Download Find the ` (GCF) of 18x and 15x 3x Find the greatest common factor

1. Find the ` (GCF) of 18x and 15x 3
3x
2. Find the greatest common factor (GCF) of 28 a 3 b 2 and 44 ab 3
4ab2
3. Factor. Check by multiplying 4x 2 + 36x=
4x(x+9)
4. Factor. Check by multiplying

2 xy x 5 y 3  3x 3 y 2  4

2x 6 y 4  6 x 4 y 3  8 xy =
x 3 x  2  9x  2 =
5. Factor.


(x3+9)(x+2) x 3  9 x  2
6. Factor by grouping.
28 x 3  12 x 2  35 x  15 =
7. Factor by grouping.
x 3  9 x 2  2 x  18 =
7 x  34 x 2  5
x
2

 2  x  9
8. Factor the trinomial.
r 2  7r  12 =
(r+3)(r+4)
9. Factor the trinomial.
v 2  12v  35 =
(v-7)(v-5)
10. Factor.
r 2  2r  24 =
(r-6)(r+4)
11. Factor the trinomial.
w 2  3wg  54 g 2 =
w  9g w  6g 
12. Factor.
5s 2  14 s  3 =
13. Factor.
20r 2  17r  63 =
14. Factor.
28  26b  24b 2 =
5s  1s  3
4r  95r  7
 23b  24b  7
15. Factor the trinomial completely.
2r  73r  5
6r 2  11r  35 =
16. Factor. Note that the middle term has already been split.
s  3s  7
17. Factor by grouping.
v  33v  7
3v 2  2v  21 =
s 2  3s  7 s  21 =
18. Factor by grouping. 14a 2  45a  14 =
7a  22a  7
19. Factor by grouping.
6b 2  17b  3 =
6b  1b  3
20. Factor the trinomial.
6d 2  4d  16 =
2d  23d  4
21. Factor completely.
2c  3g 4c  3g 
9 g 2  18 gc  8c 2 =
22. Determine whether the expression is a trinomial square.
b 2  18b  81
b  9 2
Yes
23. Factor.
r 2  16r  64 =
r  82
24. Factor completely.
3v 2  48v  192 =
3v  8
2
25. Factor.
b 2  49 =
(b  7)(b  7)
26. Factor completely.
r  f r  f 
27. Factor.
r2  f 2=
49w  121w 3 =
w7  11w7  11w
28. Factor completely.
0.49 y
2
0.7 y  0.020.7 y  0.02

 0.0004 =
(Type the answer in factored form)
29. Factor completely. 1  b 8 =
1  b 1  b 1  b1  b
4
2
30. Factor completely.


2 r 2  4 r  2r  2
2r 4  32 =
31. Solve using the principle of zero products.
r  9r  64  0
r  9, r  64
32. Solve using the principle of zero products.
comma to separate answers.
c  0, c  6
cc  6  0 The solution is c=
Use a
33. Solve using the principle of zero products.
9t  54t  12  0
Use a comma to
separate answers.
t  5 9, t  3
34. Solve.
s 2  11s  24  0 The solution is s =
s=-8, s=-3
35. Solve.
s 2  6 s  0 The solution is s =
s=0, s=6
36. Use the graph to solve.
x 2  2 x  8  0 Use a comma to separate answers as
needed.
x  4, x  2
Graph of the function
y  x 2  2 x  8 . At the ponts where
the curve crosses the x-axis , y=0.
These are the solutions to the
equation.
Curve crosses x-axis at x=-4 and x=2
37. A rectangular table is three times as long as it is wide. If the area is 48 ft 2 find
the length and the width of the table.
width of table =w
length of table = 3w (3 times its width)
Area=length x width =3w2 = 48
Thus, w2=16, and hence w=4
Thus, Width of the table = 4 ft
Length of the table =12 ft
38. There are n teams in a league and the number of games played is given by the
polynomial n 2  n  n . A woman’s softball league has 12 teams. What is the total
number of games to be played?
12 teams in the league
The equation for number of games played is n 2  n  12 2  12  132
[Note: Please check if there is something wrong with the equation. n 2  n  n means n=2 .
which will not be true for n=12. Looks like there is some minor error in the equation]
39. The product of the page number on two facing pages of a book is 182. Find the page
numbers.
if the page number is x, the next page number is (x+1)
The product of these two numbers x(x+1)=182
or, x 2  x  182  0
This gives the solutions x  14, x  13
Since negative page number is not possible,
The page numbers are 13 and 14.