士班招生考試試題
系所:生物技術研究所
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45. How many species were used to evaluate the respective monophyly of the tilapiine and haplochromine
cichlid fish assemblages?
(A) 14 species,
(B) 39 species,
(C) 52 species,
(D) 53 species.
46. What was not the reason to added many other cichlid lineages in this study?
(A) They all belong to tilapiines,
(B) The all from Lake Tanganyika,
(C) To find an out-group from Madagascar,
(D) They all have the same parental care and mating systems.
47. What is the reason that results of this study were different from of Regan (1920, 1922 ), Trewavas (1983),
and Stiassny (1991)?
(A) tilapiines is a monophyletic group,
(B) specimens all belong to genus Tilapia,
(C) allozyme analysis,
(D) different resolution power of the two detected methods.
48. What narration is wrong in this writing?
(A) It was suggested that for all African cichlids were highly adaptable in their ancestral state,
(B) This study tried to establish the evolutionary history of the African, Neotropical, and
Madagascan cichlids,
(C) Pouyaud and Agnese (1995) suggested that Tilapia species only divided into two clusters.
(D) The mouthbrooding behaviors in the family Cichlidae were derived from the related species.
- 14 -