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Transcript
CHAPTER 5
Probability: What Are
the Chances?
5.2
Probability Rules
The Practice of Statistics, 5th Edition
Starnes, Tabor, Yates, Moore
Bedford Freeman Worth Publishers
Probability Rules
Learning Objectives
After this section, you should be able to:
 DESCRIBE a probability model for a chance process.
 USE basic probability rules, including the complement rule and the
addition rule for mutually exclusive events.
 USE a two-way table or Venn diagram to MODEL a chance process
and CALCULATE probabilities involving two events.
 USE the general addition rule to CALCULATE probabilities.
The Practice of Statistics, 5th Edition
2
Probability Models
In Section 5.1, we used simulation to imitate chance behavior.
Fortunately, we don’t have to always rely on simulations to determine
the probability of a particular outcome.
Descriptions of chance behavior contain two parts:
The sample space S of a chance process is the set of all possible
outcomes.
A probability model is a description of some chance process that
consists of two parts:
• a sample space S and
• a probability for each outcome.
The Practice of Statistics, 5th Edition
3
Example: Building a probability model
Sample Space
36 Outcomes
The Practice of Statistics, 5th Edition
Since the dice are fair, each outcome is equally
likely.
Each outcome has probability 1/36.
4
Probability Models
Probability models allow us to find the probability of any collection of
outcomes.
An event is any collection of outcomes from some chance
process. That is, an event is a subset of the sample space. Events
are usually designated by capital letters, like A, B, C, and so on.
If A is any event, we write its probability as P(A).
In the dice-rolling example, suppose we define event A as “sum is 5.”
There are 4 outcomes that result in a sum of 5.
Since each outcome has probability 1/36, P(A) = 4/36.
Suppose event B is defined as “sum is not 5.” What is P(B)?
P(B) = 1 – 4/36 = 32/36
The Practice of Statistics, 5th Edition
5
Basic Rules of Probability
• The probability of any event is a number between 0 and 1.
• All possible outcomes together must have probabilities whose sum
is exactly 1.
• If all outcomes in the sample space are equally likely, the probability
that event A occurs can be found using the formula
P(A) =
number of outcomes corresponding to event A
total number of outcomes in sample space
• The probability that an event does not occur is 1 minus the
probability that the event does occur.
• If two events have no outcomes in common, the probability that one
or the other occurs is the sum of their individual probabilities.
Two events A and B are mutually exclusive (disjoint) if they
have no outcomes in common and so can never occur together—
that is, if P(A and B ) = 0.
The Practice of Statistics, 5th Edition
6
Basic Rules of Probability
We can summarize the basic probability rules more concisely in
symbolic form.
Basic Probability Rules
•For any event A, 0 ≤ P(A) ≤ 1.
•If S is the sample space in a probability model,
P(S) = 1.
•In the case of equally likely outcomes,
number of outcomes corresponding to event A
P(A) =
total number of outcomes in sample space
•Complement rule: P(AC) = 1 – P(A)
•Addition rule for mutually exclusive events: If A and B are
mutually exclusive,
P(A or B) = P(A) + P(B).
The Practice of Statistics, 5th Edition
7
Two-Way Tables and Probability
When finding probabilities involving two events, a two-way table can
display the sample space in a way that makes probability calculations
easier.
Consider the example on page 309. Suppose we choose a student at
random. Find the probability that the student (a) has pierced ears.
(b) is a male with pierced ears.
(c) is a male or has pierced
ears.
Define events A: is male and B: has pierced ears.
(a)
(b) Each
(c)
We want
student
to find
is equally
P(male likely
or
and
pierced
pierced
to beears),
chosen.
ears),
that
that
103
is,is,
students
P(A
P(A
orand
B).have
There
B).
pierced
are
ears.
in
So,
theP(pierced
classofand
ears)
103
=
individuals
P(B)
103/178.
with
pierced
ears.There
Look90atmales
the intersection
the
“Male”
row=and
“Yes”
column.
are 19 males
with pierced
ears. So,
P(A
and B)
= 19/178.
However,
19 males
have pierced
ears
– don’t
count
them twice!
P(A or B) = (19 + 71 + 84)/178. So, P(A or B) = 174/178
The Practice of Statistics, 5th Edition
8
General Addition Rule for Two Events
We can’t use the addition rule for mutually exclusive events unless the
events have no outcomes in common.
General Addition Rule for Two Events
If A and B are any two events resulting from some chance
process, then
P(A or B) = P(A) + P(B) – P(A and B)
The Practice of Statistics, 5th Edition
9
Venn Diagrams and Probability
Because Venn diagrams have uses in other branches of mathematics,
some standard vocabulary and notation have been developed.
The complement AC contains exactly the outcomes that are not in A.
The events A and B are mutually exclusive (disjoint) because they do not
overlap. That is, they have no outcomes in common.
The Practice of Statistics, 5th Edition
10
Venn Diagrams and Probability
The intersection of events A and B (A ∩ B) is the set of all outcomes
in both events A and B.
The union of events A and B (A ∪ B) is the set of all outcomes in either
event A or B.
Hint: To keep the symbols straight, remember ∪ for union and ∩ for intersection.
The Practice of Statistics, 5th Edition
11
Venn Diagrams and Probability
Recall the example on gender and pierced ears. We can use a Venn
diagram to display the information and determine probabilities.
Define events A: is male and B: has pierced ears.
The Practice of Statistics, 5th Edition
12
Roulette An American roulette wheel has 38 slots with numbers 1 through 36, 0, and
00, as shown in the figure. Of the numbered slots, 18 are red, 18 are black, and 2–the
0 and 00–are green. When the wheel is spun, a metal ball is dropped onto the middle
of the wheel. If the wheel is balanced, the ball is equally likely to settle in any of the
numbered slots. Imagine spinning a fair wheel once. Define events B: ball lands in a
black slot, and E: ball lands in an even-numbered slot. (Treat 0 and 00 as even
numbers.)
•(a) Make a two-way table that displays the sample space in terms of events B and E.
The Practice of Statistics, 5th Edition
13
• (a) Make a two-way table that displays the sample space in terms of
events B and E.
• (b) Find P(B) and P(E).
• P(B) = 18/38= 0.474 and P(E) = 20/38 = 0.526
• (c) Describe the event “B and E” in words. Then find P(Band E).
• The ball lands in a spot that is black and even. P(B and E) = =
0.263.
• (d) Explain why P(B or E) ≠ P(B) + P(E). Then use the general
addition rule to compute P(B or E).
• If we add the probabilities of B and E, the spots that are black and
even will be double-counted. P(B or E) = = 0.737.
The Practice of Statistics, 5th Edition
14
Make the table into a Venn Diagram
The Practice of Statistics, 5th Edition
15
Probability Rules
Section Summary
In this section, we learned how to…
 DESCRIBE a probability model for a chance process.
 USE basic probability rules, including the complement rule and the
addition rule for mutually exclusive events.
 USE a two-way table or Venn diagram to MODEL a chance process
and CALCULATE probabilities involving two events.
 USE the general addition rule to CALCULATE probabilities.
The Practice of Statistics, 5th Edition
16