Download Circuit Of Math and Physics Questions Begin Here : 3x – 2y = 11

Circuit Of Math and Physics Questions
Begin Here :
3x – 2y = 11
Everyone:
4x – 3y = 13
Remember: Distance=rate*time
A bicyclist is riding .5km/min but it takes 6 minutes to oil the chain
before they can take off. You are running .2km/min. How long until the bike catches
you?
Outer 1: –2x – 4y = 2
6x – 6y = 48
Outer 2: A car goes 10 meters in 4 seconds at a constant velocity, then accelerates at 2m/s2 for 5 seconds. What is the final velocity of the car?
(hint: use the constant velocity as the initial velocity when the car accelerates use the following equations to solve the problem):
Vave=x/t
aave=V/t
Outer 3: x + z = 6
z - 3y = 7
2x + y + 2z = 11
Outer 4: If a runner does not start from rest and runs 100 meters in 10 seconds at a constant acceleration of 0.5m/s2. What was the initial and
final velocity of the runner?
Use these equations to solve the problem:
Vf=Vi+at
x=(1/2)*( Vi+Vf)*t
Outer 5: The equation for voltage gain (AV) in a typical noninverting, single-ended opamp circuit is as follows:
R1
AV =
+1
R2
Where,
R1 is the feedback resistor (connecting the output to the inverting input)
R2 is the other resistor (connecting the inverting input to ground)
Suppose we wished to change the voltage gain in the following circuit from 5 to 6.8, but only had the freedom to alter the resistance of R2:
Algebraically manipulate the gain equation to solve for R2, then determine the necessary value of R2 in this circuit to give it a voltage gain of 6.8.
Outer 6: A satellite with the mass of 1*103kg is orbiting the Earth which has a mass of 5.97*1024kg. The (x,y) coordinates of the satellite is
(2*108, 5*108)m where the center of the Earth is the origin. If the gravitational force is defined by
F=(6.67*10-11)*mass of Earth*mass of satellite/r2
where r is the distance between the Earth and the Satellite, what is the gravitational force between the Earth and the satellite? (hint: use the
Pythagorean theorem to solve for r)
Outer 7:
1
x=
157
y -
14
14
16x + 3y = -51
Outer 8: Electric Potential (V) is a way to measure the potential energy between charged objects. It is commonly calculated in Volts and is
mathematically defined as
V=(8.99*109)*q/r
where q is the charge of the object and r is the distance between two objects. If there are three charges objects (q1=3C, q2=2C, q3=1C) and the
distance between each object is equal to 100 meters, what would be the total Electric Potential of the three object system?
(hint: use Vtotal=V1+V2+V3)
Inner 1: Calculate all currents in this DC circuit:
Hint: it may help you to set up the necessary equation by labeling the current through the lower resistor as I and the current through the upper
resistor as I + 0.005.
Inner 2: If a box weighing 15N (or 1.53kg) is being pulled by a rope with an acceleration of 2m/s2. What would be the tension (force caused by
the rope) in the rope? Account for the kinetic friction force that opposes motion.
Use the following equations:
Kinetic friction force=0.2*(weight of the object in Newtons)
Net Force=m*a Newton’s Second Law
Net Force= Tension-kinetic friction force
Inner 3: 2x – y + z = 7
x + 2y + 2z = 3
7x – 3y – 3z = 4
Inner 4: Using the definition of average velocity (change of distance over time) and average acceleration (change in velocity over time)
Vave=x/t
aave=V/t
derive the following two equations:
Vf2=Vi2+2ax
and
x=Vit+(1/2)*a*t2
where Vf is the final velocity and Vi is the initial velocity.
Inner 5: Using the definition of average velocity (change of distance over time) and average acceleration (change in velocity over time)
Vave=x/t
aave=V/t
derive the following two equations:
Vf=Vi+at
where Vf is the final velocity and Vi is the initial velocity.
and
x=(1/2)*( Vi+Vf)*t
Final Question: Ball 1 with a mass of 3.0kg (m1) is stationary. Ball 2 with a lesser mass of 2.0kg strikes it going at an initial velocity (Vi2) of 5m/s.
Both balls go away from each other with a final velocity. What are their final velocities (Vf1 and Vf2)?
To solve use the equations of the conservation of momentum (m*V) and the conservation of kinetic energy (KE).
m1Vf1+m2Vf2= m1Vi1+m2Vi2
conservation of momentum
KEi=KEf conservation of kinetic energy (initial KE=finial KE)
KE=(1/2)mV2
definition of mechanical KE
Solutions to circuit questions.
Begin Here : (7, 5)
Everyone:
t= 10 min
d=2km
Final Question: (answer: Vf1=-1.0 m/s Vf2=4.0m/s)
Outer 1: (5, -3)
Outer 2: (answer: 12.5 m/s)
Outer 3: x = 2, y = -1 and z = 4
Outer 4: (Vi=7.5m/s and Vf=12.5m/s)
Outer 5:
R1
R2 =
AV − 1
For the circuit shown, R2 would have to be set equal to 810.3 Ω.
Outer 6: (answer: F=1.37N).
Outer 7: y=31 x= -9
Outer 8: (answer: V=539,400,000Volts or 5.394*108Volts)
Inner1: Upper resistor current = 8.5 mA; lower resistor current = 3.5 mA
Inner 2: (answer T=6.06N)
Inner 3: (1,-2, 3)
Inner 4: (answers can vary)
Inner 5: (answers can vary)
3x – 2y = 11
Key:
4x – 3y = 13
(7,5)
A car goes 10 meters in 4 seconds at a
constant velocity, then accelerates at 2m/s2
for 5 seconds. What is the final velocity of
the car? (hint: use the constant velocity as
the initial velocity when the car
accelerates)use the following equations to
solve the problem:Vave=x/t
aave=V/t
(answer: 12.5 m/s)
A 20.0m-long extension cord is made from
two #19 gauge copper wires. (One wire
carries current to an appliance, while the
other wire carries current from it.) What is
the resistance of each wire at 10.00 C? The
diameter of the#19 gauge wire is .912mm.
A=6.533x10
-7
R=.511Ώ
2x - y + 6z = 1
x-y+z=2
x+y+z=1
x = 21, y = -49/3 and z = -11/3
Remember: Distance=rate*time
A bicyclist is riding .5km/min but it takes 6
minutes to oil the chain before they can
take off. You are running .2km/min. How
long until the bike catches you?
t= 10 min
d=2km
Exploded cube:
Each student will roll the cube.
3x – 2y = 11
4x – 3y = 13
students will get together in groups
corresponding to the problem they
rolled and work together to
solve that problem. One student
will then share with the class how
they solved the problem.
A car goes 10 meters in 4 seconds at a
constant velocity, then accelerates at 2m/s2
for 5 seconds. What is the final velocity of
the car? (hint: use the constant velocity as
the initial velocity when the car
accelerates)use the following equations to
solve the problem:
Vave=x/t
A 20.0m-long extension cord is made from
two #19 gauge copper wires. (One wire
carries current to an appliance, while the
other wire carries current from it.) What is
the resistance of each wire at 10.00 C? The
diameter of the#19 gauge wire is .912mm.
2x - y + 6z = 1
x-y+z=2
x+y+z=1
aave=V/t
Remember: Distance=rate*time
A bicyclist is riding .5km/min but it takes 6
minutes to oil the chain before they can
take off. You are running .2km/min. How
long until the bike catches you?